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Staff Selection Commission Combined Graduate Level Exam

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14 Views

Question : If $(x-5)^2+(y-2)^2+(z-9)^2=0$, then value of $(x+y-z)$ is:

Option 1: 16

Option 2: –1

Option 3: –2

Option 4: 12

Team Careers360 21st Jan, 2024

Correct Answer: –2


Solution : Given:
$(x-5)^2+(y-2)^2+(z-9)^2=0$
So, $x=5, y=2, z=9$
Therefore, $x+y-z = (5+2-9) = -2$
Hence, the correct answer is –2.

18 Views

Question : Directions: In a certain code language, BELOVED is coded as 65, and FLOWER is coded as 79. How will QUIVER be coded in that language?

Option 1: 92

Option 2: 94

Option 3: 91

Option 4: 90

Team Careers360 23rd Jan, 2024

Correct Answer: 92


Solution : Given:
BELOVED is coded as 65, and FLOWER is coded as 79.

Add the place values of the letters of BELOVED and FLOWER to get their required codes.
BELOVED; B→2; E→5; L→12; O→15; V→22; E→5; D→4
Add the pace values→2 + 5 + 12 +

17 Views

Question : Which of the following is not a nitrogenous fertiliser?

Option 1: Ammonium sulphate

Option 2: Urea

Option 3: Ammonium Thiosulphate

Option 4: Superphosphate

Team Careers360 25th Jan, 2024

Correct Answer: Superphosphate


Solution : The correct option is Superphosphate.

The term "superphosphate" does not refer to nitrogenous fertiliser. It is a sort of phosphate fertiliser that gives plants phosphorous but no nitrogen. Nitrogenous fertilisers, on the other hand, such as Urea, and Ammonium sulphate, include nitrogen as a

35 Views

Question : The marked price of a piano was Rs. 15,000. At the time of sale, there were successive discounts of 20%, 10%, and 10% respectively on it. The sale price was:

Option 1: Rs. 9,720

Option 2: Rs. 9,750

Option 3: Rs. 9,760

Option 4: Rs. 9,780

Team Careers360 25th Jan, 2024

Correct Answer: Rs. 9,720


Solution : Single discount of 20% and 10% = $20 + 10 - \frac{20\times 10}{100} = 28\%$
Now single discount of 20%, 10%, and 10% = $28 + 10 - \frac{28\times 10}{100} = 35.2\%$
SP of the piano = $15000×\frac{100\:–\:35.2}{100}$ = Rs. 9,720
Hence, the correct

22 Views

Question : Directions: Which of the following interchanges of numbers and mathematical signs would make the given equation correct?
729 × 81 ÷ 20 + 16 − 6 = 50

Option 1: 6 and 20, × and ÷

Option 2: 20 and 50, + and −

Option 3: 16 and 50, × and +

Option 4: 16 and 20, + and ÷

Team Careers360 23rd Jan, 2024

Correct Answer: 6 and 20, × and ÷


Solution : Given:
729 × 81 ÷ 20 + 16 − 6 = 50

Let's check the given options –
First option: 6 and 20, × and ÷
On interchanging the signs and numbers, we get –
⇒ 729 ÷ 81 ×

30 Views

Question : Find the value of the following expression.
$12\left(\sin^4 \theta+\cos^4 \theta\right)+18\left(\sin^6 \theta+\cos^6 \theta\right)+78 \sin^2 \theta \cos^2 \theta$

Option 1: 30

Option 2: 40

Option 3: 10

Option 4: 20

Team Careers360 25th Jan, 2024

Correct Answer: 30


Solution : $12(\sin^4 \theta+\cos^4 \theta)+18(\sin^6 \theta+\cos^6 \theta)+78 \sin^2 \theta \cos^2 \theta$
$=12[(\sin^2 \theta+\cos^2\theta)^2-2\sin^2 \theta \cos^2 \theta]+18[(\sin^2 \theta+\cos^2 \theta)^3-3\sin^2 \theta \cos^2 \theta(\sin^2 \theta+\cos^2\theta)]+78 \sin^2 \theta \cos^2 \theta$
$=12[1-2\sin^2 \theta \cos^2 \theta]+18[1-3\sin^2 \theta \cos^2 \theta]+78 \sin^2 \theta \cos^2 \theta$
$= 12-24\sin^2 \theta \cos^2 \theta+18-54\sin^2 \theta \cos^2 \theta+78 \sin^2 \theta

15 Views

Question : The Revolutionary Socialist Party was established in _______.

Option 1: 1936

Option 2: 1925

Option 3: 1940

Option 4: 1929

Team Careers360 24th Jan, 2024

Correct Answer: 1940


Solution : The correct answer is 1940.

The Revolutionary Socialist Party was established in 1940. It had its roots in the Bengali liberation movement and the Hindustan Socialist Republican Army. Tridib Chaudhuri was the founder of this party.

12 Views

Question : Value of $\sec^2\theta-\frac{\sin^2\theta-2\sin^4\theta}{2\cos^4\theta-\cos^2\theta}$ is:

Option 1: 1

Option 2: 2

Option 3: –1

Option 4: 0

Team Careers360 25th Jan, 2024

Correct Answer: 1


Solution : $\sec^2\theta-\frac{\sin^2\theta-2\sin^4\theta}{2\cos^4\theta-\cos^2\theta}$
$=\sec^2\theta-\frac{\sin^2\theta(1-2\sin^2\theta)}{\cos^2\theta(2\cos^2\theta-1)}$
$=\sec^2\theta-\frac{\sin^2\theta(1-2\sin^2\theta)}{\cos^2\theta[2(1-\sin^2\theta)-1]}$
$=\sec^2\theta-\frac{\sin^2\theta(1-2\sin^2\theta)}{\cos^2\theta(1-2\sin^2\theta)}$
$=\sec^2\theta-\tan^2\theta$
$=1$
Hence, the correct answer is 1.

6 Views

Question : A, B, and C can do a job working alone in 6, 9, and 18 days, respectively. They all worked together for one day, and then A and B quit. How many days does C working alone take to complete the remainder of the job?

Option 1: 9

Option 2: 6

Option 3: 12

Option 4: 10

Team Careers360 21st Jan, 2024

Correct Answer: 12


Solution : Given: A, B, and C can do a job working alone in 6, 9, and 18 days, respectively.
One day's work for A = $\frac{1}{6}$
B's one day's work = $\frac{1}{9}$
C's one day's work = $\frac{1}{18}$
Let for $x$ days, C worked alone.
A

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