Staff Selection Commission Combined Graduate Level Exam
Question : In India, the Temperate Forest Research Centre is in which city?
Option 1: Shimla
Option 2: Ranchi
Option 3: Dehradun
Option 4: Srinagar
Correct Answer: Shimla
Solution : The answer is Shimla.
Shimla, Himachal Pradesh, is home to the Temperate Forest Research Centre. Its goals include temperate forest regeneration, cold desert afforestation, forest conservation, and ecological restoration in the Himalayan area.
Question : In the first 10 overs of a cricket game, the run rate was only 3.2. The run rate in the remaining 40 overs to reach the target of 282 runs is:
Option 1: 6.4
Option 2: 6.3
Option 3: 6.25
Option 4: 6.5
Correct Answer: 6.25
Solution : The run rate for the first 10 overs = 3.2 Total runs scored in 10 overs = 3.2 × 10 = 32 Total runs to be scored = 282 Runs left to be scored in 40 overs = 282 – 32 = 250 The run
Question : Directions: Which two signs should be interchanged to make the given equation correct? 108 ÷ 2 × 10 + 70 – 10 = 480
Option 1: + and –
Option 2: ÷ and ×
Option 3: + and ×
Option 4: ÷ and –
Correct Answer: + and –
Solution : Given: 108 ÷ 2 × 10 + 70 – 10 = 480
Replace the given symbols in the options one by one with the original symbols in the given equation. First option: + and – = 108 ÷ 2 × 10 – 70
Question : The pie chart given shows the number of males in 6 departments. The number of males in a particular department is shown in terms of degrees concerning the total number of males in all 6 departments. The number of males in department S is 1080. J = Total number of males in T and P K = Difference between the number of males in P and Q What is the value of J + K?
Option 1: 3600
Option 2: 4800
Option 3: 2400
Option 4: 1200
Correct Answer: 3600
Solution : Given: The number of males in the S department = 1080. ⇒ $54^{\circ}=1080$ ⇒ $1^{\circ}=20$ The number of males in the T department is $90^{\circ}$. = 90 × 20 = 1800 The number of males in the P department is $30^{\circ}$. = 30 × 20
Question : Directions: In the following question, select the odd letter pair from the given alternatives.
Option 1: KQ
Option 2: DJ
Option 3: SZ
Option 4: RX
Correct Answer: SZ
Solution : Let's check the options – First option: KQ; K + 6 = Q Second option: DJ; D + 6 = J Third option: SZ; S + 7 = Z Fourth option: RX; R + 6 = X
So, the third option is different from the
Question : Directions: In a certain code language, if EAR is written as 2037 and PBU is written as 23418, how will DIG be written in the same code language?
Option 1: 9116
Option 2: 7106
Option 3: 4108
Option 4: 8114
Correct Answer: 9116
Solution : Given: EAR is coded as 2037 and PBU is coded as 23418.
Add 2 to the place value of EAR and shuffle their position as shown to get the required code – E + 2→7; A + 2→3; R + 2→20 Shuffle the positions to
Question : What will be the atomic number of element X that is placed in period 2 and group 17?
Option 1: 8
Option 2: 7
Option 3: 10
Option 4: 9
Correct Answer: 9
Solution : The correct answer is 9.
The atomic number of an element corresponds to the count of protons in its nucleus, while its position on the periodic table is defined by its period (row) and group (column). In Group 17, there are typically 7 electrons
Question : Directions: Three different positions of the same dice are shown. Find the number on the face opposite the face showing 3.
Option 1: 2
Option 2: 1
Option 3: 4
Option 4: 6
Correct Answer: 4
Solution : According to the dice rule, if two or three positions of the same dice are given with two common faces but in different orientations then out of those two common faces the faces that are not common are opposite to each other. While considering Figures
Question : Trinitrotoluene is
Option 1: Used to melt metals
Option 2: Used to fuse two metals
Option 3: Used as an abrasive
Option 4: Used as an explosive
Correct Answer: Used as an explosive
Solution : The correct answer is Used as an explosive.
Trinitrotoluene (TNT) is a type of explosive. It is a highly explosive chemical that has found widespread use in military, industrial, and mining applications. The presence of three nitro groups (-NO2) connected
Question : Three Science classes A, B, and C take a Life Science test. The average score for class A is 83. The average score for class B is 76. The average score in class C is 85. The average score of classes A and B is 79, and the average score of classes B and C is 81. Then the average score of classes A, B, and C is:
Option 1: 81.5
Option 2: 81
Option 3: 80.5
Option 4: 80
Correct Answer: 81.5
Solution : The average score of classes A, B, and C are 83, 76, and 85 respectively. The average score of class A and class B = 79 The average score of class B and class C = 81 Let the number of students in classes A,
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