Staff Selection Commission Multi Tasking Staff Exam
Question : What will be the HCF of 54 and 48?
Option 1: 4
Option 2: 7
Option 3: 6
Option 4: 8
Correct Answer: 6
Solution : HCF is the highest common factor. 48 = 2 × 2 × 2 × 2 × 3 54 = 2 × 3 × 3 × 3 The HCF of 54 and 48 = 2 × 3 = 6 Hence, the correct answer is 6.
Question : Which of the following cell organelles are not present in animal cells?
Option 1: Ribosomes
Option 2: Plastids
Option 3: Lysosomes
Option 4: Mitochondria
Correct Answer: Plastids
Solution : The correct option is Plastids.
Plastids are membrane-bound organelles found in plant cells and some algae. They encompass chloroplasts, which are crucial for photosynthesis. Animal cells lack plastids but contain other organelles, such as mitochondria for energy production and lysosomes for cellular digestion. The
Question : Identify the segment that contains a grammatical error. If there is no error, select 'No Error'.
He best understand that / because of the fight it is no / longer his decision to make.
Option 1: He best understand that
Option 2: longer his decision to make.
Option 3: because of the fight it is no
Option 4: No Error
Correct Answer: He best understand that
Solution : The correct choice is the first option.
To maintain a proper subject-verb agreement, we have to use "understands" with the pronoun "he".
Therefore, the correct sentence will be: "He best understands that because of the fight, it is no longer his decision
Question : Directions: What will be the value of the following expression, if × and – are interchanged and + and ÷ are interchanged? 200 ÷ 100 × 300 ÷ 200 + 10 – 2 × 40 = ?
Option 1: 200
Option 2: 2
Option 3: 40
Option 4: 0
Correct Answer: 0
Solution : Given: 200 ÷ 100 × 300 ÷ 200 + 10 – 2 × 40 = ?
On interchanging the mathematical signs, we get – = 200 + 100 – 300 + 200 ÷ 10 × 2 – 40 = 200 + 100 – 300 +
Question : The cost price of 50 articles is the same as the selling price of $x$ articles. If there is a profit of 25 percent, then what is the value of $x$?
Option 1: 20
Option 2: 40
Option 3: 30
Option 4: 25
Correct Answer: 40
Solution : Let the cost price of one article be C and the selling price of one article be S. Given that the cost price of 50 articles is the same as the selling price of $x$ articles. ⇒ 50 × C = $x$ × S It's
Question : A can do a piece of work in 30 days while B can do it in 40 days. How many days can A and B when working together do it?
Option 1: $42\frac{3}{4}$ days
Option 2: $27\frac{1}{7}$ days
Option 3: $17\frac{1}{7}$ days
Option 4: $70$ days
Correct Answer: $17\frac{1}{7}$ days
Solution : Given: A can do a piece of work in 30 days while B can do it in 40 days. (A + B)'s work in 1 day $=\frac{1}{30} + \frac{1}{40}=\frac{4+3}{120} = \frac{7}{120}$ $\therefore$ (A + B) can complete the work in $=\frac{120}{7} = 17\frac{1}{7}$ days
Question : Directions: Five friends Aman, Biraj, Chaman, Sourav, and Rajesh are searing around a circular table facing the centre. Aman is to the immediate right of Chaman who is second to the right of Sourav. Biraj is to the immediate left of Chaman. Who is second to the right of Aman?
Option 1: Chaman
Option 2: Biraj
Option 3: Sourav
Option 4: Rajesh
Correct Answer: Sourav
Solution : Given: 1. Aman is to the immediate right of Chaman who is second to the right of Sourav. 2. Biraj is to the immediate left of Chaman.
From the above-given information, the following seating arrangement can be drawn – All of them are sitting around
Question : What is the value of $\frac{5}{12} \times \frac{7}{12} \div\left(\frac{1}{75}+\frac{5}{12}\right.$ of $\left.\frac{36}{25}\right)+\frac{4}{5} \times \frac{75}{16} ?$
Option 1: $\frac{8305}{1104}$
Option 2: $\frac{4675}{1104}$
Option 3: $\frac{2565}{2208}$
Option 4: $\frac{9155}{2208}$
Correct Answer: $\frac{9155}{2208}$
Solution : Given expression, $\frac{5}{12} \times \frac{7}{12} \div\left(\frac{1}{75}+\frac{5}{12}\right.$ of $\left.\frac{36}{25}\right)+\frac{4}{5} \times \frac{75}{16}$ Using the BODMAS Rule, B – Brackets, O – Of, D – Division, M – Multiplication A – Addition, and S – Subtraction = $\frac{5}{12}\times\frac{7}{12}\div(\frac{1}{75}+\frac{5}{12}\times\frac{36}{25})+\frac{4}{5}\times\frac{75}{16}$ = $\frac{5}{12}\times\frac{7}{12}\div(\frac{1}{75}+\frac{5\times3}{25})+\frac{4}{5}\times\frac{75}{16}$ = $\frac{5}{12}\times\frac{7}{12}\div(\frac{1}{75}+\frac{15}{25})+\frac{4}{5}\times\frac{75}{16}$ = $\frac{5}{12}\times\frac{7}{12}\div(\frac{1+45}{75})+\frac{4}{5}\times\frac{75}{16}$ = $\frac{5}{12}\times\frac{7}{12}\div\frac{46}{75}+\frac{4}{5}\times\frac{75}{16}$ = $\frac{5}{12}\times\frac{7}{12}\times\frac{75}{46}+\frac{4}{5}\times\frac{75}{16}$
Question : The pie chart given below shows the number of boys in 8 schools. The total number of boys in all these 8 schools is 8000. The number of boys in a particular school is shown as a percent of the total number of boys in all these 8 schools. What is the sum of the average number of boys in P, R, T, and W and the average number of boys in Q and V?
Option 1: 2580
Option 2: 2180
Option 3: 2380
Option 4: 1980
Correct Answer: 2380
Solution : The total number of boys in all these 8 schools is 8000. Number of boys in school P = $\frac{7}{100}×8000=560$ Number of boys in school R = $\frac{8}{100}×8000=640$ Number of boys in school T = $\frac{17}{100}×8000=1360$ Number of boys in school W = $\frac{3}{100}×8000=240$ The
Question : Comprehension: In the following passage some words have been deleted. Fill in the blanks with the help of the alternatives given. Select the most appropriate option for each number.
Professor Sprout was standing (1) ____ a trestle bench in the centre of the greenhouse. (2)_____ twenty (3) ____ of different-coloured ear muffs (4) ______ lying on the bench. Harry (5) _____ his place between Ron and Hermione. Question: Select the most appropriate option to fill in blank number 4.
Option 1: lay
Option 2: was
Option 3: were
Option 4: continue
Correct Answer: were
Solution : The correct choice is the third option.
Explanation: When the subject is plural, the verb must also be plural to maintain grammatical correctness. In this sentence, "twenty pairs of different-coloured ear muffs" serve as the subject. The word "pairs" indicates a plurality, and therefore,
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