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Staff Selection Commission Combined Graduate Level Exam

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Question : ABC is an isosceles right-angle triangle. $\angle ABC = 90 ^{\circ}$ and AB = 12 cm. What is the ratio of the radius of the circle inscribed in it to the radius of the circle circumscribing $\triangle ABC$?

Option 1: $6–\sqrt{2}: 3 \sqrt{2}$

Option 2: $2–\sqrt{2}: \sqrt{2}$

Option 3: $6–3 \sqrt{2}: 1 \sqrt{2}$

Option 4: $6–3 \sqrt{2}: 6 \sqrt{2}$

Team Careers360 17th Jan, 2024

Correct Answer: $2–\sqrt{2}: \sqrt{2}$


Solution :
Given: ABC is an isosceles right-angle triangle. $\angle ABC = 90 ^{\circ}$ and AB = 12 cm.
In $\triangle ABC$, $H^2=B^2+P^2$ (Using Pythagoras theorem).
⇒ $H^2=12^2+12^2$
⇒ $H^2=144+144=288$
⇒ $H=\sqrt{288}=12\sqrt2$ cm
Inradius of inscribed circle of right angled triangle = $\frac{(P + B –

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Question : What is the value of $\frac{7}{2}+\frac{11}{3}+\frac{7}{6}+\frac{11}{15}+\frac{7}{12}+\frac{11}{35}+\ldots \ldots+\frac{7}{156}+\frac{11}{575}$?

Option 1: $\frac{3917}{355}$

Option 2: $\frac{3816}{325}$

Option 3: $\frac{3714}{345}$

Option 4: $\frac{3216}{315}$

Team Careers360 23rd Jan, 2024

Correct Answer: $\frac{3816}{325}$


Solution : Given: The series is $\frac{7}{2}+\frac{11}{3}+\frac{7}{6}+\frac{11}{15}+\frac{7}{12}+\frac{11}{35}+\ldots \ldots+\frac{7}{156}+\frac{11}{575}$.
Determine the value of the series by solving two distinct series independently.
The sum of the first series = $\frac{7}{2}+\frac{7}{6}+\frac{7}{12}+...+\frac{7}{156}$
⇒ Sum = $7[1–(\frac{1}{2})+(\frac{1}{2}–\frac{1}{3})+(\frac{1}{3}–\frac{1}{4})+...+(\frac{1}{12}–\frac{1}{13})]$
⇒ Sum = $7[1–\frac{1}{13}]$
⇒ Sum = $7\times\frac{12}{13}=\frac{84}{13}$
The sum of the second series =

21 Views

Question : If $x+\left [\frac{1}{(x+7)}\right]=0$, what is the value of $x-\left [\frac{1}{(x+7)}\right]$?

Option 1: $3\sqrt{5}$

Option 2: $3\sqrt{5}-7$

Option 3: $3\sqrt{5}+7$

Option 4: $8$

Team Careers360 13th Jan, 2024

Correct Answer: $3\sqrt{5}-7$


Solution : Given: $x+[\frac{1}{(x+7)}]=0$
Adding both sides 7, we get,
⇒ $x+7+[\frac{1}{(x+7)}]=7$
Squaring both sides, we get,
⇒ $(x+7)^{2}+(\frac{1}{x+7})^{2}+2=49$
⇒ $(x+7)^{2}+(\frac{1}{x+7})^{2}=47$
Subtracting 2 from both sides,
$(x+7)^{2}+(\frac{1}{x+7})^{2}–2=47-2$
⇒ $[(x+7)-(\frac{1}{x+7})]^{2}=45$
⇒ $[(x+7)-(\frac{1}{x+7})]=\sqrt{45}$
⇒ $[(x-\frac{1}{x+7})]=\sqrt{45}-7=\sqrt{9 \times5}-7=3\sqrt{5}–7$
Hence, the correct answer is $3\sqrt{5}-7$.

55 Views

Question : What will be the remainder when $27^{27}+27$ is divided by 28?

Option 1: 28

Option 2: 27

Option 3: 25

Option 4: 26

Team Careers360 21st Jan, 2024

Correct Answer: 26


Solution : $27^{27}+27$ can written as $27^{27}+1^{27}-1+27=(27^{27}+1^{27})+26$
We know that An + Bn is divisible by A + B when n is odd.
Here n = 27 is an odd number.
When $(27^{27}+1^{27})$ is divided by 28, the remainder will be 0.
And, when $(27^{27}+1^{27})+26$

6 Views

Question : Directions: From the given option figures, select the one in which the question figure is embedded.

Option 1:

Option 2:

Option 3:

Option 4:

Team Careers360 23rd Jan, 2024

Correct Answer:


Solution : As there is no restriction on the rotation of the figure, we will check all possible angles where the question figure can fit itself in all the given option figures.
The question figure is embedded only in the first option figure.

Hence, the first option is

24 Views

Question : Direction: In the following question a series is given, with one term missing. Choose the correct alternative from the given ones that will complete the series.

156, 506, ?, 1806

Option 1: 1056

Option 2: 856

Option 3: 1456

Option 4: 1506

Team Careers360 15th Jan, 2024

Correct Answer: 1056


Solution : Given:

156, 506, ?, 1806

Here,

122 + 12 = 156

222 + 22 = 506

322 + 32 = 1056

422 + 42 = 1806

So, the missing number is 1056.

Hence, the first option is correct.

21 Views

Question : Select the most appropriate synonym of the given word.

Keen

Option 1: Happy

Option 2: Enthusiastic

Option 3: Wild

Option 4: Imitate

Team Careers360 22nd Jan, 2024

Correct Answer: Enthusiastic


Solution : The correct choice is the second option.

The word keen has a few potential synonyms, but the most appropriate one among the options provided would be enthusiastic.

The meanings of other words are as follows:

  • Happy refers to a feeling of pleasure, contentment,
45 Views

Question : The number of students in section A and section B of a class are 40 and 52, respectively. The average score in mathematics of all the students is 75. If the average score of the students in A is 20 % more than that of students in B then what is the average score of students in B?

Option 1: 71

Option 2: 65

Option 3: 69

Option 4: 63

Team Careers360 13th Jan, 2024

Correct Answer: 69


Solution : Total number of students = 40 + 52 = 92
⇒ $75 = \frac{\text{(Sum of scores of all students)}}{92}$
⇒ Total score in mathematics = 75 × 92 = 6900
Now,
Let the average score of section B students be $x$
⇒ Average score of

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