Staff Selection Commission Combined Graduate Level Exam
Question : Select the option that will improve the underlined part of the given sentence. In case no improvement is needed, select 'No improvement required'.
Do I need finish this work today itself?
Option 1: Must I to
Option 2: Need I
Option 3: No improvement required
Option 4: Do I must
Correct Answer: Need I
Solution : The correct option is the second option.
Explanation: The reason is that it maintains the inversion often used in formal or archaic language. Inverted questions, where the auxiliary verb (need) comes before the subject (I), are common in more formal
Question : Directions: In the following question, find the odd letter cluster from the given alternatives.
Option 1: DGI
Option 2: JMO
Option 3: PRT
Option 4: TWY
Correct Answer: PRT
Solution : Let's check the options – First option: DGI; D + 3 = G; G + 2 = I Second option: JMO; J + 3 = M; M + 2 = O Third option: PRT; P + 2 = R; R + 2 = T Fourth
Question : Directions: Three of the following four-letter clusters are alike in a certain way and one is different. Pick the odd one out.
Option 1: UVZ
Option 2: MNP
Option 3: XYA
Option 4: QRT
Correct Answer: UVZ
Solution : Let's check each option – First option: UVZ; U + 1 = V; V + 4 = Z Second option: MNP; M + 1 = N; N + 2 = P Third option: XYA; X + 1 = Y; Y + 2 = A Fourth
Question : The first operational electronic digital computer is:
Option 1: ENIAC
Option 2: EDVAC
Option 3: EDSAC
Option 4: UNIVAC
Correct Answer: ENIAC
Solution : The correct option is ENIAC.
The "ENIAC" (Electronic Numerical Integrator and Computer) is usually regarded as the first operating electronic digital computer. ENIAC was created during WWII and completed in 1945. It was a gigantic machine that took up a vast room, and its electronic
Question : Which of the given responses would be a meaningful order of the following?
1. Frog 2. Eagle 3. Grasshopper 4. Snake 5. Grass
Option 1: 5,3,4,2,1
Option 2: 1,3,5,2,4
Option 3: 5,3,1,4,2
Option 4: 3,4,2,5,1
Correct Answer: 5,3,1,4,2
Solution : Given - 1. Frog 2. Eagle 3. Grasshopper 4. Snake 5. Grass
Here,
The correct order of the parts of a food chain is: 5. Grass, 3. Grasshopper, 1. Frog, 4. Snake, 2. Eagle.
Hence, third option is correct.
Question : The distance between the centres of two circles of radii 2 cm and 6 cm is 5 cm. Find the length of the direct common tangent.
Option 1: $6 \mathrm{~cm}$
Option 2: $3 \mathrm{~cm}$
Option 3: $9 \mathrm{~cm}$
Option 4: $\frac{5}{2} \mathrm{~cm}$
Correct Answer: $3 \mathrm{~cm}$
Solution : Given: The distance between the centres of two circles of radii 2 cm and 6 cm is 5 cm The length of the direct common tangent between two circles $ = \sqrt{d^2 - (r_1 - r_2)^2}$ where $d$ is the distance between the centres
Question : Select the most appropriate ANTONYM of the underlined word. Evolutionary psychology is a recently advanced field of study, which has grown exponentially with interest since the 1980s.
Option 1: Rudimentary
Option 2: Lackadaisical
Option 3: Operative
Option 4: Presumptuous
Correct Answer: Rudimentary
Solution : The first option is the correct answer.
In the context of the sentence, advanced refers to the significant development and progress of evolutionary psychology. The antonym rudimentary fits well, indicating a basic or early stage of development, contrasting with the idea of significant advancement.
The
Question : The volume of a right circular cone is 1232 cm3 and its vertical height is 24 cm. Its curved surface area is:
Option 1: 154 cm2
Option 2: 550 cm2
Option 3: 604 cm2
Option 4: 704 cm2
Correct Answer: 550 cm2
Solution : Given: The volume of a right circular cone is 1232 cm3 and its vertical height is 24 cm. Let $r$, $h$, and $l$ be the radius, height, and slant height of the cone. According to the question, $\frac{1}{3}×\pi×r^2×h=1232$ Or, $\frac{1}{3}×\frac{22}{7}×r^2×24=1232$ Or, $r^2=\frac{1232×7×3}{22×24}$
Question : Directions: Select the missing number from the given responses.
Option 1: 120
Option 2: 23
Option 3: 55
Option 4: 30
Correct Answer: 23
Solution : Given:
In each row, the third number is the difference between the first two. Row 1: 134 – 34 = 100 Row 2: 117 – 86 = 31 Row 3: 87 – (?) = 64 ⇒
Question : If A borrowed Rs. $P$ at $x$% and B borrowed Rs. $Q (> P)$ at $y$% per annum in simple interest at the same time, then the amount of their debts will be equal after:
Option 1: $100(\frac{Q-P}{Px-Qy})$
Option 2: $100(\frac{Px-Qy}{Q-P})$
Option 3: $100(\frac{Px-Qy}{P-Q})$
Option 4: $100(\frac{P-Q}{Px-Qy})$
Correct Answer: $100(\frac{Q-P}{Px-Qy})$
Solution : Given: $P$ is the principal, $x$ is the rate for 1st case, $Q$ is the principal and $y$ is the rate for the second case. Let the amount be equal in $T$ years. Simple interest = $\frac{P×R×T}{100}$ According to the question: $P+\frac{P×x×T}{100}=Q+\frac{Q×y×T}{100}$ ⇒ $\frac{PxT}{100}-\frac{QyT}{100}=Q–P$ ⇒
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