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Staff Selection Commission Combined Graduate Level Exam

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Question : In which state is the festival of Gudi Padwa specially celebrated?

Option 1: Maharashtra

Option 2: Punjab

Option 3: Goa

Option 4: Odisha

Team Careers360 15th Jan, 2024

Correct Answer: Maharashtra


Solution : The correct option is Maharashtra.

The Indian state of Maharashtra is where most people celebrate the traditional Hindu festival of Gudi Padwa. It usually falls on the first day of the Hindu month of Chaitra, equivalent to March or April in the Gregorian calendar,

34 Views

Question : If the area of the base of a cone is increased by 100%, the volume increases by:

Option 1: $200\%$

Option 2: $182\%$

Option 3: $141\%$

Option 4: $100\%$

Team Careers360 20th Jan, 2024

Correct Answer: $100\%$


Solution : The volume $(V)$ of a cone,
$V = \frac{1}{3} \pi r^2 h$
The area of the base $=\pi r^2$
After $100\%$ increase in the area of the new base $=2\pi r^2$
The new volume $(V')$ of the cone,
$V' = \frac{1}{3} (2\pi r^2) h =

39 Views

Question : Directions: Select the option that represents the correct order of the given words as they would appear in an English dictionary.
1. Significant
2. Sinful
3. Signed
4. Singing
5. Simplify

Option 1: 3, 1, 5, 2, 4

Option 2: 3, 5, 1, 2, 4

Option 3: 3, 2, 1, 5, 4

Option 4: 3, 1, 2, 5, 4

Team Careers360 11th Jan, 2024

Correct Answer: 3, 1, 5, 2, 4


Solution : Given:
1. Significant 2. Sinful 3. Signed 4. Singing 5. Simplify

Step 1: Compare the first two letters of each word. Since both the words start with the same letter and i, then move on to the next letter.

75 Views

Question : P, Q, and R can complete a piece of work in 9, 12, and 18 days, respectively. Working together, how much work can they complete in one day?

Option 1: $\frac{2}{3}$

Option 2: $\frac{1}{2}$

Option 3: $\frac{1}{3}$

Option 4: $\frac{1}{4}$

Team Careers360 11th Jan, 2024

Correct Answer: $\frac{1}{4}$


Solution : One day work of P $= \frac{1}{9}$
One day work of Q $= \frac{1}{12}$
One day work of R $= \frac{1}{18}$
Work done by all the three in a day
$= \frac{1}{9}+\frac{1}{12}+\frac{1}{18}$
$= \frac{4+3+2}{36}$
$= \frac{9}{36} = \frac{1}{4}$
Hence, the correct answer is $\frac{1}{4}$.

19 Views

Question : Directions: By Interchanging the given two numbers which of the following equations will be not correct?
9 and 6

Option 1: 7 + 6 × 4 ÷ 9 – 8 = 5

Option 2: 6 × 8 – 9 ÷ 3 + 5 = 75

Option 3: 9 × 7 + 4 ÷ 1 – 6 = 38

Option 4:  7 × 6 ÷ 3 + 9 – 8 = 19

Team Careers360 9th Jan, 2024

Correct Answer: 9 × 7 + 4 ÷ 1 – 6 = 38


Solution : Given:
9 and 6

Replace the given numbers in the options one by one with the original numbers in the given equation.
First option: 7 + 6 × 4 ÷ 9 – 8 = 5

15 Views

Question : A number, when divided by 6, leaves a remainder of 3. When the square of the same number is divided by 6, the remainder is:

Option 1: 0

Option 2: 2

Option 3: 1

Option 4: 3

Team Careers360 16th Jan, 2024

Correct Answer: 3


Solution : Let the number be $x$.
Dividend = Quotient × Divisor + Remainder
When divided by 6, $x$ leaves a remainder of 3.
Let the quotient be $q$.
Then, $x=6q+3$
Now, squaring both sides we get,
$x^2=(6q+3)^2$
⇒ $x^2=36q^2+36q+9$
⇒ $x^2=6(6q^2+6q+1)+3$
Thus, $x^2$ divided by 6

4 Views

Question : Which of the following cities did not host matches of the FIFA U-17 Women’s World Cup 2022 in India?

Option 1: New Delhi

Option 2: Navi Mumbai

Option 3: Goa

Option 4: Bhubaneswar

Team Careers360 7th Jan, 2024

Correct Answer: New Delhi


Solution : The correct answer is New Delhi.

Three venues hosted the 32 football matches of the FIFA U-17 Women's World Cup 2022. The Pandit Jawaharlal Nehru Stadium in Margao, Goa; the DY Patil Stadium in Navi Mumbai, Maharashtra. It happened in Navi Mumbai.

On

14 Views

Question : If $p+q+r=pqr=\frac{1}{p}+\frac{1}{q}+\frac{1}{r}=1$, find $\mathrm{p}^3+\mathrm{q}^3+\mathrm{r}^3$.

Option 1: 1

Option 2: –1

Option 3: 5

Option 4: –5

Team Careers360 10th Jan, 2024

Correct Answer: 1


Solution : Given:
$p+q+r=pqr=\frac{1}{p}+\frac{1}{q}+\frac{1}{r}=1$
$\frac{1}{p}+\frac{1}{q}+\frac{1}{r}=1$
⇒ $\frac{qr+pr+pq}{pqr}=1$
⇒ $pr+qr+pq=pqr$
⇒ $pr+qr+pq=1$
Now, $(p+q+r)^2=1^2$
⇒ $p^2+q^2+r^2+2(pq+pr+qr)=1$
⇒ $p^2+q^2+r^2+2=1$
$\therefore p^2+q^2+r^2=-1$
$p^3+q^3+r^3$
$=(p+q+r)(p^2+q^2+r^2-pq-pr-qr)+3pqr$
$=(p+q+r)[p^2+q^2+r^2-(pq+pr+qr)]+3pqr$
$=1×[-1-1]+3×1$
$=-2+3$
$=1$
Hence, the correct answer is 1.

23 Views

Question : Calculate the mean from the following table.

Scores Frequencies
0-10 2
10-20 4
20-30 12
30-40 21
40-50 6
50-60 3
60-70 2

 

Option 1: 34.2

Option 2: 33.4

Option 3: 32.6

Option 4: 35.8

Team Careers360 24th Jan, 2024

Correct Answer: 33.4


Solution :

Scores Frequencies Mid Point Mid Point × Frequencies
0-10 2 5 10
10-20 4 15 60
20-30 12 25 300
30-40 21 35 735
40-50 6 45 270
50-60 3 55 165
60-70 2 65 130

 Mean = $\frac{\sum \text{ (Mid Point × Frequencies)}}{\sum \text{Frequencies}}$

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