Correct Answer: + and ÷

Solution : Given:
1000 – 448 + 14 ÷ 15 × 2 = 998

Let's check the options –
First option: + and ÷
The equation becomes ⇒ 1000 – 448 ÷ 14 + 15 × 2 = 998
Solving the L.H.S. of the equation

Correct Answer: (36, 14, 35)

Solution : Given: 
(21, 33, 31)
(42, 17, 26)

Adding all the numbers in the set –
⇒ (21, 33, 31)→21+ 33 + 31 = 85
⇒ (42, 17, 26)→42 + 17 + 26 = 85

Let's check the options –
First option: (36, 14,

Correct Answer: 675

Solution : Here, the given equations follows a pattern in which the first number, the middle number and the last number in LHS becomes the units place digit , the hundreds place digit and the tens place digit in the answer part in RHS respectively.

⇒ 1

Correct Answer: a = 70$^{\circ}$ and b = 110$^{\circ}$

Solution : Since $l \parallel m$,
⇒ $\angle$ c = 110$^{\circ}$ (corresponding angles are equal)
Also, $\angle$ a + $\angle$ c = 180$^{\circ}$ (supplementary angles)
⇒ $\angle$ a = 180$^{\circ}$ – 110$^{\circ}$ = 70$^{\circ}$
Now, $\angle$ b = $\angle$ a +

Correct Answer: (4, 26, 416)

Solution : Given:
(6, 17, 408); (13, 27, 1404)

Multiply the first and the second numbers and then multiply the resultant by four to get the third number of the triad.
(6, 17, 408)→6 × 17 = 102; 102 × 4 = 408
(13, 27,

Correct Answer: 4

Solution : Given expression,
$\sqrt{20-\sqrt{20-\sqrt{20-\sqrt{20-\cdots \infty}}}}$
Let us equate this with $y$
⇒ $y=\sqrt{20-\sqrt{20-\sqrt{20-\sqrt{20-\cdots \infty}}}}$
⇒ $y=\sqrt{20-y}$
Squaring both sides,
⇒ $y^2=20-y$
⇒ $y^2+y-20=0$
⇒ $y^2+5y-4y-20=0$
⇒ $y(y+5)-4(y+5)=0$
⇒ $(y+5)(y-4)=0$
⇒ $y=-5$ and $y=4$
Hence, the correct answer is 4.

Correct Answer: 14

Solution : The correct answer is 14.

The key legislation related to the employment of children in India is the "Child and Adolescent Labour (Prohibition and Regulation) Act, 1986" (often referred to as the Child Labour Act). This Act prohibits the employment of children below the age

Correct Answer: OWRW

Solution : Given:

BR _ _ NB _ O _ NB

We have to check the order of the letters in the given series.

To fill the series we have to divide the series, BR _ _ / NB _ O / _ NB.

So, the series

Correct Answer: $\frac{209}{156}$

Solution : In the second quadrant, $\sin x$ and $\operatorname{cosec x}$ are positive.
$\tan x = –\frac{12}{5}$
$⇒\cot x=\frac{1}{\tan x}=-\frac{5}{12}$
We know, $\sec^2x -\tan^2x=1$
$⇒\sec^2x=1+(–\frac{12}{5})^2$
$⇒\sec^2x=1+\frac{144}{25}$
$⇒\sec^2x=\frac{169}{25}$
$⇒ \sec x=\frac{13}{5}$
$⇒\cos x = \frac{5}{13}$
$\therefore\sin x = \sqrt{1-\cos^2x}=\sqrt{1-\frac{25}{169}}=\frac{144}{169}=\frac{12}{13}$
$\sin x - \cot x = \frac{12}{13} – (-\frac{5}{12})

Correct Answer: Genuine

Solution : The correct option is the first option.

In the context of the word authentic, genuine is the most appropriate synonym because it closely aligns with the meaning of authentic, which means genuine, real, or true. It refers to something that is not a