Staff Selection Commission Combined Graduate Level Exam
Question : Direction: Some equation are solved on the basis of certain pattern find the correct answer for the unsolved equation on that basis.
8 x 7 x 6 = 765
5 x 3 x 2 = 421
9 x 6 x 4 = ?
Option 1: 583
Option 2: 853
Option 3: 841
Option 4: 481
Correct Answer: 853
Solution : Here, in the given equations, each number is reduced by 1 and placed at hundreds, tens and units place respectively.
⇒ 8 x 7 x 6 = 765
⇒ 5 x 3 x 2 = 421
Similarily, 9 x 6 x 4 = 853
Hence,
Question : The number of students in a class is 45, out of which $33 \frac{1}{3} \%$ are boys and the rest are girls. The average score of girls in Science is $66 \frac{2}{3} \%$ more than that of boys. If the average score of all the students is 78, then the average score of girls is:
Option 1: 78
Option 2: 54
Option 3: 90
Option 4: 65
Correct Answer: 90
Solution : Let the average score of boys as B and the average score of girls as G. Given that $33 \frac{1}{3} \%$ of the students are boys. The number of boys = 45 × $\frac{1}{3}$ = 15 The number of girls = 45 – 15 =
Question :
Direction: In the following question, select the related word from the given alternatives.
Garbage : House :: Gangue : ?
Option 1: Ore
Option 2: Drugs
Option 3: Factory
Option 4: Office
Correct Answer: Ore
Solution : Given:
The relationship appears to be that garbage is typically found or associated with a house.
Now, let's apply the same logic to the second part of the analogy:
Gangue is a term used in mining to
Question : A and B can complete a task together in 18 hours. After 6 hours, A leaves. B takes 36 hours to finish the rest of the task. How many hours would it have taken A to do the task if he worked alone?
Option 1: 54
Option 2: 45
Option 3: 21
Option 4: 27
Correct Answer: 27
Solution : (A + B) can do $\frac{1}{18}$th of the task in 1 hour. In 6 hours that A and B worked together, they did $\frac{6}{18}=\frac{1}{3}$rd of the task. What remained after that was $\frac{2}{3}$rd which was done by B alone, in 36 hours. So, in 36
Question : The secretariat of the convention on Biological Diversity Campaign was based in
Option 1: London
Option 2: Italy
Option 3: Montreal
Option 4: Toronto
Correct Answer: Montreal
Solution : The correct option is Montreal.
the Secretariat of the Convention on Biological Diversity (CBD) was based in Montreal, Canada. The Convention on Biological Diversity (CBD) is an international treaty that aims to conserve biodiversity and promote sustainable use of biological resources.
Question : Select the option that can be used as a one-word substitute for the given group of words. Formal forgiveness of a person’s sins.
Option 1: Ablutions
Option 2: Absolution
Option 3: Absolutism
Option 4: Forgiveness
Correct Answer: Absolution
Solution : The correct option is the second option.
Explanation: Absolution refers to the formal forgiveness granted by a religious authority for a person's sins. It is often part of religious rituals like confession in Christianity. The meanings of the other options are as follows:
Question : Directions: In the question, a part of the sentence is in bold. Below are given alternatives to the bold part at 1, 2 and 3 that may improve the sentence. Choose the correct alternative. In case no improvement is needed, your answer is (4).
I can't allow you to make jokes in the class.
(1) cut
(2) crack
(3) break
(4) No Improvement
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
Correct Answer: 2
Solution : In the original sentence, the verb "make" is used, meaning to create or produce jokes. However, a more suitable verb is "crack," which means to tell or share jokes.
Therefore, the sentence should read, "I can't allow you to crack jokes in the class."
Question : If $x=a\cos\theta + b\sin\theta$ and $y=b\cos\theta-a\sin\theta$, then $x^{2}+y^{2}$ is equal to:
Option 1: $ab$
Option 2: $a^2+b^2$
Option 3: $a^2-b^2$
Option 4: $1$
Correct Answer: $a^2+b^2$
Solution : Given: $x=a\cos\theta + b\sin\theta$ and $y=b\cos\theta-a\sin\theta$ To find: $x^{2}+y^{2}$ Putting the value of $x$ and $y$, we get $(a\cos\theta+b\sin\theta)^{2}+(b\cos\theta-a\sin\theta)^{2}$ $(a^2\cos^2\theta+b^2\sin^2\theta+2×a\cos\theta×b\sin\theta)+(b^2\cos^2\theta+a^2\sin^2\theta-2×b\cos\theta×a\sin\theta)$ $=a^2\cos^2\theta + b^2\sin^2\theta+b^2\cos^2\theta+a^2\sin^2\theta$ $=a^2(\cos^2\theta+sin^2\theta)+b^2(sin^2\theta+\cos^2\theta)$ We know that, $(sin^2\theta+\cos^2\theta)=1$ Thus, $a^2(1)+b^2(1)$= $a^2+b^2$ Hence, the correct answer is $a^2+b^2$.
Question : Directions: Which of the following letters will replace the question mark (?) and complete the following letter series? Q, O, M, K, I, G, ?
Option 1: D
Option 2: F
Option 3: G
Option 4: E
Correct Answer: E
Solution : Given: Q, O, M, K, I, G, ?
Subtract 2 to the place value of each letter to get the next letter of the series. Q – 2 = O; O – 2 = M; M – 2 = K; K – 2 = I;
Question : A man has three sons, two daughters and a wife. They divided a sum of Rs. 19000 among themselves such that each daughter got 1.5 times the amount received by each son and his wife received Rs. 600 less than each son. What is the total amount (in Rs.) received by the three sons together?
Option 1: 2800
Option 2: 3600
Option 3: 5600
Option 4: 8400
Correct Answer: 8400
Solution : Let the amount received by each son be Rs. $x$. The amount received by each daughter = 1.5$x$ The amount received by wife = $x$ – 600 Total amount = Rs. 19000 According to the question, $3x + 2(1.5x) + x- 600 = 19000$ ⇒$
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