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Staff Selection Commission Combined Higher Secondary Level Exam

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Question : Select the option that expresses the given sentence in active voice.

Tall promises were being made by each candidate.

Option 1: Each candidate made tall promises.

Option 2: Each candidate can make tall promises.

Option 3: Each candidate has made tall promises.

Option 4: Each candidate was making tall promises.

Team Careers360 23rd Jan, 2024

Correct Answer: Each candidate was making tall promises.


Solution : The correct choice is the fourth option.

Active voice emphasises the doer of the action, while passive voice emphasises the receiver. To convert passive to active, we make the subject perform the action and rephrase the verb.

The structure of

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Question : AB is the diameter of a circle having a centre at O. PQ is a chord that does not intersect AB. Join AP and BQ. If $\angle$BAP = $\angle$ABQ, then ABQP is a:

Option 1: cyclic square

Option 2: cyclic trapezium

Option 3: cyclic rhombus

Option 4: cyclic rectangle

Team Careers360 23rd Jan, 2024

Correct Answer: cyclic trapezium


Solution :
$\angle$BAP = $\angle$ABQ and AB $\neq$ PQ
Now, $\angle$BAP + $\angle$BQP = 180°
⇒ $\angle$ABQ + $\angle$BQP = 180°
⇒ AB || PQ
So, ABQP is a cyclic trapezium.
Hence, the correct answer is cyclic trapezium.

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Question : $\frac{1}{7}$+(999$\frac{692}{693})$×99 is equal to ___.

Option 1: 1

Option 2: 99000

Option 3: 99800

Option 4: 99900

Team Careers360 23rd Jan, 2024

Correct Answer: 99000


Solution : $\frac{1}{7}$ + (999$\frac{692}{693})$×99
= $\frac{1}{7}$ + $(\frac{692999}{693})$×99
= $\frac{1}{7}$ + $(\frac{692999}{7})$
= $\frac{693000}{7}$
= 99000
Hence, the correct answer is 99000.

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Question : Directions: A series is given below with one term missing. Choose the correct alternative from the given ones that will complete the series.
TU, DE, NO, ?

Option 1: PQ

Option 2: FG

Option 3: XY

Option 4: VW

Team Careers360 23rd Jan, 2024

Correct Answer: XY


Solution : Given:
TU, DE, NO, ?

Add 10 to the positional value of each letter of the previous term to get the next term in the series.
First letter of the series→T + 10 = D; D + 10 = N; N + 10 = X

72 Views

Question : Directions: Which term from among the given options can replace the question mark (?) in the following series to make it logically complete?
BV 101, (?), DX 109, EY 113, FZ 117

Option 1: CW 105

Option 2: CV 104

Option 3: CW 106

Option 4: CV 107

Team Careers360 23rd Jan, 2024

Correct Answer: CW 105


Solution : Given:
BV 101, (?), DX 109, EY 113, FZ 117

Add 1 to the place value of the first and second letters and add 4 to the number, to obtain the next term –
BV 101→B + 1 = C; V + 1 =

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Question : The angle subtended by a chord on the major arc of the circle is 50°. What is the angle subtended by the same chord on the centre of the circle?

Option 1: 100°

Option 2: 120°

Option 3: 140°

Option 4: 25°

Team Careers360 25th Jan, 2024

Correct Answer: 100°


Solution :
The angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle.
Let O, R, and PQ be the centre, a point on the major arc, and the aforementioned chord, respectively.

113 Views

Question : Directions: In a certain code language, BED is written as 122 and CAB is written as 37. How will ADD be written in that code language?

Option 1: 65

Option 2: 50

Option 3: 101

Option 4: 82

Team Careers360 24th Jan, 2024

Correct Answer: 82


Solution : Given:
BED is written as 122 –

Find the square of the sum of the position values of the letters of the given word BED then add 1 to the resultant number to obtain the required code –
B→2; E→5; D→4
Now, find the square

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