Staff Selection Commission Combined Graduate Level Exam
Question : Microbial Type Culture Collection Centre is situated at :
Option 1: Bangalore
Option 2: Chandigarh
Option 3: New Delhi
Option 4: Hyderabad
Correct Answer: Chandigarh
Solution : The correct option is - Chandigarh
The Microbial Type Culture Collection and Gene Bank is located in The Institute of Microbial Technology (IMTECH), Chandigarh. It was started in 1986 and is supported equally by the Indian government's Council of Scientific and Industrial Research (CSIR) and
Question : Which of the following options gives an expression equivalent to $\sin \ (A + B)$?
Option 1: $\cos\ A \cos\ B - \sin \ A \sin \ B$
Option 2: $\sin\ A \cos \ B + \cos\ A\ \sin \ B$
Option 3: $\cos \ A \cos\ B+\sin\ A \sin \ B$
Option 4: $\sin \ A \cos \ B - \cos \ A \sin \ B$
Correct Answer: $\sin\ A \cos \ B + \cos\ A\ \sin \ B$
Solution : Given: $\sin \ (A + B)$ We know the formula, $\sin\ (A + B) = (\sin\ A \cos\ B + \cos\ A\ \sin\ B)$ Hence, the correct answer is $(\sin\ A \cos \ B +
Question : Select the most appropriate one-word substitution for the given words. A word or law no longer in use
Option 1: Venerable
Option 2: Obsolete
Option 3: Vintage
Option 4: Absolute
Correct Answer: Obsolete
Solution : The correct choice is the second option.
The most suitable one-word substitution for "a word or law no longer in use" is obsolete. This term describes something that is no longer in use or has become outdated. In the context of a word or
Question : Directions: In a certain code language, ABOUT is written as YZQSR, and PARTS is written as NYTRQ. How will PLANT be written in that language?
Option 1: NICRL
Option 2: NJCLR
Option 3: RJCLV
Option 4: NJDLP
Correct Answer: NJCLR
Solution : Given: ABOUT is written as YZQSR, and PARTS is written as NYTRQ.
Subtract 2 to the place value of each letter of the word ABOUT and add 2 to the middle letter to get the code – ABOUT→A – 2 = Y; B – 2
Question : If $x\left(3-\frac{2}{x}\right)=\frac{3}{x}$, then the value of $x^3-\frac{1}{x^3}$ is equal to:
Option 1: $\frac{8}{27}$
Option 2: $\frac{61}{27}$
Option 3: $\frac{62}{27}$
Option 4: $\frac{52}{27}$
Correct Answer: $\frac{62}{27}$
Solution : $x\left(3-\frac{2}{x}\right)=\frac{3}{x}$ ⇒ $3x-2 = \frac{3}{x}$ ⇒ $3x- \frac{3}{x} = 2$ ⇒ $(x- \frac{1}{x}) = \frac{2}{3}$ $\because$ $(x-y)^3 = x^3-y^3-3xy(x-y)$ $(x- \frac{1}{x})^3 = (\frac{2}{3})^3$ ⇒ $x^3-\frac{1}{x^3} - 3(x-\frac{1}{x}) = \frac{8}{27}$ ⇒ $x^3-\frac{1}{x^3} - 3(\frac{2}{3}) = \frac{8}{27}$ ⇒ $x^3-\frac{1}{x^3} = \frac{8}{27}+2$ ⇒ $x^3-\frac{1}{x^3} = \frac{62}{27}$ Hence, the
Question : Directions: From the given alternative words, select the word that cannot be formed using the letters of the given word. PRONOUNCEMENT
Option 1: MOUNT
Option 2: CEMENT
Option 3: PAVEMENT
Option 4: NOUN
Correct Answer: PAVEMENT
Solution : Given: PRONOUNCEMENT
Now, let's compare all the option words with the word PRONOUNCEMENT – First option: MOUNT; All the letters of MOUNT are present in the word PRONOUNCEMENT. Second option: CEMENT; All the letters of CEMENT are present in the word PRONOUNCEMENT. Third option: PAVEMENT;
Question : Select the most appropriate synonym of the underlined word.
During the summer of 1893, Miss. Sullivan and I visited the World's Fair with Dr. Alexander Graham Bell. I recall with unmixed delight those days when a thousand childish fancies became beautiful realities.
Option 1: enchant
Option 2: dismay
Option 3: memory
Option 4: emotion
Correct Answer: enchant
Solution : The correct choice is the first option.
Enchant means to fill with great pleasure. In the sentence, the speaker is recalling days filled with joy, which aligns with the meaning of delight.
The meanings of the other options are as follows:
Question : Directions: Select the correct combination of mathematical signs to sequentially replace the * signs and balance the given equation. 7 * 5 * 4 * 2 * 3 * 7
Option 1: ÷, –, +, ×, =
Option 2: +, –, ÷, –, =
Option 3: ÷, +, ÷, +, =
Option 4: –, ÷, +, ×, =
Correct Answer: +, –, ÷, –, =
Solution : Given: 7 * 5 * 4 * 2 * 3 * 7
Let's check the given options – First option: ÷, –, +, ×, = ⇒ 7 ÷ 5 – 4 + 2 × 3 = 7 Solving the L.H.S. of
Question : If $(x+\frac{1}{x})$ = 5, then the value of $\frac{5x}{x^{2}+5x+1}$ is:
Option 1: $\frac{1}{3}$
Option 2: $\frac{1}{4}$
Option 3: $\frac{1}{2}$
Option 4: $\frac{1}{5}$
Correct Answer: $\frac{1}{2}$
Solution : Given: $(x+\frac{1}{x})$ = 5 ⇒ $x^2+1= 5x$ Now, $\frac{5x}{x^{2}+5x+1}$ = $\frac{5x}{x^{2}+1+5x}$ = $\frac{5x}{5x+5x}$ = $\frac{5x}{10x}$ = $\frac{1}{2}$ Hence, the correct answer is $\frac{1}{2}$.
Question : What is the number of common tangents that can be drawn to two circles that touch each other externally?
Option 1: 2
Option 2: 4
Option 3: 3
Option 4: 1
Correct Answer: 3
Solution : Only three tangents can be drawn passing through two external touching circles. Hence, the correct answer is 3.
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