Staff Selection Commission Combined Graduate Level Exam
Question : PSW stands for
Option 1: Program status word
Option 2: Processor ststus word
Option 3: Process status word
Option 4: Primitive status word
Correct Answer: Program status word
Solution : The Correct Answer is- Program status word
The register for the program status word (PSW) has 8 bits. The flag register is another name for it. Program Status Word is referred to as PSW. It is a control register for the IBM System/360
Question : Who was the reformer of oppressed and backward classes?
Option 1: Dayanand Saraswati
Option 2: Raja Ram Mohan Roy
Option 3: Dr. B. R. Ambedkar
Option 4: Mahatma Gandhi
Correct Answer: Dr. B. R. Ambedkar
Solution : The correct answer is Dr. B. R. Ambedkar.
Dr. B. R. Ambedkar is known as the Father of the Indian Constitution. Belonging to a depressed community himself, Ambedkar was a reformer who stood against the social evil of casteism. He formed Bahishkrit
Question : Which of the following is used to protect objects in a computer system in the absence of more complete protection schemes?
Option 1: Digital certificate
Option 2: Digital signature
Option 3: Passwords
Option 4: Tokens
Correct Answer: Passwords
Solution : The correct answer is Passwords.
In the absence of more comprehensive protection measures, passwords are employed to secure items on a computer system. Passwords are a type of authentication in which users must input a secret code to get access to a computer system or
Question : Direction: The bar shows the number of accidents in a city during the first six months of a year. Examine the bar chart and answer the following question.
The percentage of decrease in the number of accidents from May to June is:
Option 1: $15\frac{4}{7}$%
Option 2: $22\frac{3}{7}$%
Option 3: $22\frac{6}{7}$%
Option 4: $18\frac{5}{7}$%
Correct Answer: $22\frac{6}{7}$%
Solution : Number of accidents in May = 35 Number of accidents in June = 27 The decrease in the number of accidents = 35 – 27 = 8 Required percentage = $\frac{\text{The decrease in the number of accidents}}{\text{The number of accidents occurred in May}}\times 100=\frac{8}{35}\times 100
Question : The distance between the centres of two circles having radii 22 cm and 18 cm, is 32 cm. The length (in cm) of the direct common tangent of the two circles is:
Option 1: $2 \sqrt{252} \mathrm{~cm}$
Option 2: $2 \sqrt{152} \mathrm{~cm}$
Option 3: $3 \sqrt{242} \mathrm{~cm}$
Option 4: $3 \sqrt{252} \mathrm{~cm}$
Correct Answer: $2 \sqrt{252} \mathrm{~cm}$
Solution : Given: The distance between the centres of two circles having radii 22 cm and 18 cm, is 32 cm. Let the radius of the bigger circle ($r_1$) = 22 cm And the radius of the smaller circle ($r_2$) = 18 cm Distance between
Question : The value of $\frac{(0.67 \:\times\: 0.67 \:\times\: 0.67)\:-\:(0.33 \:\times\: 0.33 \:\times\: 0.33)}{(0.67 \:\times\: 0.67)\:+\:(0.67 \:\times\: 0.33)\:+\: (0.33 \:\times\: 0.33)}$ is:
Option 1: 11
Option 2: 1.1
Option 3: 3.4
Option 4: 0.34
Correct Answer: 0.34
Solution : $\frac{(0.67 \:\times\: 0.67 \:\times\: 0.67)\:-\:(0.33 \:\times\: 0.33 \:\times\: 0.33)}{(0.67 \:\times\: 0.67)\:+\:(0.67 \:\times\: 0.33)\:+\: (0.33 \:\times\: 0.33)}$ = $\frac{(0.67^{3}\:-\:0.33^{3})}{0.67^{2}\:+\:(0.67 \:\times\: 0.33)\:+\:0.33^{2}}$ = $\frac{(0.67\:-\:0.33)({0.67^{2}\:+\:(0.67 \:\times\: 0.33)\:+\:0.33^{2}})}{0.67^{2}\:+\:(0.67 \:\times\: 0.33) \:+\: 0.33^{2}}$ = $0.67 - 0.33$ = $0.34$ Hence, the correct answer is 0.34.
Question : Select the most appropriate passive form of the given sentence.
Please do not pluck any flowers from the temple compound
Option 1: You are requested not to pluck any flowers from the temple compound
Option 2: No flowers can be plucked from the temple compound
Option 3: How can any flowers be plucked from the temple compound?
Option 4: Let any flowers not to be plucked from the temple compound.
Correct Answer: You are requested not to pluck any flowers from the temple compound
Solution : The first option is correct.
Question : 9435 is added to 7593, then 2607 is subtracted from the sum. The result is divisible by:
Option 1: 4
Option 2: 10
Option 3: 3
Option 4: 5
Correct Answer: 3
Solution : Resultant number = 7593 + 9435 – 2607 = 14421 Divisibility check: ⇒ Since the unit digit is not 0, it is not divisible by 10. ⇒ Since the last two digits, 21, is not divisible by 4, it is also not divisible by 4.
Question : Directions: In the following question, out of the four alternatives, select the alternative that will improve the bracketed part of the sentence. In case no improvement is needed, select "No Improvement".
(If) the sky is overcast, I take my umbrella with me.
(1) When
(2) Unless
(3) Whenever
(4) No Improvement
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (3)
Solution : The sentence can be improved using the third option.
It replaces if with whenever indicating a repeated or habitual action in response to the condition of the overcast sky. This choice provides a clearer sense of the speaker's consistent behaviour.
Question : Directions: Which of the following numbers will replace the question mark (?) in the given series? 1, 4, 27, 16, 125, ?
Option 1: 216
Option 2: 36
Option 3: 343
Option 4: 49
Correct Answer: 36
Solution : Given: 1, 4, 27, 16, 125, ?
In the above-given series – (1)3 = 1; (2)2 = 4; (3)3 = 27; (4)2 = 16; (5)3 = 125 According to the above pattern, the next number will be – (6)2
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