Staff Selection Commission Combined Higher Secondary Level Exam
Question : Directions: In the following question, a series is given, with one term missing. Choose the correct alternative from the given ones that will complete the series. AC, EG, IK, ?
Option 1: LM
Option 2: ON
Option 3: OP
Option 4: MO
Correct Answer: MO
Solution : Given: AC, EG, IK, ?
Add four to the place value of each letter to get the next term – AC; A (1) + 4 = E, C (3) + 4 = G→EG EG: E (5) + 4 = I, G (7) + 4 =
Question : The surface area of a sphere is 616 cm2. The volume of the sphere would be:
Option 1: $1437\frac{1}{3}$ cm3
Option 2: $2100$ cm3
Option 3: $2500$ cm3
Option 4: $1225\frac{3}{5}$ cm3
Correct Answer: $1437\frac{1}{3}$ cm3
Solution : Given: The surface area of a sphere = 616 cm$^2$ We know that, The surface area of a sphere of radius $r$ = $4\pi r^2$ ⇒ $4\pi r^2$ = 616 ⇒ $4×\frac{22}{7}× r^2$ = 616 ⇒ $r^2 = \frac{616×7}{4×22}= 49$ ⇒ $r =
Question : Which experiment was designed to trace the motion of the earth through the 'luminiferous aether', a theoretical substance necessary for the transmission of light?
Option 1: Maxwell and Hertz's experiment
Option 2: Faraday and Henry's experiment
Option 3: Michelson-Morley's experiment
Option 4: Marconi and Thomson's experiment
Correct Answer: Michelson-Morley's experiment
Solution : The correct option is Michelson-Morley's experiment.
The goal of the Michelson-Morley experiment was to determine how quickly the earth moved about the luminiferous aether, which was believed to be a medium that permeated space and carried light waves. Albert Michelson and Edward Morley
Question : A hemispherical dome of a building needs to be painted. If the circumference of the base of the dome is 154 cm, then find the cost of painting it if the cost of painting is INR 4 per 100 cm2. (Use$ ~\pi=\frac{22}{7}$).
Option 1: INR 150.92
Option 2: INR 150.66
Option 3: INR 105.29
Option 4: INR 105.66
Correct Answer: INR 150.92
Solution : Let $R$ be the radius. Circumference of the base of the dome = 154 cm $⇒2\pi R$ = $154$ $⇒R$ = $\frac{154×7}{2×22}$ = $\frac{49}{2}$ cm Surface area of hemispherical dome = $2\pi R^2$ = $2\pi R×R$ = $154×\frac{49}{2}$ = $3773$ cm2 Cost of
Question : In what ratio does a grocer mix tea at INR 26 per kg and INR 32 per kg so that by selling the mixture at INR 30 per kg he may gain 10%?
Option 1: 7 : 26
Option 2: 16 : 7
Option 3: 26 : 7
Option 4: 7 : 16
Correct Answer: 26 : 7
Solution : Given: A grocer mixes tea at INR 26 per kg and INR 32 per kg so that by selling the mixture at INR 30 per kg he may gain 10%. Selling price = INR 30 per kg and gain = 10%. So, the
Question : Two triangles XYZ and UVW are congruent. If the area of $\triangle$XYZ is 58 cm2, then the area of $\triangle$UVW will be:
Option 1: 58 cm2
Option 2: 116 cm2
Option 3: 29 cm2
Option 4: 15 cm2
Correct Answer: 58 cm2
Solution : Two triangles XYZ and UVW are congruent. The area of $\triangle$XYZ is 58 cm2. We know, The areas of two congruent triangles are equal. Hence, the correct answer is 58 cm2.
Question : Two circles touch each other internally. Their radii are 3 cm and 4 cm. What is the length of the biggest chord of the circle with radii of 4 cm which is outside the inner circle?
Option 1: $5 \sqrt{3} \mathrm{~cm}$
Option 2: $6 \sqrt{3} \mathrm{~cm}$
Option 3: $4 \sqrt{3} \mathrm{~cm}$
Option 4: $2 \sqrt{3} \mathrm{~cm}$
Correct Answer: $2 \sqrt{3} \mathrm{~cm}$
Solution : From the figure, MN is the diameter of the smaller circle and PQ is the biggest chord of the greater circle. O is the centre of the greater circle and O' is the centre of the inner circle. Now, OM = MN –
Question : The ratio of three numbers is 3 : 6 : 8. If their product is 9216, then what is the sum of the three numbers?
Option 1: 96
Option 2: 72
Option 3: 144
Option 4: 68
Correct Answer: 68
Solution : Given: The ratio of three numbers is 3 : 6 : 8. Their product is 9216. Let the numbers be $3k, 6k$, and $8k$. Product of $3k × 6k × 8k = 9216$ ⇒ $144k^{3}=9216$ ⇒ $k^{3}=\frac{9216}{144}$ ⇒ $k=\sqrt[3]{64}$ ⇒ $k=4$ The sum of the
Question : Which of the following statements is/are not correct? I. The property of metals by which they can be beaten into thin sheets is called malleability. II. The property of metals by which they can be drawn into wires is called ductility.
Option 1: Neither I nor II
Option 2: Both I and II
Option 3: Only I
Option 4: Only II
Correct Answer: Neither I nor II
Solution : The correct answer is Neither I nor II.
Malleability is the property of the metals in which it can be beaten into thin sheets. Gold is the most malleable metal. Ductility is the property of the metals in which it can
Question : Directions: In the following question, some parts of the sentence may have some errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No Error".
Had the plane not been delayed, (1) / I will reach here (2) / in time for the function. (3) / No Error (4)
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (2)
Solution : The error lies in the second part of the sentence.
The third conditional is applied here. In the conditional clause, the past perfect tense is used, which is to be followed by the past form of modal + have + past participle form of the
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