Staff Selection Commission Combined Graduate Level Exam
Question : Directions: In the following question, identify the correct response from the given premises stated according to the following symbols. If × denotes added to, + denotes subtracted from, – denotes multiplied by, then, 14 × 12 – 16 + 18 = ?
Option 1: 430
Option 2: 180
Option 3: 168
Option 4: 188
Correct Answer: 188
Solution : Given: 14 × 12 – 16 + 18 = ?
On replacing the symbols as per the given information, the equation becomes – = 14 + 12 × 16 – 18 = 14 + 192 – 18 = 206 – 18 = 188
So, 188
Question : Select the most appropriate synonym of the underlined word.
Bullying is a rather unacknowledged social evil.
Option 1: Unidentified
Option 2: Notable
Option 3: Infamous
Option 4: Named
Correct Answer: Unidentified
Solution : The correct choice is the first option.
Explanation:
We have to look for a synonym that conveys a lack of acknowledgement or recognition. Unacknowledged means not recognised or not acknowledged. Among the options, unidentified is the closest synonym that implies a lack of acknowledgement
Question : "Modernisation" as a goal of planning in the context of the Indian economy was not aimed at:
Option 1: Adopting a Western lifestyle
Option 2: Change in social outlook
Option 3: Increase in the production of goods and services
Option 4: Use of new technology
Correct Answer: Adopting a Western lifestyle
Solution : The correct answer is Adopting a Western lifestyle.
"Modernisation" as a goal of planning in the context of the Indian economy was not aimed at adopting a Western lifestyle. Industrialisation, technological advancement, economic expansion, and social development were among the goals
Question : If $7\sin^{2}\theta+3\cos^{2}\theta=4$, and $0^{\circ}< \theta< 90^{\circ}$, then the value of $\tan\theta$ is:
Option 1: $\frac{1}{\sqrt{2}}$
Option 2: $\frac{1}{\sqrt{3}}$
Option 3: $\sqrt{\frac{3}{2}}$
Option 4: $1$
Correct Answer: $\frac{1}{\sqrt{3}}$
Solution : We know that $\sin^{2}\theta + \cos^{2}\theta = 1$ $7\sin^{2}\theta+3\cos^{2}\theta=4$ ⇒ $7\sin^{2}\theta+3(1-\sin^{2}\theta)=4$ ⇒ $4\sin^{2}\theta=1$ ⇒ $\sin\theta = \sqrt{\frac{1}{4}}$ or $\sin\theta = -\sqrt{\frac{1}{4}}$ Since $0^{\circ}< \theta< 90^{\circ}$, $\sin\theta$ is positive. ⇒ $\sin\theta = \frac{1}{2}$ ⇒ $\theta = 30^{\circ}$ ⇒ $\tan\theta = \tan30^{\circ} = \frac{1}{\sqrt{3}}$ Hence, the correct
Question : At 129 m away from the foot of a cliff on level ground, the angle of elevation of the top of the cliff is 30°. The height of this cliff is:
Option 1: $50\sqrt{3}$ m
Option 2: $45\sqrt{3}$ m
Option 3: $43\sqrt{3}$ m
Option 4: $47\sqrt{3}$ m
Correct Answer: $43\sqrt{3}$ m
Solution : Let h be the height of the cliff. From the figure we get, $\tan 30°=\frac{h}{129}$ ⇒ $\frac{1}{\sqrt{3}}=\frac{h}{129}$ ⇒ $h=\frac{129}{\sqrt{3}}$ $\therefore h=43\sqrt{3}$ m Hence, the correct answer is $43\sqrt{3}$ m.
Question : Solve the following to find its value in terms of trigonometric ratios. $(\sin A + \cos A)(1 - \sin A \cos A)$
Option 1: $\sin^3A+\cos^3A$
Option 2: $\sin^2A-\cos^2A$
Option 3: ${[\cos A-\sin A]\left[\sin ^2 A+\cos ^2 A\right]}$
Option 4: $\sin^3A-\cos^3A$
Correct Answer: $\sin^3A+\cos^3A$
Solution : Given expression, $(\sin A + \cos A)(1 – \sin A \cos A)$ $\sin A+\cos A−\sin^2A\cos A-\sin A\cos^2A$ We know, $\sin^2A=1−\cos^2A$ and $\cos^2A=1−\sin^2A$ Now, $\sin A+\cos A−\sin^2A\cos A−\sin A\cos^2A$ = $\sin A+\cos A−(1−\cos^2A)\cos A−\sin A(1−\sin^2A)$ = $\sin A+\cos A−\cos A+\cos^3A−\sin A+\sin^3A$ = $\sin^3A+\cos^3A$ Hence, the correct
Question : Directions: How many triangles are there in the given figure?
Option 1: 28
Option 2: 36
Option 3: 40
Option 4: 48
Correct Answer: 36
Solution : The figure can be labeled as shown below –
There are a total of 36 triangles in the above figure. They are AEI, IEB, BJF, CJF, DKG, CKG, HAL, DHL, AEB, BFC, CGD, DHA, AML, LMD, DMK, KMC, CMJ, JMB, BMI, IMA, AMD, DMC, CMB,
Question : A loan is to be returned in two equal yearly instalments. If the rate of interest is 10% p.a. compounded annually and each instalment is INR 5,808, then 60% of the total interest (nearest to INR) charged in this scheme is:
Option 1: 917
Option 2: 911
Option 3: 922
Option 4: 913
Correct Answer: 922
Solution : Let the loan amount be P. Then using P = $\frac{\text{A}}{(1 +\frac{\text{R}}{100})^T}$, where A is amount due at R% rate of interest for $T$ years ⇒ P = $\frac{5808}{(1+\frac{10}{100})}$ + $\frac{5808}{(1+\frac{10}{100})^{2}}$ = $\frac{5808}{\frac{11}{10}}$ + $\frac{5808}{\frac{121}{100}}$ = $\frac{58080}{11}$ + $\frac{580800}{121}$ = 5280 + 4800 = 10080
Question : Which of the following pairs is correct?
I. Summer Olympics 2020-Tokyo
II. Summer Olympics 2016- Rio de Janeiro
III. Summer Olympics 2012-London
Option 1: Only I and II
Option 2: Only I and III
Option 3: Only II and III
Option 4: All are correct
Correct Answer: All are correct
Solution : The correct answer is All are correct.
For the first time, the Olympics happened in 1896 in Athens, Greece.
The locations of some of the recent Olympic events are:
Question : The curved surface area of a solid hemisphere is 22 cm2. What is the total surface area of the hemisphere? (use $\pi=\frac{22}{7}$)
Option 1: 66 cm2
Option 2: 44 cm2
Option 3: 33 cm2
Option 4: 30 cm2
Correct Answer: 33 cm2
Solution : Given: The curved surface area of a solid hemisphere is 22 cm2. The curved surface area of the hemisphere = $2\pi r^2$ The total surface area of the hemisphere = $3\pi r^2$ where $r$ is the radius. According to the question,
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