Staff Selection Commission Combined Higher Secondary Level Exam
Question : Which of the following is responsible for fostering the development of dance, drama, and music in India?
Option 1: Lalit Kala AKademI
Option 2: Sangeet Natak AKademI
Option 3: National School of Drama
Option 4: Sahitya Academy
Correct Answer: Sangeet Natak AKademI
Solution : The correct option is Sangeet Natak Akademi.
The Sangeet Natak Akademi is the highest governing body for performing arts in India, entrusted with the responsibility of preserving and promoting the vast cultural heritage of the country expressed in music, dance, and drama. It
Question : Directions: In the following question, select the missing number from the given responses.
Option 1: 20
Option 2: 33
Option 3: 37
Option 4: 70
Correct Answer: 20
Solution : Here, the difference between the second column and the first column is equal to the third column.
Like, in the first row; 30 – 9 = 21 And, in the third row; 40 – 12 = 28 Similarly, in the third row; ? – 6
Question : Directions: Study the bar diagram and answer the question. The percentage of girls from the Biology department compared to the total number of girls from all the other Departments together is:
Option 1: $37\frac{1}{2}$
Option 2: 37
Option 3: $36\frac{1}{2}$
Option 4: $35\frac{1}{2}$
Correct Answer: $37\frac{1}{2}$
Solution : Girls in Biology = 300 Girls in all other departments = 140 + 180 + 260 + 220 = 800 Required percentage = $\frac{\text{Girl in biology}}{\text{Total girls}}\times 100$ $\therefore$ Required percentage = $\frac{300}{800}\times 100=37\frac{1}{2}$% Hence, the correct answer is $37\frac{1}{2}$.
Question : The bar graph given below shows the population of two states S1 and S2 in 5 years. Which of the following statements is correct? I. The ratio of the population of S1 to the population of S2 in the year Y1 are 3 : 1. II. The population of S1 is 140% of the population of S2 in the year Y3.
Option 1: Both I and II
Option 2: Neither I nor II
Option 3: Only II
Option 4: Only I
Correct Answer: Only II
Solution : Statement I: The ratio of the population of S1 to the population of S2 in the year Y1 are 3 : 1. From the graph, Population of S1 in Y1 = 300 Population of S2 in Y1 = 600 ⇒ Ratio = 300 :
Question : The following bar graph shows the number of theses submitted in six months.
The total submission of the theses on April 21, May 21, and June 21 is what percentage of the total submission of the theses on July 21, August 21, and Sept 21? (Rounded off to two decimal places).
Option 1: 85.17%
Option 2: 79.12%
Option 3: 70.21%
Option 4: 102.34%
Correct Answer: 85.17%
Solution : The total submission of the theses on April 21, May 21, and June 21 = 4673 + 3796 + 4151 = 12620 The total submission of the theses on July 21, August 21, and Sept 21 = 3844 + 4412 + 6562 = 14818 Required
Question : What is the total number of factors of the number 840 except 1 and the number itself?
Option 1: 29
Option 2: 30
Option 3: 28
Option 4: 31
Correct Answer: 30
Solution : Given number = 840 We can write it as, $2^3×3×5×7$ Now, Total factors $=(3+1)×(1+1)×(1+1)×(1+1)=4×2×2×2=32$ ⇒ Total number of factors apart from 1 and 840 itself = 32 – 2 = 30 Hence, the correct answer is 30.
Question : Which of the following shortcut keys is used to make the contents of a cell italic in MS Excel 365?
Option 1: Ctrl+4
Option 2: Ctrl+3
Option 3: Ctrl+6
Option 4: Ctrl+2
Correct Answer: Ctrl+3
Solution : The correct answer is Ctrl+3.
In Microsoft Excel 365, the following shortcut keys are used to make the contents of a cell italic: Ctrl+I or Ctrl+3. Simply select the cell or range of cells, the content of which is required to make italics and
Question : If $\sec 3\mathrm{A}=\operatorname{cosec}\left(\mathrm{A}-72^{\circ}\right)$, then what is the value of A ?
Option 1: 34.5°
Option 2: 30°
Option 3: 40.5°
Option 4: 25°
Correct Answer: 40.5°
Solution : $\sec 3A = \operatorname{cosec} (A - 72°)$ ⇒ $\sec 3A = \sec [90° - (A - 72°)]$ ⇒ $\sec 3A = \sec (162° - A)$ ⇒ $3A = 162° - A$ ⇒ $4A = 162°$ ⇒ $A = 40.5°$ Hence, the correct answer is 40.5°.
Question : The sum of the length and breadth of a cuboid is 4 cm. Length is three times the breadth. If the height of the cuboid is half of the sum of its length and breadth. Then what is the total surface area of the cuboid?
Option 1: 64 cm2
Option 2: 22 cm2
Option 3: 32 cm2
Option 4: 30 cm2
Correct Answer: 22 cm2
Solution : Given: The sum of length and breadth = 4 cm Length = 3 times of breadth Height = half of the sum of length and breadth Let breadth = $x$ ⇒ Length = $3x$ ⇒ Sum of length and breadth = $x +
Question : Directions: Which term from among the given options can replace the question mark (?) in the following series to make it logically complete? LT 48, ?, NV 42, OW 39, PX 36
Option 1: MU 45
Option 2: NU 44
Option 3: NS 44
Option 4: MS 46
Correct Answer: MU 45
Solution : Given: LT 48, ?, NV 42, OW 39, PX 36
In the above-given series, add 1 to the place values of the first and the second letters and subtract 3 from the number, to obtain the next term. LT 48→L + 1 = M;
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