Correct Answer: 10

Solution : The correct option is 10.

One-Day Internationals (ODIs) are where two teams face 50 overs in one day. Each team gets to bat and bowl once. Bowlers are limited to bowling a maximum of 10 overs. The team can use as many bowlers as

Correct Answer: West

Solution : Firstly, draw the direction and distance diagram according to the instructions –

From the above diagram, it is clear that Sudhir's starting point is in the West direction from the school.

Therefore, West is the correct answer. Hence, the second option is correct.

Correct Answer: $150\left (3 +{\sqrt3} \right)$

Solution :
In $\Delta ABC$
$\tan 60^{\circ} = \frac{AB}{BC}$
$⇒\sqrt{3} = \frac{AB}{BC}$
$⇒AB = \sqrt{3} BC \quad \text{-----------------------(1)}$
In $\Delta ABD$
$\tan 45^{\circ} = \frac{AB}{BD}$
$\Rightarrow 1 = \frac{AB}{BD}$
$⇒AB = BD \quad \text{---------------------------------(2)}$
From equation $(1)$ and equation $(2)$
$\Rightarrow BD = \sqrt{3}

Correct Answer: 10

Solution : Given: 10 men can do a work in 25 days. After 12 days of work, 3 more men were engaged to finish the work.
Here, $M_1=10,M_2=10+3=13,D_1=25-12=13$
We know, $M_1D_1= M_2D_2$
⇒ 10 × 13 = 13 × D₂
$\therefore$ D₂ = 10 days

Correct Answer: TASTE

Solution : Given:
ERADICATE

Let's compare all the option words with the word ERADICATE –
First option: AREA; All the letters of AREA are present in the word ERADICATE.
Second option: CARE; All the letters of CARE are present in the word ERADICATE.
Third option: DICE; All

Correct Answer: Pure Water

Solution : The correct option is pure water.

A substance having a pH of 7 is regarded as neutral. It has neither acidic or alkaline (basic) properties. A material with a pH value of 7 is pure water at room temperature. The point of neutrality is

Correct Answer: (29, 23, 98)

Solution : Given:
(40, 120, 400); (18, 20, 78)

Here, (40, 120, 400)→(120 × 3) + 40 = 360 + 40 = 400
(18, 20, 78)→(20 × 3) + 18 = 60 + 18 = 78

Let's check the options –
First option: (29, 23,

Correct Answer: $11\frac{1}{9}$%

Solution : Total spending = (80 + 10 + 20 + 10 + 15) = Rs. 135 lakhs
Spending on miscellaneous products = Rs. 15 lakhs
Required percentage = $\frac{\text{Miscellaneous items expenditure}}{\text{Total expenditure}} \times 100=\frac{15}{135} \times 100 = \frac{100}{9}=11\frac{1}{9}$%
Hence, the correct answer is $11\frac{1}{9}$%.

Correct Answer: Dabir-i-Khas

Solution : The correct answer is Dabir-i-Khas.

During the Delhi Sultanate, the "Dabir-i-Khas" or "Amir-Munshi" was indeed the head of the Diwan-i-Insha department. This department was responsible for managing official correspondence, including communication between the Sultan, and foreign rulers, subordinate chiefs, and officials. The Amir-Munshi oversaw this

Correct Answer: 2121514

Solution : Given:
STAR is written as 8110291 and GIFT is written as 02697.

Write the place value of the letters of STAR in reverse order, to obtain the required code –
Place value of STAR→S = 19; T = 20; A = 1; R = 18