Staff Selection Commission Combined Higher Secondary Level Exam
Question : If $\tan (90-\theta)=\frac{2}{\sqrt{3}}$, then the value of $2 \sqrt{3} \tan \theta+1$ is:
Option 1: 4
Option 2: 5
Option 3: 3
Option 4: 6
Correct Answer: 4
Solution : $\tan (90-\theta)=\frac{2}{\sqrt{3}}$ ⇒ $\cot \theta=\frac{2}{\sqrt{3}}$ ⇒ $\tan \theta=\frac{\sqrt3}{2}$ $\therefore 2 \sqrt{3} \tan \theta+1=3+1=4$ Hence, the correct answer is 4.
Question : A shopkeeper earns a profit of 20% after offering a discount of 10% on the marked price of an electric mixer. What is the cost price (in INR) of the electric mixer having a marked price of INR 6,500?
Option 1: 4,900
Option 2: 4,825
Option 3: 4,850
Option 4: 4,875
Correct Answer: 4,875
Solution : Given: The marked price of the electric mixer = INR 6,500 Discount % = 10% Selling price after getting 10% discount = $\frac{90}{100}\times 6500$ = INR 5,850 Profit = 20% ⇒ Cost price = $\frac{100}{120}×5850$ = INR 4,875 Hence, the correct answer is INR 4,875.
Question : Directions: Select the correct mirror image of the given figure when the mirror is placed at MN as shown.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : As per the mirror image properties, closer things appear closer to the mirror in the reflection. Here, according to the information provided, the mirror is placed on the right side of the figure (on line MN). So, the left side of the reflected image will appear
Question : The marked price of a saree is Rs. 200. After allowing a discount of 20% on the marked price, the shopkeeper makes a profit of Rs.16. Find the gain percentage:
Option 1: $11\frac{1}{9}$%
Option 2: $9\frac{1}{11}$%
Option 3: $11$%
Option 4: $8$%
Correct Answer: $11\frac{1}{9}$%
Solution : Selling price = 200 - 200×$\frac{20}{100}$ = Rs. 160 Cost price = Selling price – Profit = 160 – 16 = Rs. 144 Gain % = $\frac{Gain}{\text{Cost price}}×100 = \frac{16}{144}×100=\frac{100}{9}$ = $11\frac{1}{9}$% Hence, the correct answer is $11\frac{1}{9}$%.
Question : If $a+\frac{1}{a}=\sqrt{3}$, then the value of $a^{18}+a^{12}+a^{6}+1$ is:
Option 1: 0
Option 2: 1
Option 3: –1
Option 4: 4
Correct Answer: 0
Solution : Given: $a^{18}+a^{12}+a^{6}+1$ = $a^{6}(a^{12}+1)+1(a^{12}+1)$ = $(a^{6}+1)(a^{12}+1)$-----------------------------------------------(i) Now, $a+\frac{1}{a} = \sqrt{3}$ Squaring both sides, $(a+\frac{1}{a})^2 = (\sqrt{3})^2$ ⇒ $(a)^2+(\frac{1}{a})^2+2×a×\frac{1}{a} = 3$ ⇒ $(a)^2+(\frac{1}{a})^2 = 3-2 = 1$ Cubing both sides, $((a)^2+(\frac{1}{a})^2)^3 = 1^3$ ⇒ $(a)^6+(\frac{1}{a})^6+3×((a)^2+(\frac{1}{a})^2) = 1^3$ ⇒ $(a)^6+(\frac{1}{a})^6 = 1 - 3$ ⇒ $\frac{((a)^{12}+1)}{(a)^6} =
Question : Who among the following was the architect of the Integrated Guided Missile Development Program (IGMDP) in India?
Option 1: Har Gobind Khorana
Option 2: Vikram Sarabhai
Option 3: A. P. J. Abdul Kalam
Option 4: Homi J. Bhabha
Correct Answer: A. P. J. Abdul Kalam
Solution : The correct answer is A. P. J. Abdul Kalam.
The Integrated Guided Missile Development Programme (IGMDP) was created by the well-known scientist A. P. J. Abdul Kalam. The ultimate goal was to become self-sufficient in missile technology. The programme realised that
Question : Directions: Looking at the portrait of a man, Ram said, "His mother is the wife of my father's son. Brothers and sisters I have none". Whose portrait was Ram looking at?
Option 1: His grandfather
Option 2: His son
Option 3: His brother
Option 4: His cousin
Correct Answer: His son
Solution : As per the given information, the family tree will be as follows –
Here, in the above diagram, the circular figure represents the female, and the quadrilateral represents the male.
So, from the above family tree, Ram was looking at the portrait of his
Question : If the radius of a cylinder is decreased by 50% and the height is increased by 50%, then the volume change is:
Option 1: 52.5%
Option 2: 67.5%
Option 3: 57.5%
Option 4: 62.5%
Correct Answer: 62.5%
Solution : The volume of a cylinder $V = \pi r^2 h$ where $r$ is the radius and $h$ is the height. The radius of the cylinder is decreased by 50%, the new radius is, $r' = r - 0.50r = 0.50r$ The height of the cylinder
Question : Directions: DNST is related to STDN in a certain way based on a certain relationship between the given letters. In the same way, RXMK is related to MKRX. To which of the following is WBGH related to following the same logic?
Option 1: HBWG
Option 2: WGHB
Option 3: WHBG
Option 4: GHWB
Correct Answer: GHWB
Solution : Given: DNST is related to STDN and RXMK is related to MKRX DNST is related to STDN – RXMK is related to MKRX –
Similarly, WBGH is related to –
So, the code for WBGH is GHWB. Hence, the fourth option is correct.
Question : Select the option that can be used as a one-word substitute for the underlined segment.
The schedule was capable of bending easily without breaking and able to be easily modified.
Option 1: adherent
Option 2: inadaptable
Option 3: versatile
Option 4: flexible
Correct Answer: flexible
Solution : The correct choice is the fourth option.
The term flexible captures the idea that the schedule can bend easily without breaking and is easily modifiable.
Flexible: It describes the quality of being adaptable and able to change or adjust easily in response to different circumstances.
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