Staff Selection Commission Combined Graduate Level Exam
Question : Select the most appropriate option to fill in the blank.
He is an honest man and his conduct is __________ suspicion.
Option 1: over
Option 2: below
Option 3: above
Option 4: against
Correct Answer: above
Solution : The correct choice is the third option.
The phrase above suspicion means that someone's behaviour is so honest and trustworthy that there is no reason to suspect them of any wrongdoing. It indicates a high level of integrity.
Therefore, the complete sentence is: He is
Question : The famous Kohinoor diamond was produced from one of the mines in
Option 1: Orissa
Option 2: Chhota Nagpur
Option 3: Bijapur
Option 4: Golconda
Correct Answer: Golconda
Solution : Correct Answer is Golconda
Kohinoor is one of the largest cuts in the world, weighing 105.6 carats. The diamond may have been extracted from the Kollur mine, a four-meter (13-foot)-long sequence, in the 13th century in Golconda, India (currently Andhra Pradesh). Following Punjab's defeat, British
Question : A piece of wire, when bent to form a circle, will have a radius of 84 cm. If the wire is bent to form a square, the length of one side of the square is:
Option 1: 152 cm
Option 2: 132 cm
Option 3: 168 cm
Option 4: 225 cm
Correct Answer: 132 cm
Solution : Given: A piece of wire, when bent to form a circle, will have a radius of 84 cm. Length of the wire = circumference of the circle = $2\pi r$ ⇒ $2×\frac{22}{7}×84=528$ So, the perimeter of the square = 528 cm ⇒ One side
Question : If $\tan(5x-10^{\circ})=\cot(5y+20^{\circ})$, the value of $(x+y)$ is:
Option 1: $15^{\circ}$
Option 2: $16^{\circ}$
Option 3: $24^{\circ}$
Option 4: $20^{\circ}$
Correct Answer: $16^{\circ}$
Solution : Given: $\tan(5x-10^{\circ})=\cot(5y+20^{\circ})$ ⇒ $\tan(5x-10^{\circ})=\tan(90^{\circ}-(5y+20^{\circ}))$ ⇒ $5x-10^{\circ}=90^{\circ}-5y-20^{\circ}$ ⇒ $5x+5y=80^{\circ}$ ⇒ $x+y=16^{\circ}$ Hence, the correct answer is $16^{\circ}$.
Question : The site of birth [nativity] of Gautam Buddha is marked by :
Option 1: a monastery
Option 2: a "Rummindel Pillar" Ashok Maurya
Option 3: a statue
Option 4: a Peepal tree
Correct Answer: a "Rummindel Pillar" Ashok Maurya
Solution : The Correct Answer is a "Rummindel Pillar" Ashok Maurya
The Sacred Garden, which spans 9 square kilometers, is identified in the Ashoka Pillar's inscription as the location of the Enlightened One's birth. The Lumbini Pillar Edict, also known as the Rummindei
Question : Which of the following is a tree found in mountain vegetation?
Option 1: Sundari
Option 2: Keekar
Option 3: Chir
Option 4: Teak
Correct Answer: Chir
Solution : The correct answer is Chir.
"Chir" is a tree that is typically found in mountain vegetation. It is a species of pine tree that is commonly found in hilly and mountainous regions of India and surrounding areas. It is known for its needle-like leaves,
Question : Due to inclement weather, an aeroplane reduced its speed by 300 km/h and reached its destination of 1200 km late by 2 hours. Then, the scheduled duration of the flight was:
Option 1: 1 hour
Option 2: 1.5 hours
Option 3: 2 hours
Option 4: 2.5 hours
Correct Answer: 2 hours
Solution : Let the original speed of the aeroplane be $x$ km/h. According to the question, $\frac{1200}{x–300} – \frac{1200}{x} = 2$ ⇒ $\frac{1200}{x–300} – \frac{1200}{x} = 2$ ⇒ $1200(\frac{x–x+300}{x(x–300)}) = 2$ ⇒ $1200(\frac{300}{x(x–300)}) = 2$ ⇒ $x(x–300) = 600(300)$ ⇒ $x(x–300) = 600(600–300)$ ⇒ $x =
Question : The table given below shows the number of salesmen in five companies.
What is the average number of salesmen in C2, C4, and C5?
Option 1: 5
Option 2: 10
Option 3: 15
Option 4: 20
Correct Answer: 10
Solution : Number of salesman in C2 = 10 Number of salesman in C4 = 5 Number of salesman in C5 = 15 Now, The average number of the salesman in C2, C4 and C5 = $\frac{\text{Total number of salesman in C2, C4 and C5}}{3}$ = $\frac{10+5+15}{3}$
Question : If $x^{2}+y^{2}+6x+5=4(x-y)$, then $(x-y)$ is:
Option 1: $1$
Option 2: $0$
Option 3: $–1$
Option 4: $4$
Correct Answer: $1$
Solution : Given: $x^{2}+y^{2}+6x+5=4(x-y)$ ⇒ $x^{2}+y^{2}+6x+5-4x+4y=0$ ⇒ $x^{2}+y^{2}+2x+5+4y=0$ ⇒ $x^{2}+2x+1+y^{2}+4y+4=0$ ⇒ $x^{2}+2×x×1+1+y^{2}+2×y×2+4=0$ ⇒ $(x+1)^{2}+(y+2)^{2}=0$ ⇒ $x$ = – 1 and $y$ = – 2 [If the sum of two square terms is zero, then each term will also be zero] So, $(x-y) = (–1–( –2))=1$ Hence, the
Question : Directions: In the following question, some parts of the sentence may have some errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No error".
Ramesh smiled when he was remembering (1) / his hard early years (2) / and his long road to success. (3) / No error (4)
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (1)
Solution : The error lies in the first part of the sentence.
When we want to talk about our memories, it is common to use the simple past tense i.e., remembered instead of the past continuous tense i.e., was remembering.
Therefore, the correct sentence is: "Ramesh smiled
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