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Staff Selection Commission Combined Higher Secondary Level Exam

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Question : Directions: In a certain code language, SAGE is coded as –8, and TABS is coded as 0. What is the code for VERB in that code language?

Option 1: –7

Option 2: 4

Option 3: –4

Option 4: 7

Team Careers360 23rd Jan, 2024

Correct Answer: –7


Solution : ​Given:
SAGE is coded as –8, TABS is coded as 0.

Subtract the sum of the place values of the first two letters from the sum of the place values of the last two letters of SAGE, to obtain the required code –
S +

21 Views

Question : Shailja allows a discount of 10% to her customers and still gains 20% on the sale of a cosmetic product. What is the marked price (in Rs.) of the cosmetic product having a cost price of Rs. 450?

Option 1: 580

Option 2: 560

Option 3: 600

Option 4: 540

Team Careers360 20th Jan, 2024

Correct Answer: 600


Solution : Here SP denotes the selling price, CP denotes the cost price, and MP denotes the marked price.
Let MP be Rs. 100.
Discount = 10% of MP = $\frac{10}{100}​ ​\times 100$ = Rs. 10
SP = MP − Discount = 100 − 10 = Rs.

47 Views

Question : Two trains X and Y start from Jodhpur to Jaipur and from Jaipur to Jodhpur, respectively. After passing each other they take 4 hours 48 minutes and 3 hours 20 minutes to reach Jaipur and Jodhpur, respectively. If X is moving at 45 km/hr, the speed of Y is:

Option 1: 60 km/hr

Option 2: 58 km/hr

Option 3: 54 km/hr

Option 4: 64.8 km/hr

Team Careers360 17th Jan, 2024

Correct Answer: 54 km/hr


Solution : We know,
$\frac{\text{Speed of X}}{\text{Speed of Y}}=\sqrt{\frac{\text{Time taken by Y after crossing X}}{\text{Time taken by X after crossing Y}}}$
$⇒\frac{45}{\text{Speed of Y}}=\sqrt{\frac{\text{3 hour 20 min}}{\text{4 hour 48 min}}}=\sqrt{\frac{\text{200 min}}{\text{288 min}}}=\sqrt{\frac{100}{144}}$
$⇒\frac{45}{\text{Speed of Y}}=\frac{10}{12}$
$\therefore \text{Speed of Y}=54$ km/hr
Hence, the correct answer is 54

45 Views

Question : Parts of the following sentence are given as options. Identify the part that contains a grammatical error. If there is no error, select 'No Error'.

You never know when / you are going to stumble to a / jewel in the most unexpected corner.

Option 1: You never know when

Option 2: you are going to stumble to a

Option 3: jewel in the most unexpected corner.

Option 4: No Error

Team Careers360 20th Jan, 2024

Correct Answer: you are going to stumble to a


Solution : The error lies in the second option.

The preposition to is incorrect in this context. The correct idiom is stumble upon, which means to discover or find something unexpectedly. So, the phrase should be stumble upon a

12 Views

Question : Directions: In the following question, out of the four alternatives, select the alternative that will improve the bracketed part of the sentence. In case no improvement is needed, select "No Improvement."

The offerings were placed (on the alter).

(1) on the altar

(2) on the steps.

(3) on the platform.

(4) No improvement

Option 1: (1)

Option 2: (2)

Option 3: (3)

Option 4: (4)

Team Careers360 25th Jan, 2024

Correct Answer: (1)


Solution : The sentence can be improved using the first option "on the altar."

An "altar" is a raised platform or table used in religious ceremonies for making offerings or sacrifices. Therefore, when describing where the offerings were placed, "on the altar" is the appropriate phrase to

21 Views

Question : If $0^{\circ}< \theta< 90^{\circ}$ and $\operatorname{cosec \theta} =\cot^{2}\theta$, then the value of expression $\operatorname{cosec^{4}\theta}–\operatorname{2cosec^{2}\theta}-\cot^{2}\theta$ is equal to:

Option 1: $2$

Option 2: $0$

Option 3: $1$

Option 4: $3$

Team Careers360 24th Jan, 2024

Correct Answer: $0$


Solution : $\operatorname{cosec \theta} =\cot^{2}\theta$
$⇒\operatorname{cosec \theta} = \operatorname{cosec^2 \theta} -1$
Squaring both sides, we get,
$⇒\operatorname{cosec^2 \theta} =\operatorname{cosec^4 \theta} -2\operatorname{cosec^2 \theta} +1$
$⇒\operatorname{cosec^4 \theta} -3\operatorname{cosec^2 \theta} +1=0$
$⇒\operatorname{cosec^4 \theta} -3\operatorname{cosec^2 \theta} +\operatorname{cosec^2 \theta} -\cot^2\theta =0$ [$\because1 = \operatorname{cosec^2 \theta}-\cot^2\theta$]
$⇒\operatorname{cosec^4 \theta} -2\operatorname{cosec^2 \theta}  -\cot^2\theta =0$
Hence,

9 Views

Question : Red soil found in India in which regions?

Option 1: Eastern Region only

Option 2: Southern Region only

Option 3: Eastern and Southern part of the Deccan Plateau

Option 4: None of these

Team Careers360 17th Jan, 2024

Correct Answer: Eastern and Southern part of the Deccan Plateau


Solution : The correct answer is the Eastern and Southern parts of the Deccan Plateau.

Red soil is made up of an alluvium red layer, a thin layer of highly organic and organic-mineral soil and a lot of clay. This

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