Correct Answer: INR 3,800

Solution : We know the formula for successive discounts,
Selling price = $MP(1 - \frac{D_1}{100})(1 - \frac{D_2}{100})$
Where $MP$ is the marked price and $D_1, D_2$ are the discounts.
$\mathrm{D_1=5}$%
$\mathrm{D_2=15}$%
On substituting the values,
$\mathrm{MP(1 - \frac{5}{100})(1 - \frac{15}{100})}=3068.50$
$⇒\mathrm{MP×( \frac{19}{20})×(\frac{17}{20})}=3068.50$
$⇒\mathrm{MP×( \frac{323}{400})}=3068.50$
$⇒\mathrm{MP}=\frac{400}{323}× 3068.50$

Correct Answer: 381

Solution : Given:
I. LOAF is coded as 8362
II. LICK is coded as 5103
III. JOCK is coded as 0841
IV. JEAN is coded as 9472

By comparing all the above-coded letters, we find that –
On comparing words I and II, the common letter and

Correct Answer: LOGO

Solution : The correct answer is LOGO.

LOGO is another popular computer programming language among children. It is a text-based language, but it is intended to be simple to learn and apply. LOGO is also incredibly adaptable and can be used to build tasks, including sketching graphics,

Correct Answer: 15

Solution : Given: A boat goes 10 km upstream in 50 minutes.
The speed of the stream is 3 kmph.
Upstream speed in km/h = $\frac{10}{50}×60=12$ kmph
Let the speed of a boat in still water be $x$ kmph.
We know that,
Upstream speed = speed of

Correct Answer: Assam .

Solution : The correct option is - Assam

In the northeastern Indian state of Assam, Bihu is one of the most important festivals. 'Rongali' or 'Bohag Bihu' is observed in April, 'Kongali' or 'Kati Bihu' is observed in October or November, and 'Bhogali' or 'Magh Bihu'

Correct Answer: 6 : 11

Solution : Given,
The ratio of the area of two similar triangles = 36 : 121
If two triangles are similar, then the ratio of the area of both triangles is proportional to the square of the ratio of their corresponding sides.
⇒ $\frac{\text{(Area of

Correct Answer: An object of mass m moving with velocity v has a kinetic energy of (mv)/2.

Solution : The correct option is an object of mass m moving with velocity v has a kinetic energy of (mv)/2.

The incorrect statement asserts that the kinetic energy of an object with

Correct Answer: pounding against the windows

Solution : The most appropriate option is the third option. 

Explanation: The most appropriate option to substitute the underlined segment is pounding against the windows. This effectively conveys the intensity of the storm, as it describes the rain hitting the windows with

Correct Answer: $5\frac{1}{2}$

Solution : $\sin^{2}1^{\circ}+\sin^{2}11^{\circ}+\sin^{2}21^{\circ}+\sin^{2}31^{\circ}+\sin^{2}41^{\circ}+\sin^{2}45^{\circ}+\sin^{2}49^{\circ}+\sin^{2}59^{\circ}+\sin^{2}69^{\circ}+\sin^{2}79^{\circ}+\sin^{2}89^{\circ}$
Using the identity $\sin(90^{\circ} - \theta) = \cos\theta$, we get,
$\sin^{2}49^{\circ}=\sin^{2}(90^\circ-41^{\circ}) = \cos^2{41}^\circ$
$\sin^{2}59^{\circ}=\sin^{2}(90^\circ-31^{\circ}) = \cos^2{31}^\circ$
$\sin^{2}69^{\circ}=\sin^{2}(90^\circ-21^{\circ}) = \cos^2{21}^\circ$
$\sin^{2}79^{\circ}=\sin^{2}(90^\circ-11^{\circ}) = \cos^2{11}^\circ$
$\sin^{2}89^{\circ}=\sin^{2}(90^\circ-1^{\circ}) = \cos^2{1}^\circ$
$=\sin^{2}1^{\circ}+\sin^{2}11^{\circ}+\sin^{2}21^{\circ}+\sin^{2}31^{\circ}+\sin^{2}41^{\circ}+\sin^{2}45^{\circ}+\cos^{2}41^{\circ}+\cos^{2}31^{\circ}+\cos^{2}21^{\circ}+\cos^{2}11^{\circ}+\cos^{2}1^{\circ}$Each pair adds up to $1$ because $\sin^{2}\theta + \cos^{2}\theta = 1$
$=5+\sin^{2}45^{\circ}$
$=5+\frac{1}{2}$
$=\frac{11}{2}=5\frac{1}{2}$
Hence, the correct answer

Correct Answer:

Solution : Because there is no restriction on the rotation of the figure, we will check all possible orientations of the option figures to determine which one may fit in the question figure. By comparison of all the option figures, only the third option figure is embedded in