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Staff Selection Commission Combined Higher Secondary Level Exam

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Question : A rides his bicycle at 15 km/hr, while B starts his ride after 6 hours to catch A at a speed of 25 km/hr. Time taken by B to catch A (in hours) is:

Option 1: 9

Option 2: 8

Option 3: 10

Option 4: 6

Team Careers360 24th Jan, 2024

Correct Answer: 9


Solution : Distance travelled by A = Speed × Time
So, Distance = 15 × 6 = 90 km
Relative speed of B to A = Speed of B – Speed of A
Relative speed = (25 – 15) km/hr = 10 km/hr
Time taken by B

42 Views

Question : Directions: In a certain code language, GRATEFUL is coded as 209267562112, and INSTANCE is coded as 18138711435. What is the code for LIKEWISE in that code language?

Option 1: 15181622239195

Option 2: 15181623339195

Option 3: 15161822238195

Option 4: 15811622239195

Team Careers360 15th Jan, 2024

Correct Answer: 15181622239195


Solution : Given:
GRATEFUL is coded as 209267562112, and INSTANCE is coded as 18138711435.

Divide the given word into two equal parts and then write the position values of the first half-term from the last and the second half-term from the beginning of the alphabetical series to

13 Views

Question : If the height of the equilateral triangle is $2 \sqrt 3\:\operatorname{cm}$, then determine the area of the equilateral triangle.

Option 1: $6\:\operatorname{cm^2}$

Option 2: $2\sqrt3\:\operatorname{cm^2}$

Option 3: $4\sqrt3\:\operatorname{cm^2}$

Option 4: $12\:\operatorname{cm^2}$

Team Careers360 24th Jan, 2024

Correct Answer: $4\sqrt3\:\operatorname{cm^2}$


Solution : In an equilateral triangle, the height $(h)$ is related to the side length $(a)$,
$h = \frac{\sqrt{3}}{2}a$
Given that the height of the equilateral triangle is $2\sqrt{3}\:\text{cm}$.
⇒ $2\sqrt{3} = \frac{\sqrt{3}}{2}a$
⇒ $a = \frac{2\sqrt{3} \times 2}{\sqrt{3}} = 4\:\text{cm}$
The area $(A)$ of an equilateral

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Question : Which among the following won the best film (critics) award in the 67th Filmfare Awards 2022?

Option 1: Sherni

Option 2: Sardar Udham 

Option 3: Sandeep Aur Pinky Faraar

Option 4: Ramprasad ki Tehrvi

Team Careers360 24th Jan, 2024

Correct Answer: Sardar Udham 


Solution : The correct answer is Sardar Udham.

The 67th Filmfare Awards, hosted by The Times Group, celebrated outstanding achievements in Indian Hindi-language cinema for 2021. "Sardar Udham" dominated with nine wins, clinching accolades such as Best Film (Critics) and Best Actor (Critics) for Vicky Kaushal.

52 Views

Question : The population of the village was 12,000 two years ago. If it increased by 2.5% and 3%, respectively, in the last two years, then what is the present population of the village?

Option 1: 12,669

Option 2: 12,607

Option 3: 12,652

Option 4: 12,731

Team Careers360 8th Jan, 2024

Correct Answer: 12,669


Solution : The population of a village two years ago = 12,000
Percentage increase in each year = 2.5% and 3%
$\therefore$ Current population $=12000 × \frac{102.5}{100} × \frac{103}{100} = 12669$
Hence, the correct answer is 12669.

17 Views

Question : Newton's first law is also known as:

Option 1: Law of friction

Option 2: Law of momentum

Option 3: Law of inertia

Option 4: Law of motion

Team Careers360 22nd Jan, 2024

Correct Answer: Law of inertia


Solution : The correct option is the Law of inertia.

Newton's first law is also known as the law of inertia, highlighting the tendency of objects to maintain their state of motion or rest unless influenced by an external force. Newton's Second Law: Force

159 Views

Question : After giving a 10 percent discount on an article there is still a profit of 10 percent. What will be the profit percentage when no discount is given?

Option 1: 22.22 percent

Option 2: 25 percent

Option 3: 16.66 percent

Option 4: 26.88 percent

Team Careers360 12th Jan, 2024

Correct Answer: 22.22 percent


Solution : Let the marked price (MP) be Rs. 100.
Selling price after 10% discount (SP) = 100 – 10 = Rs. 90
Cost price = Selling price $×\frac{100}{(100+ \text{Profit})\%}$
 = $\frac{90×100}{100+ 10}$
 = $\frac{900}{11}$
Required profit percent without discount
= $\frac{100-\frac{900}{11}}{\frac{900}{11}}\times 100$
= $\frac{2}{9}\times 100$

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