Staff Selection Commission Combined Graduate Level Exam
Question : Thalassemia is an example of
Option 1: Deletion mutation
Option 2: Point mutation
Option 3: Silent mutation
Option 4: Frame shift mutation
Correct Answer: Frame shift mutation
Solution : The correct answer is Frameshift mutation.
A frameshift mutation is insertion or deletion of nucleotide bases. A genetic code is read in triplets, and in frameshift mutation the altered nucleotide bases are not multiple of three. Examples of frameshift mutation are cystic fibrosis
Question : Directions: Three statements are followed by three conclusions numbered I, II, and III. You have to consider these statements to be true, even if they seem to be at variance with commonly known facts. Decide which of the given conclusions logically follow/s from the given statements. Statements: Some watches are projectors. All projectors are lamps. Some heaters are watches. Conclusions: (I) Some heaters are projectors. (II) Some lamps are heaters. (III) All watches are lamps.
Option 1: Only conclusion II follows
Option 2: None of the conclusions follow
Option 3: Only conclusion I follows
Option 4: Either conclusion I or conclusion III follows
Correct Answer: None of the conclusions follow
Solution : The possible Venn diagram according to the given statements is as follows –
Let's analyse the conclusions – Conclusion (I): Some heaters are projectors – From the Venn diagram, it is evident that there is no direct relation between heaters and
Question : Which cell organelles are the site of photosynthesis and also contain chlorophyll?
Option 1: Chloroplast
Option 2: Vacuole
Option 3: Cytoplasm
Option 4: Nucleolus
Correct Answer: Chloroplast
Solution : The correct option is Chloroplast.
A chloroplast is a specialised organelle found in plant and algal cells. It is a photosynthesis site where light energy is collected and turned into chemical energy via intricate molecular events. Chloroplasts contain chlorophyll, the green pigment found in plants
Question : The process of depositing a layer of any desired metal on another material using electricity is called _________.
Option 1: electroplating
Option 2: galvanisation
Option 3: rusting
Option 4: crystallisation
Correct Answer: electroplating
Solution : The correct option is electroplating.
Electroplating is depositing a thin metal coating onto the surface of another material using an electric current. It is widely used for ornamental, useful, and protective purposes. Examples include gold plating for jewellery, and chrome plating for automotive parts.
Question : If $\frac{b}{a}=0.7$, find the value of $\frac{a–b}{a+b}+\frac{11}{34}$.
Option 1: 0.2
Option 2: 1
Option 3: 0.5
Option 4: 0.3
Correct Answer: 0.5
Solution : Given: The value of the ratio $\frac{b}{a}=0.7$. The value of the expression $\frac{a–b}{a+b}+\frac{11}{34}$ is given as, $=\frac{1–\frac{b}{a}}{1+\frac{b}{a}}+\frac{11}{34}$ Substitute the value of $\frac{b}{a}=0.7$ in the above expression, $=\frac{1–0.7}{1+0.7}+\frac{11}{34}$ $=\frac{0.3}{1.7}+\frac{11}{34}$ $=0.17+0.33=0.5$ Hence, the correct answer is 0.5.
Question : Who is the Chief Minister of Tamilnadu ?
Option 1: Smt Jayalalitha
Option 2: M. K. Karunanidhi
Option 3: M. K. Stalin
Option 4: Kalanidhi Maran
Correct Answer: M. K. Stalin
Solution : The correct option is - M. K. Stalin
Indian politician M. K. Stalin is the eighth and current Chief Minister of Tamil Nadu. On May 7, 2021, he took his oath to serve as Chief Minister. He had been the first Deputy Chief
Question : The following pie chart shows the number of workers of different categories A, B, C, D, E, F, G and H in a factory in 1995. What is the central angle (angular value) for category B of the pie chart?
Option 1: 55°
Option 2: 54°
Option 3: 57°
Option 4: 56°
Correct Answer: 54°
Solution : Given percentage of B = 15% The central angle will be 15% of the 360° $= \frac{15}{100}\times 360° = 54°$ Hence, the correct answer is 54°.
Question : Direction: In the following question,one statement is given followed by two Conclusions I and II. You have to consider the statement to be true, even if it seems to be at variance from commonly known facts. You are to decide which of the given conclusions can be definitely be drawn from the given statement.
Statement : Aggressive animals can be trained with care and affection to behave as the occasion demands.
Conclusions :
I. Trained dogs cannot be aggressive.
II. Animals are always aggressive unless care and affection is given to them.
Option 1: Both I and II follows.
Option 2: Only I follows.
Option 3: Only II follows.
Option 4: Neither I nor II follows.
Correct Answer: Both I and II follows.
Solution : Conclusion I: Trained dogs cannot be aggressive. From the given statement, it can be said that if dogs are trained they won't be aggressive.
Conclusion II: Animals are always aggressive unless care and affection is given to them. From the given
Question : The sum of the first 20 term of the series $\frac{1}{5×6}+\frac{1}{6×7}+\frac{1}{7×8}+....$ is:
Option 1: 0.16
Option 2: 1.6
Option 3: 16
Option 4: 0.016
Correct Answer: 0.16
Solution : Given: The sum of the first 20 terms of the series $\frac{1}{5×6}+\frac{1}{6×7}+\frac{1}{7×8}+....$ So, $a_{1} =5$ and $a_{20} =5+(20-1)×1=24$ 20th term $=\frac{1}{24×25}$ $=\frac{1}{5×6}+\frac{1}{6×7}+\frac{1}{7×8}+.... + \frac{1}{24×25}$ $=\frac{1}{5}-\frac{1}{6} + \frac {1}{6} - \frac{1}{7}+\frac{1}{7}-\frac{1}{8}+..............+\frac{1}{24}-\frac{1}{25}$ $=\frac{1}{5}-\frac{1}{25}$ $=\frac{4}{25}$ $= 0.16$ Hence, the correct answer is 0.16.
Question : ______________ is a by product of sewage treatment and can be decomposed to produce biogas.
Option 1: Sewage
Option 2: Sludge
Option 3: Sewer
Option 4: Scum
Correct Answer: Sludge
Solution : The correct option is Sludge.
Sludge is a byproduct of sewage treatment that may be degraded to generate biogas through a biological process known as anaerobic digestion. Anaerobic digestion is the breakdown of organic materials by microbes in the absence of oxygen. In the case
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