Staff Selection Commission Combined Graduate Level Exam
Question : Census in India was first started under______ in the year 1872.
Option 1: Lord Lawrence
Option 2: Lord Canning
Option 3: Lord Cornwallis
Option 4: Lord Mayo
Correct Answer: Lord Mayo
Solution : The correct option is Lord Mayo.
The 1872 census in India was the first comprehensive census conducted in the country during British colonial rule. It was conducted under the administration of Lord Mayo, the Viceroy at that time. The main objective of this census
Question :
Where did Aurangzeb die ?
Option 1: Pune
Option 2: Aurangabad
Option 3: Ahmed Nagar
Option 4: Mumbai
Correct Answer: Ahmed Nagar
Solution : The correct option is Ahmed Nagar.
Aurangzeb, India's sixth Mughal emperor, died at the age of 88 on March 3, 1707. He died in Ahmednagar Fort, in the city of Ahmednagar, Maharashtra, India. Aurangzeb was born in 1618 and assassinated in 1658. He reigned
Question : Directions: Select the figure that will come next in the following figure series.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : In the given figure, follow the directions to find the next term –
From box 1 to box 2, @ is shifted from the top left corner to the bottom right corner, # is shifted from left-centre to the top right corner, & is shifted from
Question : A shopkeeper offers the following three schemes. Scheme I: Two successive discounts of 15% and 25% Scheme II: Buy 5, get 3 free Scheme III: Buy 4, get 6 Which scheme is the best for customers?
Option 1: Scheme I
Option 2: Scheme III
Option 3: Scheme II
Option 4: All are equal
Correct Answer: Scheme II
Solution : Scheme I: Two successive discounts of 15% and 25% Final discount = 15 + 25 – $\frac{15\times25}{100}$ = 36.25% Scheme II: Buy 5, get 3 free Customers will get a total of 8 items at the price of 5 items. So, discount = $\frac{3}{8}\times100$
Question : Directions: Select the correct combination of mathematical signs to sequentially replace the * signs and balance the given equation. 11 * 3 * 11 * 2 * 9 = 10
Option 1: ×, ÷, −, +
Option 2: ÷, ×, −, +
Option 3: ÷, +, −, ×
Option 4: ×, ÷, +, −
Correct Answer: ×, ÷, −, +
Solution : Given: 11 * 3 * 11 * 2 * 9 = 10
Replace * with the mathematical signs and solve the equation one by one using the BODMAS rule.
Let's check the given options – First option: ×, ÷, −, + ⇒
Question : Select the most appropriate option to improve the underlined segment in the given sentence. If there is no need to improve it, select 'No improvement'.
I cannot recollect where did I leave my umbrella.
Option 1: I did leave
Option 2: I left
Option 3: No improvement
Option 4: I have leave
Correct Answer: I left
Solution : The second option is the correct choice.
The sentence is structured as an indirect question within a main clause (I cannot recollect). When reporting a past action in an indirect question, the word order follows that of a declarative sentence, which is subject +
Question : Name a single letter, which can be prefixed to the following words in order to obtain entirely new words?
TILL TABLE PILE TAB PRING
Option 1: C
Option 2: S
Option 3: B
Option 4: H
Correct Answer: S
Solution : Given: TILL TABLE PILE TAB PRING
Here,
If we add S in all the words, then,
- STILL: It describes an object that is not moving or audibly creating noise. - STABLE: It designates a solid, steady object. - SPILE: A little, pointed object used
Question : Direction: 7, 2 = 59 ; 5, 3 = 28 ; 9, 1 = 810 ; 2, 1 = 13 ; 5, 4 = ?
Option 1: 19
Option 2: 9
Option 3: 20
Option 4: 239
Correct Answer: 19
Solution : Given:
7, 2 = 59 ; 5, 3 = 28; 9, 1 = 810 ; 2, 1 = 13;
The given series adheres to the following pattern:
7, 2 = 59 →(7 – 2) × 10 + (7 + 2) × 1 = 59
5,
Question : If $ab=21$ and $\frac{(a+b)^{2}}{(a-b)^{2}}=\frac{25}{4}$, then the value of $a^{2}+b^{2}+3ab$ is:
Option 1: 115
Option 2: 121
Option 3: 125
Option 4: 127
Correct Answer: 121
Solution : $\frac{(a+b)^{2}}{(a-b)^{2}}=\frac{25}{4}$ Taking root on both sides, ⇒ $\frac{(a+b)}{(a-b)}=\frac{5}{2}$ Cross Multiplying both sides: ⇒ $(2a+2b)=(5a-5b)$ ⇒ $3a=7b$ ⇒ $a=\frac{7}{3}b$ Given: $ab=21$ ⇒ $\frac{7}{3}b\times b=21$ ⇒ $\frac{7}{3}b^{2}=21$ ⇒ $b^{2}=\frac{21\times 3}{7}$ ⇒ $b^{2}=9$ Now putting the value in $a^{2}+b^{2}+3ab$ $=\frac{49}{9}b^{2}+9+3\times 21$ $=\frac{49}{9}\times 9+9+3\times 21$ $=49+9+63$ $=121$ Hence, the
Question : Which of the following is called the 'shrimp capital of India'?
Option 1: Mangalore
Option 2: Nagapatanam
Option 3: Kochi
Option 4: Nellore
Correct Answer: Nellore
Solution : The correct answer is Nellore.
Nellore district in Andhra Pradesh is called 'shrimp capital of India' because of its extensive shrimp production and export. Nellore is famous for cultured shrimp farming. According to International Trade Centre data, until 2021 India has been the largest exporter
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