Staff Selection Commission Combined Graduate Level Exam
Question : Direction: The following bar graph shows the production of table fans in a factory for one week. Study the bar graph and answer the given question.
The maximum production exceeds the minimum production by:
Option 1: 400
Option 2: 420
Option 3: 500
Option 4: 540
Correct Answer: 420
Solution : The provided bar graph shows that the maximum production is 540 and the minimum production is 120, respectively. Difference = Maximum production – Minimum production = 540 – 120 = 420 Hence, the correct answer is 420.
Question : A, B, and C are employed to do a piece of work for INR 5,290. A and B together are supposed to do $\frac{19}{23}$ of the work and B and C together $\frac{8}{23}$ of the work. Then A should be paid:
Option 1: INR 4,250
Option 2: INR 3,450
Option 3: INR 1,950
Option 4: INR 2,290
Correct Answer: INR 3,450
Solution : Part of work done by A and B together = $\frac{19}{23}$ of total work Part of work done by B and C together = $\frac{8}{23}$ of total work Part of the work done by A alone = Total work – Part of work done
Question : If $m-n=2$ and $mn=15,(m,n>0)$ , then the value of $(m^2-n^2)(m^3-n^3)$ is:
Option 1: 1856
Option 2: 1658
Option 3: 1586
Option 4: 1568
Correct Answer: 1568
Solution : Given: $m-n=2$ and $mn=15,(m,n>0)$ $(m-n)^2=2^2$ ⇒ $m^2+n^2-2mn=4$ ⇒ $m^2+n^2=4+(2×15)=34$ ⇒ $m^2+n^2+30=34+30$ [adding 30 to both sides] ⇒ $m^2+n^2+2mn=64$ [as, $mn=15$] ⇒ $(m+n)^2=8^2$ ⇒ $m+n=8$ Now, $(m^2-n^2)(m^3-n^3)$ = $(m+n)(m-n) (m-n)(m^2+mn+n^2)$ = $8×2×2×(34+15)$ = $1568$ Hence, the correct answer is 1568.
Question : Select the option that can be used as a one-word substitute for the given group of words.
One who runs away from the law.
Option 1: Fatalist
Option 2: Convict
Option 3: Fugitive
Option 4: Lunatic
Correct Answer: Fugitive
Solution : The third option is the correct answer.
The term fugitive is the most appropriate, as it specifically refers to a person who is fleeing or evading legal authorities to escape punishment or arrest.
The meanings of the other options are as follows:
Question : Which of the following is equal to $[\frac{\tan \theta+\sec \theta–1}{\tan \theta–\sec \theta+1}]$?
Option 1: $\frac{1+\sin \theta}{\cos \theta}$
Option 2: $\frac{1+\tan \theta}{\cot \theta}$
Option 3: $\frac{1+\cot \theta}{\tan \theta}$
Option 4: $\frac{1+\cos \theta}{\sin \theta}$
Correct Answer: $\frac{1+\sin \theta}{\cos \theta}$
Solution : Given: The given trigonometric expression is $[\frac{\tan \theta+\sec \theta–1}{\tan \theta–\sec \theta+1}]$. Use the trigonometric identity, $\sec^2\theta–\tan^2\theta=1$ ⇒ $[\frac{\tan \theta+\sec \theta–(\sec^2\theta–\tan^2\theta)}{\tan \theta–\sec \theta+1}]=[\frac{(\tan \theta+\sec \theta)(1–\sec\theta+\tan \theta)}{\tan \theta–\sec \theta+1}$ $=\tan \theta+\sec \theta=\frac{1+\sin \theta}{\cos \theta}$ Hence, the correct answer is $\frac{1+\sin \theta}{\cos \theta}$.
Question : If $\cos \theta=\frac{\sqrt{3}}{2}$, then $\tan ^2 \theta \cos ^2 \theta=?$
Option 1: $\frac{1}{\sqrt{3}}$
Option 2: $\frac{1}{4}$
Option 3: $\frac{1}{2}$
Option 4: $\sqrt{3}$
Correct Answer: $\frac{1}{4}$
Solution : We have, $\cos \theta = \frac{\sqrt{3}}{2}$ ⇒ $\cos \theta = \cos 30^\circ$ ⇒ $\theta = 30^\circ$ Now, $\tan^2 \theta \cos^2 \theta=\tan^2 30^\circ \cos^2 30^\circ= (\frac{1}{\sqrt3})^2 ×(\frac{\sqrt{3}}{2})^2$ $= \frac{1}{4}$ Hence, the correct answer is $\frac{1}{4}$.
Question : A man can cover a certain distance in 3 hours and 36 minutes if he walks at a rate of 5 km/h. If he covers the same distance on a bicycle at a rate of 24 km/h, then the time taken by him in minutes is:
Option 1: 40
Option 2: 45
Option 3: 50
Option 4: 55
Correct Answer: 45
Solution : Let the time taken by him on a bicycle be $x$ hour. Distance covered by him by walking = $5×3\frac{36}{60}=5×\frac{18}{5}=18$ km. Distance covered by him on the bicycle = 24$x$ km. According to the question, 24$x$ = 18 ⇒ $x = \frac{18}{24}$ hour = $\frac{18}{24}×60$
Question : Shiva’s monthly salary is Rs.75,000. He spends Rs.12,000 on household items, Rs.14,000 on LIC and mutual funds, Rs.15,000 on his children’s education, and keeps Rs.10,000 for miscellaneous expenses. His savings are Rs.21,000 per month and he donates the rest of the amount to an orphanage. The percentage of his income that he donates is:
Option 1: 3%
Option 2: 6%
Option 3: 8%
Option 4: 4%
Correct Answer: 4%
Solution : Percentage Donated = $\frac{\text{Amount Donated}}{\text{Total Income}}\times 100$ First, let's calculate the total expenses: Total Expenses = Household items + LIC and mutual funds + Children's education + Miscellaneous expenses Total Expenses = Rs. 12,000 + Rs. 14,000 + Rs. 15,000 + Rs. 10,000 = Rs.
Question : Select the option that contains a grammatical error in the underlined portion.
When Mrs. Sinha came to see Varanasi in 2019, Nupur has already been teaching there for five years.
Option 1: When Mrs. Sinha came to see Varanasi in 2019, Nupur has already been teaching there for five years.
Option 2: When Mrs. Sinha came to see Varanasi in 2019, Nupur has already been teaching there for five years.
Option 3: When Mrs. Sinha came to see Varanasi in 2019, Nupur has already been teaching there for five years.
Option 4: When Mrs. Sinha came to see Varanasi in 2019, Nupur has already been teaching there for five years.
Correct Answer: When Mrs. Sinha came to see Varanasi in 2019, Nupur has already been teaching there for five years.
Solution : The correct choice is the second option.
The past perfect tense "had already been teaching" should have been used as it indicates an action that was completed before
Question : Match the columns (As per Census 2011).
Option 1: 1-a, 2-b, 3-c
Option 2: 1-b, 2-a, 3-c
Option 3: 1-a, 2-c, 3-b
Option 4: 1-c, 2-b, 3-a
Correct Answer: 1-a, 2-b, 3-c
Solution : The correct answer is 1-a, 2-b, 3-c.
Kerala - a. Highest sex ratio. The sex ratio of Kerala is 1084, one of the highest sex ratios in India whereas 943 is the sex ratio of India.
Haryana - b. Lowest sex ratio. Haryana
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