Staff Selection Commission Combined Graduate Level Exam
Question : What is the value of $\frac{3}{2} \div \frac{1}{7} \times[(\frac{1}{2} - \frac{1}{3}) \div \frac{1}{42}]?$
Option 1: $72 \frac{1}{3}$
Option 2: $73 \frac{1}{2}$
Option 3: $72 \frac{1}{2}$
Option 4: $71 \frac{2}{3}$
Correct Answer: $73 \frac{1}{2}$
Solution : Given: $\frac{3}{2} \div \frac{1}{7} \times[(\frac{1}{2} - \frac{1}{3}) \div \frac{1}{42}]$ Applying the BODMAS rule, $=\frac{3}{2} \div \frac{1}{7} \times[(\frac{3-2}{6}) \div \frac{1}{42}]$ $=\frac{3}{2} \div \frac{1}{7} \times[\frac{1}{6} \div \frac{1}{42}]$ $=\frac{3}{2} \div \frac{1}{7} \times[\frac{1}{6} \times{42}]$ $=\frac{3}{2} \div \frac{1}{7} \times7$ $=\frac{21}{2}\times 7$ $=\frac{147}{2}$ $=73\frac{1}{2}$ Hence, the correct answer is $73\frac{1}{2}$.
Question : Directions: In the following question, you have to identify the correct response from the given premises stated according to the following symbols. If P means +, Q means ×, R means ÷ and S means –, then what is the value of 44 Q 9 R 12 S 6 Q 4 P 16 = ?
Option 1: 25
Option 2: 36
Option 3: 112
Option 4: 12
Correct Answer: 25
Solution : Given: P means +, Q means ×, R means ÷ and S means –. 44 Q 9 R 12 S 6 Q 4 P 16 = ?
On replacing the symbols according to the instructions given, the equation becomes – = 44 × 9 ÷
Question : Directions: In the following question, some parts of the sentence may have errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No Error."
The patient (1) / was accompanied (2) / with his friend. (3) / No Error (4)
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (3)
Solution : The error lies in the third part of the sentence.
The preposition "with" should be replaced with the preposition "by", as it is used in passive structure, followed by a noun or noun phrase. "Accompanied by" is used to refer to people, while
Question : Select the option that expresses the given sentence in reported speech. She said to her mother, “May I have another slice of cake?”
Option 1: She asked her mother that may I have another slice of cake.
Option 2: She asked her mother that may she have another slice of cake.
Option 3: She asked her mother if she might have another slice of cake.
Option 4: She asked her mother if she may have another slice of cake
Correct Answer: She asked her mother if she might have another slice of cake.
Solution : The correct choice will be the third option.
The steps of conversion are as follows:
Question : Which of the following statements is true?
Option 1: $1 \frac{1}{2} + 17 \frac{3}{4} - 5 \frac{1}{5} - 2 \frac{1}{10} = \frac{239}{20}$
Option 2: $\frac{9}{1078}>\frac{11}{1127} >\frac{12}{1219}$
Option 3: $\frac{149}{151} > \frac{153}{155} > \frac{157}{159}$
Option 4: None
Correct Answer: $1 \frac{1}{2} + 17 \frac{3}{4} - 5 \frac{1}{5} - 2 \frac{1}{10} = \frac{239}{20}$
Solution : 1. $1 \frac{1}{2} + 17 \frac{3}{4} - 5 \frac{1}{5} - 2 \frac{1}{10} = \frac{239}{20}$ $\frac{3}{2} + \frac{71}{4} - \frac{26}{5} - \frac{21}{10} = \frac{239}{20}$ Simplifying the left side, we get: $\frac{239}{20} = \frac{239}{20}$ This
Question : Points $P$ and $Q$ lie on sides $AB$ and $AC$ of triangle $ABC$, respectively, such that segment $PQ$ is parallel to side $BC$. If the ratio of areas of triangle $APQ$ to triangle $ABC$ is 25 : 36, then the ratio of $AP$ to $PB$ is:
Option 1: $5:6$
Option 2: $1:5$
Option 3: $6:5$
Option 4: $5:1$
Correct Answer: $5:1$
Solution : We have: $\frac{\text{area of } \Delta APQ}{\text{area of }\Delta ABC}=\frac{25}{36}$ Two triangles $APQ$ and $ABC$ such that $△APQ ∼△ABC$ $⇒\frac{\text{area of }\Delta APQ}{\text{area of }\Delta ABC}=(\frac{AP}{AB})^2$ $⇒\frac{25}{36}=(\frac{AP}{AB})^2$ $⇒\frac{5}{6}=(\frac{AP}{AB})$ If $AB$ = 6 units and $AP$ = 5 units, then $PB = AB - AP$ =
Question : The compound interest on Rs. 30000 at 7% per annum for $n$ years is Rs. 4347. The value of $n$ is:
Option 1: $3$ years
Option 2: $2$ years
Option 3: $4$ years
Option 4: $5$ years
Correct Answer: $2$ years
Solution : Given: Principal, $P$ = Rs. 30000 Rate, $R$ = 7% per annum Let time be $n$ years. Compound interest, CI = Rs. 4347 Formula: Amount = $P(1+\frac{R}{100})^{n}$ Solution: Amount = $P + C.I = 30000 + 3437 = 34347$ $34347 = 30000(1+\frac{7}{100})^{n}$ $(\frac{107}{100})^{n}=\frac{34347}{30000}=\frac{11449}{10000}$ ⇒
Question : Direction: If WATER is written as YCVGT, then what is written as HKTG?
Option 1: REFI
Option 2: ERIF
Option 3: IRFE
Option 4: FIRE
Correct Answer: FIRE
Solution : WATER → YCVGT
Similarly, HKTG →
Therefore, HKTG can be written as
Question : Directions: Select the related letter cluster from the given alternatives. DCBA : WXYZ :: IJKL : ?
Option 1: SRQP
Option 2: QPON
Option 3: RQPO
Option 4: PONM
Correct Answer: RQPO
Solution : Given: DCBA : WXYZ :: IJKL : ?
Like, DCBA : WXYZ→(DW, CX, BY, AZ) are opposite pairs. Similarly, for IJKL : (?)→(IR, JQ, KP, LO) are opposite pairs.
Thus, IJKL is related to RQPO. Hence, the third option is correct.
Question : Directions: Select the figure from among the given options that can replace the question mark (?) in the following series.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : According to the given figure series – The geometrical figures follow a certain pattern for movement inside the box. The pattern is as follows – 1. Parallelogram = Top left→Centre→Bottom left→Bottom right→Top left 2. Triangle = Bottom left→Bottom right→Top left→Centre→Bottom left 3. Shaded circle = Bottom
The Question containing Inaapropriate or Abusive Words
Question lacks the basic details making it difficult to answer
Topic Tagged to the Question are not relevant to Question
Question drives traffic to external sites for promotional or commercial purposes
The Question is not relevant to User
And never miss an important update
