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Staff Selection Commission Multi Tasking Staff Exam

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Question : Fill in the blank with the most appropriate option.
They were_____ there when Janvi heard something large and heavy collide with the door.

Option 1: much

Option 2: most

Option 3: about

Option 4: almost

Team Careers360 24th Jan, 2024

Correct Answer: almost


Solution : The fourth option is the correct choice.

Almost is suitable in this context, as it indicates that they were very close to reaching their destination when Janvi heard the noise. It conveys a sense of proximity or nearness to the location they were heading towards.

13 Views

Question : Directions: Which of the following diagrams represents the relationship between Hockey, Cricket, and Games?

Option 1:

Option 2:

Option 3:

Option 4:

Team Careers360 24th Jan, 2024

Correct Answer:


Solution : We know that both hockey and cricket are games. So, the circles representing hockey and cricket will lie inside the circle representing games. But, hockey and cricket are not related to each other. So, their circles will not have a common area.
The Venn diagram will

19 Views

Question : If $A=\frac{2}{3}+\frac{4}{7}$ of $\frac{14}{12}$ and $B=\frac{5}{12}$ of $\frac{7}{15} \times \frac{36}{21}$, then what is the value of $A + B$?

Option 1: $\frac{5}{3}$

Option 2: $2$

Option 3: $\frac{4}{3}$

Option 4: $\frac{2}{3}$

Team Careers360 25th Jan, 2024

Correct Answer: $\frac{5}{3}$


Solution : $A=\frac{2}{3}+\frac{4}{7}$ of $\frac{14}{12}$
$=\frac{2}{3}+\frac{4}{7}\times\frac{14}{12}$
$=\frac{4}{3}$
$B=\frac{5}{12}$ of $\frac{7}{15} \times \frac{36}{21}$
$=\frac{5}{12}\times\frac{7}{15} \times \frac{36}{21}$
$=\frac{1}{3}$
$⇒ A + B =\frac{4}{3}+\frac{1}{3}= \frac{5}{3}$
Hence, the correct answer is $\frac{5}{3}$.

11 Views

Question : If ${P}_1, {P}_2$, and ${P}_3$ are three distinct prime numbers, then what is the least common multiple of ${P}_1, {P}_2$, and ${P}_3$ ?

Option 1: $P_1$

Option 2: $P_1 \times P_2 \times P_3$

Option 3: $P_2 \times P_3$

Option 4: ${P}_1+{P}_2+{P}_3$

Team Careers360 25th Jan, 2024

Correct Answer: $P_1 \times P_2 \times P_3$


Solution : The least common multiple (LCM) of three distinct prime numbers, P1, P2, and P3, is simply their product, $P_1 \times P_2 \times P_3$.
To see why, we can use the fact that the LCM of any set of numbers is the

12 Views

Question : If two successive discounts of 10% and 20% are offered, then what is the net discount?

Option 1: 22%

Option 2: 28%

Option 3: 25%

Option 4: 20%

Team Careers360 25th Jan, 2024

Correct Answer: 28%


Solution : Single equivalent discount = $(a+b-\frac{a×b}{100}$)%, where $a$% and $b$% are successive discounts.
Here, $a =10,b=20$
So, Single equivalent discount = $10+20-\frac{10×20}{100}=28$%
Hence, the correct answer is 28%.

25 Views

Question : The selling price of an article is Rs. 817. If the loss percentage is 14%, then what is the cost price of the article?

Option 1: Rs. 850

Option 2: Rs. 950

Option 3: Rs. 880

Option 4: Rs. 900

Team Careers360 25th Jan, 2024

Correct Answer: Rs. 950


Solution : Let's denote the cost price of the article as $C$.
The selling price ($SP$) is given as Rs. 817, and the loss percentage is 14%
Loss Percentage = $\frac{\text{Cost Price – Selling Price}}{\text{Cost Price}}×100$
Given that the loss percentage is 14%.
So, $14 =

20 Views

Question : Directions: In the following question, select the one which is different from the other three alternatives.

Option 1: 14 – 49 

Option 2: 16 – 64 

Option 3: 20 – 100

Option 4: 24 – 121

Team Careers360 24th Jan, 2024

Correct Answer: 24 – 121


Solution : Let's check the options –
First option: 14 – 49; (14 ÷ 2)2 = (7)2 = 49
Second option: 16 – 64; (16 ÷ 2)2 = (8)2 = 64
Third option: 20 – 100; (20 ÷ 2)=

10 Views

Question : Select the number that will come in place of the question mark (?) in the following mathematical statement.
$\left(9^2 \times 27+3^3 \times 7+?\right)^{\frac{1}{2}}=59$

Option 1: 1087

Option 2: 1105

Option 3: 1111

Option 4: 1090

Team Careers360 25th Jan, 2024

Correct Answer: 1105


Solution : $\left(9^2 \times 27+3^3 \times 7+?\right)^{\frac{1}{2}}=59$
⇒ $9^2 \times 27+3^3 \times 7+? = 59^2$
⇒ $81 \times 27+27 \times 7+? = 3481$
⇒ $2187+189+? = 3481$
⇒ $? = 3481-2187-189 = 1105$
Hence, the correct answer is 1105.

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