Staff Selection Commission Combined Graduate Level Exam
Question : Directions: How many triangles are there in the given figure?
Option 1: 28
Option 2: 36
Option 3: 40
Option 4: 48
Correct Answer: 36
Solution : The figure can be labeled as shown below –
There are a total of 36 triangles in the above figure. They are AEI, IEB, BJF, CJF, DKG, CKG, HAL, DHL, AEB, BFC, CGD, DHA, AML, LMD, DMK, KMC, CMJ, JMB, BMI, IMA, AMD, DMC, CMB,
Question : A loan is to be returned in two equal yearly instalments. If the rate of interest is 10% p.a. compounded annually and each instalment is INR 5,808, then 60% of the total interest (nearest to INR) charged in this scheme is:
Option 1: 917
Option 2: 911
Option 3: 922
Option 4: 913
Correct Answer: 922
Solution : Let the loan amount be P. Then using P = $\frac{\text{A}}{(1 +\frac{\text{R}}{100})^T}$, where A is amount due at R% rate of interest for $T$ years ⇒ P = $\frac{5808}{(1+\frac{10}{100})}$ + $\frac{5808}{(1+\frac{10}{100})^{2}}$ = $\frac{5808}{\frac{11}{10}}$ + $\frac{5808}{\frac{121}{100}}$ = $\frac{58080}{11}$ + $\frac{580800}{121}$ = 5280 + 4800 = 10080
Question : Which of the following pairs is correct?
I. Summer Olympics 2020-Tokyo
II. Summer Olympics 2016- Rio de Janeiro
III. Summer Olympics 2012-London
Option 1: Only I and II
Option 2: Only I and III
Option 3: Only II and III
Option 4: All are correct
Correct Answer: All are correct
Solution : The correct answer is All are correct.
For the first time, the Olympics happened in 1896 in Athens, Greece.
The locations of some of the recent Olympic events are:
Question : The curved surface area of a solid hemisphere is 22 cm2. What is the total surface area of the hemisphere? (use $\pi=\frac{22}{7}$)
Option 1: 66 cm2
Option 2: 44 cm2
Option 3: 33 cm2
Option 4: 30 cm2
Correct Answer: 33 cm2
Solution : Given: The curved surface area of a solid hemisphere is 22 cm2. The curved surface area of the hemisphere = $2\pi r^2$ The total surface area of the hemisphere = $3\pi r^2$ where $r$ is the radius. According to the question,
Question : Directions: Which of the following numbers will replace the question mark (?) in the given series? $\frac{1}{2}, \frac{3}{4}, ?, \frac{5}{4}$
Option 1: 1
Option 2: $\frac{1}{4}$
Option 3: $\frac{3}{4}$
Option 4: $\frac{2}{3}$
Correct Answer: 1
Solution : Given: $\frac{1}{2}, \frac{3}{4}, ?, \frac{5}{4}$
In the given series, add $\frac{1}{4}$ to the previous number to get the next number. $\frac{1}{2}$ + $\frac{1}{4}$ = $\frac{3}{4}$; $\frac{3}{4}$ + $\frac{1}{4}$ = $\frac{4}{4}$ = 1; 1 + $\frac{1}{4}$ = $\frac{5}{4}$
So, 1 is the missing number of the
Question : If $ax+by=1$ and $bx+ay=\frac{2ab}{a^{2}+b^{2}}$, then $(x^{2}+y^{2})(a^{2}+b^{2})$ is equal to:
Option 2: 2
Option 3: 0.5
Option 4: 0
Solution : $ax+by=1$ ---------------------------------------(1) $bx+ay=\frac{2ab}{a^{2}+b^{2}}$ -----------------------------------(2) On dividing equation (1) by (2), we get, ⇒ $\frac{ax+by}{bx+ay}=\frac{a^{2}+b^{2}}{2ab}$ ⇒ $2a^{2}xb+2ab^{2}y=a^{2}bx+b^{3}x+a^{3}y+ab^{2}y$ ⇒ $a^{2}xb+ab^{2}y=b^{3}x+a^{3}y$ ⇒ $a^{2}xb-b^{3}x=a^{3}y-ab^{2}y$ ⇒ $x(a^{2}b-b^{3})=y(a^{3}-ab^{2})$ ⇒ $\frac{x}{y}=\frac{(a^{3}-ab^{2})}{(a^{2}b-b^{3})}$ ⇒ $\frac{x}{y}=\frac{a(a^{2}-b^{2})}{b(a^{2}-b^{2})}$ ⇒ $\frac{x}{y}=\frac{a}{b}$ ---------------------------------(3) Putting the value of $(x,y)$ from equation (3) in equation (1), we get, ⇒ $y=\frac{b}{a^{2}+b^{2}}$ ⇒
Question : The time required for a sum of money to amount to three times itself at 8% simple interest p.a. will be:
Option 1: 35 years
Option 2: 25 years
Option 3: 30 years
Option 4: 20 years
Correct Answer: 25 years
Solution : Given: Rate is 8% Let the Principle be P. It amounts to 3 times of itself. Simple interest = 3P – P = 2P We know, Simple interest $= \frac{\text{Principal × Rate × Time}}{100}$ ⇒ $2P =\frac{P×8×\text{Time}}{100}$ ⇒ Time = 25 years Hence, the
Question : One of the regions that receives rainfall from North-Easterly monsoon is :
Option 1: West Bengal
Option 2: Assam
Option 3: Kerela
Option 4: Tamil Nadu
Correct Answer: Tamil Nadu
Solution : The correct option is - Tamil Nadu
Most of the yearly rainfall in Tamil Nadu is accounted by the northeast monsoon. The northeast monsoon, commonly known as the winter monsoon, approaches India from that direction. The wind blows from land to sea during this
Question : P, Q, and R can complete a piece of work in 10 days, 15 days, and 20 days, respectively. If they work together, in how many days can they finish the same work?
Option 1: $4 \frac{8}{13}$
Option 2: $4 \frac{3}{7}$
Option 3: $4 \frac{7}{13}$
Option 4: $4 \frac{5}{7}$
Correct Answer: $4 \frac{8}{13}$
Solution : P, Q and R can complete a task in 10 days, 15 days and 20 days, respectively. P's work in 1 day = $\frac{1}{10}$ Q's work in 1 day = $\frac{1}{15}$ R's work in 1 day = $\frac{1}{20}$ Work done by P, Q, and
Question : The value of $\tan 5^{\circ} \tan 25^{\circ} \tan 45^{\circ} \tan 65^{\circ} \tan 85^{\circ}$ is ______.
Option 1: 4
Option 2: 3
Option 3: 1
Option 4: 2
Solution : $\tan 5^{\circ} \tan 25^{\circ} \tan 45^{\circ} \tan 65^{\circ} \tan 85^{\circ}$ $=\tan 5^{\circ} \tan (90^{\circ} - 5^{\circ})\tan 25^{\circ} \tan (90^{\circ} - 25^{\circ}) \tan 45^{\circ}$ $=\tan 5^{\circ} \cot 5^{\circ}\tan 25^{\circ} \cot 25^{\circ} \times 1$ $=1 \times 1\times 1$ $= 1$ Hence, the correct answer is 1.
The Question containing Inaapropriate or Abusive Words
Question lacks the basic details making it difficult to answer
Topic Tagged to the Question are not relevant to Question
Question drives traffic to external sites for promotional or commercial purposes
The Question is not relevant to User
And never miss an important update