Staff Selection Commission Combined Graduate Level Exam
Question : Directions: From the given option figures, select the one in which the question figure is embedded.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : As there is no restriction on the rotation of the figure, we will check all possible angles where the question figure can fit itself in the given option figures. The question figure is embedded only in the second option figure.
Hence, the second option is correct.
Question : If $x+\frac{1}{x}=1$, then the value of $x^{12}+x^9+x^6+x^3+1$ is:
Option 1: 1
Option 2: - 1
Option 3: 0
Option 4: - 2
Correct Answer: 1
Solution : We have to find the value of $x^{12} + x^9 + x^6 + x^3 + 1$ Given, $x + \frac{1}{x} = 1$ $x^2 + 1 = x$ ⇒ $x^2 - x + 1 = 0$ ⇒ $x^3+1^3=(x + 1)(x^2 - x + 1) $ ⇒
Question : A supply of juice lasts for 35 days. If its use is increased by 40%, the number of days the same amount of juice would last is:
Option 1: 25 days
Option 2: 30 days
Option 3: 24 days
Option 4: 27 days
Correct Answer: 25 days
Solution : Let the original use of the juice be 100 units. Now, after the increase of 40%, the use becomes (100 + 100 × $\frac{40}{100}$) = 140 units So, 140 units of juice will be required for 35 days ⇒ 100 units of juice will
Question : If $x^{2} + \frac{1}{x^{2}} = 18$ and $x > 0$, what is the value of $x^{3} + \frac{1}{x^{3}}?$
Option 1: $36 \sqrt{5}$
Option 2: $40 \sqrt{5}$
Option 3: $46 \sqrt{5}$
Option 4: $34 \sqrt{5}$
Correct Answer: $34 \sqrt{5}$
Solution : $x^{2} + \frac{1}{x^{2}} = 18$ ⇒ $x^{2} + \frac{1}{x^{2}} + 2 = 18+2$ ⇒ $(x + \frac{1}{x})^{2} = 20$ ⇒ $(x + \frac{1}{x}) = \sqrt{20}$ Now, $(x + \frac{1}{x})^{3}=x^3+\frac{1}{x^3}+3 × x × \frac{1}{x} × (x + \frac{1}{x})$ ⇒ $(\sqrt{20})^3=x^3+\frac{1}{x^3}+3×\sqrt{20}$ ⇒ $x^3+\frac{1}{x^3}=20\sqrt{20} - 3\sqrt{20}$ ⇒
Question : Direction: Which of the following diagrams represents the correct relationship between Herbivores, Tigers, and Animals?
Solution : Tigers are animals and they are carnivores, not herbivores.
But, herbivores are also animals. So, both the circles come inside the circle of animals.
Based on the above conclusions, the following Venn diagram will be formed:
Hence, the first option is correct.
Question : The Competition (Amendment) Bill, 2022 proposes to reduce the timeline for the CCI to pass an order on transactions from 210 days to _______ days.
Option 1: 140
Option 2: 180
Option 3: 150
Option 4: 190
Correct Answer: 150
Solution : The correct answer is 150.
The proposed Competition (Amendment) Bill of 2022 recommends shortening the duration within which the Competition Commission of India (CCI) is required to issue an order on transactions, reducing it from 210 days to 150 days. More specifically, the bill
Question : Directions: In the following question, find the odd number pair from the given alternatives.
Option 1: 24
Option 2: 49
Option 3: 64
Option 4: 81
Correct Answer: 24
Solution : Let's check the options — First option: 24→24 is not a perfect square. Second option: 49→49 = 72 Third option: 64→64 = 82 Fourth option: 81→81 = 92
So, the first option is the odd one as all the other three options
Question : Directions: Which two signs and two numbers should be interchanged in the following equation to make it correct? 264 + 24 × 9 ÷ 60 – 4 = 630
Option 1: 264 and 9; ÷ and −
Option 2: 264 and 9; + and –
Option 3: 4 and 24; ÷ and +
Option 4: 4 and 9; − and ×
Correct Answer: 4 and 24; ÷ and +
Solution : Given: 264 + 24 × 9 ÷ 60 – 4 = 630
Replace the given signs and numbers in the equation one by one with the original signs in the given equation. First option: 264 and 9; ÷ and −
Question : Given below are four jumbled sentences. Select the option that gives their correct order, forming a meaningful and coherent paragraph.
A. Gopu was not allowed into the main temple shrine. B. But Gopu did not mind his work. C. Pandit Ji had given him a little room in the courtyard of the temple, and this was the only place he could call his own. D. He would sit every evening outside the temple to look after the shoes and slippers
Option 1: DACB
Option 2: CBDA
Option 3: ADBC
Option 4: ABCD
Correct Answer: ADBC
Solution : The third option is correct.
Question : Directions: The graph shows the result of 10th class students of school for 4 years. Study the graph and answer the question:
III class
II class
I class
The percentage increase in first class in the year 2003 over the year 2002 is approximately:
Option 1: 12%
Option 2: 0%
Option 3: 10%
Option 4: 10%
Correct Answer: 0%
Solution : $$\text{Percentage Change =}\frac{\text{No. of Student in year 2003 - No. of Student in year 20002}}{\text{ No. of Student in year 2002}}\times100$$
$\text{Here , both Steep of graph for first class in the year 2003 over the year 2002 is same. So Numerator for above Formula
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