Correct Answer: 37

Solution : In the diagram, the shaded part represents the region of teachers.

Therefore, the total number of teachers→16 + 4 + 8 + 9 = 37

So, from the above, the total number of teachers is 37. Hence, the fourth option is correct.

Correct Answer: 752

Solution : Given:
2 × 3 × 4 = 432; 5 × 6 × 7 = 765; 7 × 8 × 9 = 987

The second number remains at the second position while the first and third numbers swap positions.
Like, 2 × 3 × 4 =

Correct Answer: aimlessly

Solution : The fourth option is the correct answer.

The word aimlessly is the most appropriate choice in this context because it conveys that Purush was wandering without a clear purpose or direction in life.

So, the correct sentence is: Puresh wandered aimlessly through life, with no

Correct Answer: Article 51A(b)

Solution : The correct answer is Article 51A(b).

Fundamental duties are mentioned in Part 4A of Article 51A of the Indian Constitution. 11 fundamental duties are mentioned in the Constitution. Article 51A(b) states that we must cherish and follow the noble ideals that inspired our

Correct Answer: GB 23

Solution : Given:
EZ 10, ?, ID 36, KF 49, MH 62

Add 2 in the positional value of each letter and add 13 to each number of the previous term to get the next term –
EZ 10→E + 2 = G; Z + 2

Correct Answer: INR 5,795$\frac{5}{9}$

Solution : Let, the A pay for the mobile phone be $x$.
A sold the item to B at a gain of 25%
⇒ the cost price for B is $x$ + 25% of $x = x+\frac{x}{4}=\frac{5x}{4}$.
B sold the item to C at a loss

Correct Answer: 2,155.0625

Solution : Given, Principal, $P=\mathrm{INR\ }10000,$ Rate, $r=10\%=0.10,$
As it compounded half-yearly, the time will be 2 × 2 = 4 years
$\text{Total Amount, A}=\text{Principal}×(1+\frac{\text{Rate}}{100})^{\text{Time}}$
⇒ $A=10000(1+\frac{\frac{10}{100}}{2})^{4}$
⇒ $A=10000(\frac{21}{20})^4$
⇒ $A=10000×\frac{441}{400}×\frac{441}{400}$
$\therefore A=12155.0625$
Now, Compound interest = Total amount – Principal = 12155.0625 – 10000 = INR

Correct Answer: 3842

Solution : $(a + \frac{1}{a}) = 8$
Squaring both sides, we get,
⇒ $ (a^2 + \frac{1}{a^2}) + 2 = 64$
⇒ $(a^2 + \frac{1}{a^2}) = 62$
Squaring both sides again, we get,
⇒ $a^4 + \frac{1}{a^4} + 2 = 3844$
⇒ $a^4 + \frac{1}{a^4} = 3844

Correct Answer: 2

Solution : Given:
$\frac{\operatorname{sin} 58^{\circ}}{\cos 32^{\circ}}+\frac{\sin 55^{\circ} \sec 35^{\circ}}{\tan 5^{\circ} \tan 45^{\circ} \tan 85^{\circ}}$
 $=\frac{\operatorname{sin} 58^{\circ}}{\cos (90^{\circ}-58^{\circ})}+\frac{\sin 55^{\circ} \cot 5^{\circ}}{\cos 35^{\circ} \tan 45^{\circ} \tan 85^{\circ}}$
 $=\frac{\operatorname{sin} 58^{\circ}}{\operatorname{sin} 58^{\circ}}+\frac{\sin 55^{\circ} \cot (90^{\circ}-85^{\circ})}{\cos (90^{\circ}-55^{\circ}) \tan 45^{\circ} \tan 85^{\circ}}$
$= 1+\frac{\sin 55^{\circ} \tan 85^{\circ}}{\sin 55^{\circ} \tan 45^{\circ} \tan 85^{\circ}}$
 $=1+\frac{1}{

Correct Answer: 1435

Solution : Given: 1440 – 200 ÷ 50 × 2 + 3
= 1440 – 4 × 2 + 3
= 1440 – 8 + 3
= 1435
Hence, the correct answer is 1435.