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Staff Selection Commission Combined Graduate Level Exam

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Question : The first edition of the Commonwealth Youth Games was organised in which of the following years?

Option 1: 2008

Option 2: 2012

Option 3: 2000

Option 4: 2016

Team Careers360 14th Jan, 2024

Correct Answer: 2000


Solution : The correct option is 2000.

August 2000 saw the inaugural Commonwealth Youth Games take place in Edinburgh, Scotland. Seventy-three athletes from fourteen different countries competed. For three days, they participated in eight different sports. In December 2004, the CYG hosted its second edition in

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Question : If $x$ runs are scored by A, $y$ runs by B, and $z$ runs by C then, $x:y=y:z=3:2$. If the total number of runs scored by A, B, and C is 342, the runs scored by each would be:

Option 1: 144, 96, and 64

Option 2: 162,108, and 72

Option 3: 180, 120, and 80

Option 4: 189, 126, and 84

Team Careers360 22nd Jan, 2024

Correct Answer: 162,108, and 72


Solution : Given: $x$ runs are scored by A, $y$ runs by B, and $z$ runs by C then, $x:y=y:z=3:2$. The total number of runs scored by A, B, and C is 342.
$x:y=3:2=9:6$ and $y:z=3:2=6:4$
So, $x:y:z=9:6:4$
According to the given information,
$9a+6a+4a=342$

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Question : Direction: Which one set of the letters when sequentially placed in the gaps in the given letter series shall complete it?

aa_baa_aaa_ba_ba

 

Option 1: bbba

Option 2: abab

Option 3: abaa

Option 4: babb

Team Careers360 15th Jan, 2024

Correct Answer: bbba


Solution : Given:

aa_baa_aaa_ba_ba

Let's check the options –

First option: bbba

The series becomes aabbaabaaabbaaba

The pattern in the series becomes aabbaaba / aabbaaba

Second option: abab

The series becomes

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Question : If $A =(\frac{1}{0.4})+(\frac{1}{0.04})+(\frac{1}{0.004})+....$ upto 8 terms, then what is the value of $A$?

Option 1: 27272727.5

Option 2: 25252525.5

Option 3: 27777777.5

Option 4: 25555555.5

Team Careers360 19th Jan, 2024

Correct Answer: 27777777.5


Solution : Given: $ A =(\frac{1}{0.4})+(\frac{1}{0.04})+(\frac{1}{0.004})+....$ upto 8 terms.
This expression can be written as:
$⇒ A =(\frac{10}{4})+(\frac{100}{4})+(\frac{1000}{4})+(\frac{10000}{4})+(\frac{100000}{4})+(\frac{1000000}{4})(\frac{10000000}{4})+(\frac{100000000}{4})$
Using the formula, $S_n = \frac{a(r^n-1)}{r-1}$, where $a$ = first term, $r$ = common ratio, $n$ = number of terms
$10 + 100 + 1000+ .............+ 100000000 = \frac{10(10^8-1)}{10-1}=111111110$

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Question : Kosala Mahajanapada (6th century BCE) is a part of modern-day

Option 1: Maharashtra

Option 2: Haryana

Option 3: Madhya Pradesh

Option 4: Uttar Pradesh

Team Careers360 24th Jan, 2024

Correct Answer: Uttar Pradesh


Solution : The correct option is Uttar Pradesh.

Kosala Mahajanapada, an ancient Indian kingdom flourishing in the 6th century BCE, was one among the sixteen pivotal political and cultural centres of ancient India known as Mahajanapadas. Situated in the northern expanse of the Indian subcontinent,

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Question : A can do a piece of work in 20 days and B in 15 days. With the help of C, they finish the work in 5 days. C can alone do the work in:

Option 1: 5 days

Option 2: 6 days

Option 3: 10 days

Option 4: 12 days

Team Careers360 14th Jan, 2024

Correct Answer: 12 days


Solution : Given: A alone can do the work in 20 days.
B alone can do the work in 15 days.
A, B, and C together finish the work in 5 days.
Let C alone finish the work in $x$ days.
As per given conditions,

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