Staff Selection Commission Combined Higher Secondary Level Exam
Question : AC is the diameter of the circle. B is a point on the circumference. If $\angle$BAC is 40°, then what is $\angle$BCA?
Option 1: 50°
Option 2: 90°
Option 3: 55°
Option 4: 40°
Correct Answer: 50°
Solution : Given that AC is the diameter of the circle, B is a point on the circumference, and $\angle$ BAC = 40° In $\triangle$ABC, $ \angle$ BAC + $\angle$ ABC + $\angle $BCA = 180° ⇒ 40° + 90° + $\angle $BCA = 180° ⇒ $
Question : A cellulose wall is found in the cells of:
Option 1: Animals
Option 2: Bacteria
Option 3: Fungi
Option 4: Plants
Correct Answer: Plants
Solution : The correct option is Plants.
Cellulose cell walls are typically found in the cells of plants. Cellulose is a complex carbohydrate and the primary structural component of plant cell walls. It provides strength and rigidity to plant cells, allowing them to maintain their shape
Question : Directions: In the following question, a series is given, with one term missing. Choose the correct alternative from the given ones that will complete the series. AFKPU, BGLQV, CHMRW, ?
Option 1: VQLGB
Option 2: DINSX
Option 3: KLMNO
Option 4: UVWXY
Correct Answer: DINSX
Solution : Given: AFKPU, BGLQV, CHMRW, ?
Add 1 to the place value of each letter of the previous term to obtain the next term in the series – AFKPU→A + 1 = B; F + 1 = G; K + 1 = L; P + 1
Question : The name of Ustad Vilayat Khan is associated with which of the following Indian musical instruments?
Option 1: Santoor
Option 2: Sitar
Option 3: Bansuri
Option 4: Tabla
Correct Answer: Sitar
Solution : The correct answer is Sitar.
Ustad Vilayat Khan, an Indian classical sitarist who lived from August 28, 1928, to March 13, 2004, is regarded by many as the best sitarist of his generation. Among sitar players, he became a pioneer and an inspiration when he
Question : Directions: In the following question, find the odd letter cluster from the given alternatives.
Option 1: DCBA
Option 2: HGFE
Option 3: PONM
Option 4: IJKL
Correct Answer: IJKL
Solution : Let's check the options –
First option: DCBA; D – 1 = C; C – 1 = B; B – 1 = A Second option: HGFE; H – 1 = G; G – 1 = F; F – 1 = E Third option: PONM; P
Question : In what ratio, wheat at INR 23 per kg should be mixed with wheat at INR 14 per kg so that on selling the mixture at INR 20 per kg there is a profit of 25%?
Option 1: 5 : 7
Option 2: 3 : 5
Option 3: 2 : 3
Option 4: 2 : 7
Correct Answer: 2 : 7
Solution : Let the quantity of wheat priced INR 23 be $x$ kg and the quantity of wheat priced INR 14 be $y$ kg. According to the question, $\frac{100+25}{100}×(23x+14y)=20(x+y)$ $⇒23x+14y=16x+16y$ $⇒7x=2y$ $\therefore \frac{x}{y}=\frac{2}{7}$ Hence, the correct answer is 2 : 7.
Question : Directions: In the following question, some parts of the sentence may have some errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No Error".
If she had seen (1) / the car coming. she (2) / may not crossed the road. (3) / No Error (4)
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (3)
Solution : The error lies in the third part of the sentence.
The phrase "may not crossed" is incorrect due to the wrong use of the tense form. In this case, the action of seeing the car happened before the action of crossing the road. Hence, the
Question : If the demand curve is a racing cycle, D = 80200 - 13P, and the supply curve is S = 6200 + 12P, what is the equilibrium quantity?
Option 1: 2960 units
Option 2: 31220 units
Option 3: 8750 units
Option 4: 41720 units
Correct Answer: 41720 units
Solution : The correct option is 41720 units.
Demand (D) = 80200 - 13P,
Supply (S) = 6200 + 12P
For the equilibrium position,
Demand (D) should be equal to Supply (S)
80200 - 13P = 6200 + 12P
80200 - 6200 = 13P + 12P
Question : Directions: Select the option that is related to the fifth number in the same way as the first number is related to the second number and the third number is related to the fourth number. 7 : 512 :: 11 : 1728 :: 10 : ?
Option 1: 1331
Option 2: 2197
Option 3: 1397
Option 4: 1133
Correct Answer: 1331
Solution : Given: 7 : 512 :: 11 : 1728 :: 10 : ?
The pattern is as follows – 7 : 512→7 + 1 = 8; (8)³ = 512 11 : 1728→11 + 1 = 12; (12)³ = 1728 Similarly, follow the same pattern for 10
Question : Directions: In the following question, select the one which is different from the other three alternatives.
Option 1: 101
Option 2: 121
Option 3: 111
Option 4: 131
Correct Answer: 121
First option: 101; This is not a perfect square. Second option: 121; This is a perfect square. Third option: 111; This is not a perfect square. Fourth option: 131; This is not a perfect square.
So, the second option is
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