Staff Selection Commission Combined Graduate Level Exam
Question : Directions: Sonal's brother's paternal grandmother, named Seeta, is coming to Sonal's party with her only son. How is Seeta's son related to Sonal?
Option 1: Father
Option 2: Paternal grandfather
Option 3: Son
Option 4: Brother
Correct Answer: Father
Solution : According to the given information, the family tree will be –
Here, the quadrilateral represents the male, and the circular figure represents the female in the figure.
So, from the above, it can be said that Seeta's son is the father of Sonal. Hence, the
Question : Directions: Select the option that is related to the third word in the same way as the second word is related to the first word. (The words must be considered meaningful English words and must not be related to each other based on the number of letters/number of consonants/vowels in the word.) Bee : Beehive :: Dog : ?
Option 1: Kennel
Option 2: Stable
Option 3: Pen
Option 4: Shed
Correct Answer: Kennel
Solution : Given: Bee : Beehive :: Dog : ?
Like, Bee lives in the beehive. Similarly, the place where the dog lives is a kennel.
Hence, the first option is correct.
Question : Bhimbetka, a noted site of the Palaeolithic period, is located in which state of India?
Option 1: Bihar
Option 2: Uttar Pradesh
Option 3: Rajasthan
Option 4: Madhya Pradesh
Correct Answer: Madhya Pradesh
Solution : The correct answer is Madhya Pradesh.
Bhimbetka, a noted site of the Paleolithic, is located in Madhya Pradesh. It is just 45 kilometres away from the Capital city of Madhya Pradesh, Bhopal. It is famous for cave paintings from around 8000 B.C. This
Question : The value of $\frac{1}{4}+\frac{\left[(20.35)^2-(8.35)^2\right] \times 0.0175}{(1.05)^2+(1.05)(27.65)}$ is:
Option 1: $\frac{9}{20}$
Option 2: $\frac{7}{20}$
Option 3: $\frac{3}{20}$
Option 4: $\frac{3}{10}$
Correct Answer: $\frac{9}{20}$
Solution : $\frac{1}{4}+\frac{\left[(20.35)^2-(8.35)^2\right] \times 0.0175}{(1.05)^2+(1.05)(27.65)}$ $=\frac{1}{4}+\frac{\left[(20.35+8.35)(20.35-8.35)\right] \times 0.0175}{(1.05)[1.05+27.65]}$ $=\frac{1}{4}+\frac{\left[(12)(28.70)\right] \times 0.0175}{(1.05)[28.70]}$ $=\frac{1}{4}+\frac{12 \times 0.0175}{(1.05)}$ $=\frac{1}{4}+\frac{1}{5}$ $=\frac{9}{20}$ Hence, the correct answer is $\frac{9}{20}$.
Question : _________became the first swimmer from India to breach the Olympic Qualification Time (A cut) in swimming as he capped the qualification period with an outstanding performance in the Sette Colli Trophy in Rome, Italy in June 2021.
Option 1: Sajan Prakash
Option 2: Srihari Nataraj
Option 3: Anand Anilkumar Shylaja
Option 4: Virdhawal Khade
Correct Answer: Sajan Prakash
Solution : The correct option is Sajan Prakash.
Indian swimmer Sajan Prakash excels in the freestyle, butterfly, and medley events. When he set an Indian national record of 1:56.38 in the 200 m butterfly event at the 2021 Sette Colli Trophy in Rome, he became the
Question : Directions: Select the option that is related to the fifth number in the same way as the second number is related to the first number and the fourth number is related to the third number. 6 : 125 :: 2 : 1 :: 5 : ?
Option 1: 81
Option 2: 64
Option 3: 68
Option 4: 72
Correct Answer: 64
Solution : Given: 6 : 125 :: 2 : 1 :: 5 : ?
Like, 6 : 125→(6 – 1)3 = (5)3 = 125 2 : 1→(2 – 1)3 = (1)3 = 1 Similarly, for 5 : ?→(5 – 1)3 = (4)
Question : Directions: By Interchanging the given two numbers which of the following equations will be correct? 8 and 2
Option 1: 7 ÷ 2 – 8 × 4 + 1 = 0
Option 2: 2 × 4 – 8 + 5 ÷ 1 = 50
Option 3: 8 × 4 + 6 – 2 ÷ 1 = 6
Option 4: 8 × 4 – 9 ÷ 3 + 2 = 35
Correct Answer: 8 × 4 + 6 – 2 ÷ 1 = 6
Solution : Let's check the options –
First option: 7 ÷ 2 – 8 × 4 + 1 = 0 After replacing the digits the equation becomes – →7 ÷ 8 – 2 × 4 + 1
Question : Directions: Three statements are given followed by three conclusions numbered I, II, and III. Assuming the statements to be true, even if they seem to be at variance with commonly known facts, decide which of the conclusions logically follow(s) from the statements. Statements: Some colors are rainbows. Some paints are rainbows. All rainbows are drawings. Conclusions: I. Some drawings are colors. II. All paints are drawings. III. Some drawings are rainbows.
Option 1: Only conclusions I and II follow
Option 2: Only conclusions I and III follow
Option 3: Only conclusions II and III follow
Option 4: All conclusions follow
Correct Answer: Only conclusions I and III follow
Solution : The possible Venn diagram according to the given statements is as follows –
Let's analyse the conclusion – Conclusion I: Some drawings are colors – From the above diagram, it can be seen that the circle of drawings and colors
Question : Directions: Three of the following letter clusters are alike in some manner and hence form a group. Which letter cluster does not belong to that group?
Option 1: CGB
Option 2: FYI
Option 3: RKU
Option 4: KDN
Correct Answer: CGB
Solution : Let's check the options – First option: CGB; C + 4 = G; G – 5 = B Second option: FYI; F – 7 = Y; Y + 10 = I Third option: RKU; R – 7 = K; K + 10 = U Fourth
Question : Directions: Select the figure from the options that can replace the question mark (?) and complete the given pattern.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : On comparing the question figure and all the answer figures, the following figure will combine and make the complete pattern –
Hence, the second option is correct.
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