Correct Answer: 2

Solution : According to the question,
$\frac{1}{x+\frac{1}{y+\frac{2}{z+\frac{1}{4}}}}=\frac{29}{79}$
⇒ $x+\frac{1}{y+\frac{2}{z+\frac{1}{4}}} = \frac{79}{29}$
⇒ $x+\frac{1}{y+\frac{2}{z+\frac{1}{4}}} = 2+\frac{21}{29}$
Comparing both sides, we get $x=2$,
and $\frac{1}{y+\frac{2}{z+\frac{1}{4}}} =\frac{21}{29}$
⇒ $\frac{1}{y+\frac{2}{z+\frac{1}{4}}}={\frac{1}{1+\frac{8}{21}}}$
⇒ $\frac{1}{y+\frac{2}{z+\frac{1}{4}}}={\frac{1}{1+\frac{2}{5+\frac{1}{4}}}}$
Comparing both sides, we get,
$y= 1$ and $z= 5$
$\therefore$ $(2 x+3 y-z)= 2 × 2 + 3

Correct Answer: Nitrogen

Solution : The correct option is Nitrogen.

Nitrogen is the most abundant element in the atmosphere (78%). This is inert, essential for life, a component of the nitrogen cycle, a diatomic gas that maintains atmospheric pressure and is employed in agriculture and industry.

Correct Answer: January

Solution : The correct option is January.

The Australian Open is a major tennis tournament held annually in Melbourne, Australia. In 2022, the tournament dates were from January 17 to January 30. The Australian Open is one of the four Grand Slam tournaments in tennis, along

Correct Answer: A and B only

Solution : The correct option is A and B only.

The subjects that are not included in any of the three lists (Union List, State List, and Concurrent List) are called residual subjects. These subjects fall under the residuary powers of the Union

Correct Answer: chemically unreactive

Solution : The correct option is chemically unreactive.

Inert gases, known as noble gases, exhibit chemical inertness due to their stable electron configurations. Their electron shells are filled, making it highly improbable for these gases to engage in chemical reactions with other elements.

Correct Answer: 13

Solution : Given:
Principal = Rs. 9500
Time = 10 years
Formula Used:
SI=$\frac{\text{PRT}}{100}$
Calculation:
Let the rate of Interest be R.
SI = $\frac{9500 \times 10 \times R}{100}$
Now we know the interest received is 130% of 9500 = $\frac{130 \times 9500}{100}$
$\therefore \frac{9500 \times 10

Correct Answer: 196

Solution : The area of a circle,
$ \text{Area} = \pi r^2$ where $r$ is the radius of the circle.
Given that the area of the circle is 38.5 cm².
$⇒ r = \sqrt{\frac{\text{Area}}{\pi}} = \sqrt{\frac{38.5}{\pi}} = 3.5$ cm
The side length of square LMNO

Correct Answer: 90,000

Solution : We have,
A = Rs. 119790, r = 10%, and t = 3 years.
$A = P \left(1 + \frac{r}{100}\right)^{t}$
Substituting the given values into the formula, we get
$⇒119790 = P \left(1+\frac{10}{100}\right)^{1×3}$
$⇒119790 = P \left(1+0.1\right)^{3}$
$⇒119790 = P \left(1.1\right)^{3}$
$⇒P=\frac{119790}{1.331}=Rs. 90,000$
Hence, the

Correct Answer: damaged

Solution : The first option is correct.

Explanation: In this context, the word that best fits the grammatical structure and conveys the negative impact of industrial pollution on the ecosystem is damaged. The sentence describes the harmful effects of industrial pollution on rivers like the Ganga

Correct Answer: 10 m/s

Solution : Given: A bus travels 720 kilometres in 20 hours.
Applying the formula of $\text{Speed}=\frac{\text{Distance}}{\text{Time}}$, we get,
$\text{Speed}=\frac{720}{20}=36$ km/hr
Converting km/hr into m/s by multiplying it with $\frac{5}{18}$, we get,
$\text{Speed}=36\times\frac{5}{18}=10$ m/s
Hence, the correct answer is 10 m/s.