Staff Selection Commission Combined Graduate Level Exam
Question : If two circles of radii 18 cm and 8 cm touch externally, then the length of a direct common tangent is:
Option 1: 24 cm
Option 2: 14 cm
Option 3: 16 cm
Option 4: 12 cm
Correct Answer: 24 cm
Solution : Let $r{_1}$ and $r{_2}$ be the radii of the two circles, and let $d$ be the distance between their centres. In this case: $d=r{_1}+r{_2}$ Given that the radii are 18 cm and 8 cm, we have: $d=18+8=26$ cm Now, the direct common tangent is
Question : Relative humidity is expressed as
Option 1: grams
Option 2: Kilograms
Option 3: Percentage
Option 4: Ratio
Correct Answer: Percentage
Solution : The correct option is Percentage.
The amount of moisture in the air as compared to the greatest amount that the air may contain at a particular temperature is known as relative humidity, which is stated as a percentage. A relative humidity of 50%, for instance,
Question : A girl purchases 9 mangoes for Rs. 90 and sells 10 mangoes for Rs. 95. Find the gain or loss percentage.
Option 1: 2.5% loss
Option 2: 5% loss
Option 3: 2.5% gain
Option 4: 5% gain
Correct Answer: 5% loss
Solution : Given, A girl purchases 9 mangoes for Rs. 90 and sells 10 mangoes for Rs. 95. ⇒ Cost Price of each mango = $\frac{90}{9} =\text{Rs. }10$ And Selling Price of each mango = $\frac{95}{10} = \text{Rs. }9.5$ Loss percentage = $\frac{10-9.5}{10}\times 100 = 5\%$
Question : If $\tan A = n\tan B$ and $\sin A=m \sin B$, then the value of $\cos^{2}A$ is:
Option 1: $\frac{m^{2}-1}{n^{2}+1}$
Option 2: $\frac{m^{2}+1}{n^{2}-1}$
Option 3: $\frac{m^{2}+1}{n^{2}+1}$
Option 4: $\frac{m^{2}-1}{n^{2}-1}$
Correct Answer: $\frac{m^{2}-1}{n^{2}-1}$
Solution : $\sin A = m\sin B$--------------(i) $\tan A = n\tan B$ $\frac{\sin A}{\cos A}$ = $n\frac{\sin B}{\cos B}$------------------(ii) Substituting $\sin B$ from equation (i), ⇒ $\cos B$ = $\frac{n}{m}$$\cos A$----------(iii) Squaring both sides of equation (i), ⇒ $\sin^{2} A$ = $m^{2}\sin^{2}B$ ⇒ 1–$\cos^{2} A$ = $m^{2}(1–\cos^{2}
Question : The price of a shirt after a 15% discount is Rs. 119. What was the marked price of the shirt before the discount?
Option 1: Rs. 129
Option 2: Rs. 150
Option 3: Rs. 140
Option 4: Rs. 160
Correct Answer: Rs. 140
Solution : Let the marked price of the shirt be Rs. $x$. Price after 15% discount $= x - 0.15x = 0.85x$ So, $0.85x = 119$ $\therefore x = 140$ Hence, the correct answer is Rs. 140.
Question : Gelena is a mineral of
Option 1: Iron
Option 2: Gold
Option 3: Lead
Option 4: Calcium
Correct Answer: Lead
Solution : The correct option is - Lead.
Gelena, commonly known as galena, is a mineral composed primarily of lead sulfide (PbS). It is one of the most important ores of lead and is widely distributed throughout the world.
Question : Select the most appropriate option to fill in the blank.
We _______ off old clothes and bought new ones for Diwali.
Option 1: cost
Option 2: coast
Option 3: caste
Option 4: cast
Correct Answer: cast
Solution : The correct option to fill in the blank is the fourth option.
The word cast in this context means getting rid of or disposing of old clothes. Cast off is the correct phrasal verb to use when indicating the act of discarding something.
Therefore, the
Question : If the length of each of two equal sides of an isosceles triangle is 10 cm and the adjacent angle is $45^{\circ}$, then the area of the triangle is:
Option 1: $20\sqrt{2}$ sq. cm
Option 2: $12\sqrt{2}$ sq. cm
Option 3: $25\sqrt{2}$ sq. cm
Option 4: $15\sqrt{2}$ sq. cm
Correct Answer: $25\sqrt{2}$ sq. cm
Solution : $AD = AB \sin 45^\circ$ $= 10\times\frac{1}{\sqrt2}$ $= 5\sqrt2$ cm $\therefore$ Area of $\triangle ABC = \frac{1}{2}\times BC \times AD$ $=\frac{1}{2}\times 10 \times 5\sqrt2$ $= 25\sqrt2$ sq. cm Hence, the correct answer is $25\sqrt2$ sq. cm.
Question : A Sphygmomanometer measures the blood pressure in the
Option 1: Veins
Option 2: Arteries
Option 3: Eyes
Option 4: Synovial
Correct Answer: Arteries
Solution : The correct option is Arteries.
A sphygmomanometer is a medical instrument used to determine blood pressure. Blood pressure refers to the force applied by the blood on the walls of arteries while flowing through them. This device comprises an inflatable cuff that is put
Question : S and T are points on the sides PQ and PR, respectively, of $\triangle$PQR such that PS × PR = PQ × PT. If $\angle$Q = 96° and $\angle$PST = $\angle$PRQ + 34°, then $\angle$QPR = ?
Option 1: 24°
Option 2: 25°
Option 3: 22°
Option 4: 26°
Correct Answer: 22°
Solution : According to the question, PS × PR = PQ × PT ⇒ $\frac{PQ}{PS}$ = $\frac{PR}{PT}$ ⇒ ST || QR $\angle$ Q = $\angle$ PST = 96° (corresponding angles between two parallel lines) Since $\angle$ PST = $\angle$ PRQ + 34° ⇒ 96° = $\angle$ PRQ
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