Staff Selection Commission Sub Inspector Exam
Question : Directions: In the following question, a sentence is given with a blank that is to be filled in with an appropriate word. Four alternatives are suggested; choose the correct alternative out of them as your answer.
Rohan yelled ______ her, and she hastily retreated.
Option 1: towards
Option 2: to
Option 3: on
Option 4: at
Correct Answer: at
Solution : The fourth option is the correct choice.
Therefore,
Question : What is the value of m in the quadratic equation $x^{2}+mx+24=0$, if one of its roots is $\frac{3}{2}$.
Option 1: $–\frac{45}{2}$
Option 2: $16$
Option 3: $–\frac{21}{2}$
Option 4: $–\frac{35}{2}$
Correct Answer: $–\frac{35}{2}$
Solution : Given: $x^{2}+mx+24=0$ One of its roots is $\frac{3}{2}$. Putting $x=\frac{3}{2}$ into the equation, we have, $(\frac{3}{2})^{2}+m(\frac{3}{2})+24=0$ ⇒ $\frac{9}{4}+\frac{3m}{2}+24=0$ ⇒ $\frac{3m}{2}=–(\frac{9+96}{4})$ ⇒ $m=–\frac{105}{4}×\frac{2}{3}$ ⇒ $m=–\frac{35}{2}$ Hence, the correct answer is $–\frac{35}{2}$.
Question : A and B can do a piece of work in 25 days. B alone can do $66 \frac{2}{3}$% of the same work in 30 days. In how many days can A alone do $\frac{4}{15}$th part of the same work?
Option 1: 18
Option 2: 15
Option 3: 12
Option 4: 20
Correct Answer: 15
Solution : Days taken by A and B together to do total work = 25 days Days taken by B to do = $66\frac{2}{3}$% of total work = 30 days We know, Number of days taken = $\frac{(\text{Total work})}{(\text{Efficiency})}$ Days taken by B to do $66\frac{2}{3}\%$ i.e.
Question : Directions: Select the related letter cluster from the given alternatives. YAC : CEG :: NOQ : ?
Option 1: RSU
Option 2: RUS
Option 3: STV
Option 4: SVT
Correct Answer: RSU
Solution : Given: YAC : CEG :: NOQ : ?
Add 4 to the place value of each letter of YAC to obtain the required code – Y + 4 = C; A + 4 = E; C + 4 = G Thus, YAC is coded as
Question : Directions: In the following question, select the related number from the given alternatives. 200 : 25 :: 300 : ?
Option 1: 30
Option 2: 37.50
Option 3: 32.50
Option 4: 30.25
Correct Answer: 37.50
Solution : Given: 200 : 25 :: 300 : ?
Like, 200 : 25→200 ÷ 8 = 25 Similarly, for 300 : ?→300 ÷ 8 = 37.50
So, 300 is related to 37.50. Hence, the second option is correct.
Question : Directions: Which two numbers should be interchanged to make the given equation correct? 36 × 12 + 48 ÷ 6 –18 = 202
Option 1: 6 and 18
Option 2: 6 and 12
Option 3: 36 and 18
Option 4: 36 and 48
Correct Answer: 6 and 12
Solution : Given: 36 × 12 + 48 ÷ 6 –18 = 202
Replace the given numbers in the options one by one with the original numbers in the given equation. First option: 6 and 18 = 36 × 12 + 48 ÷ 18 –
Question : Directions: Which letter cluster will replace the question mark (?) to complete the given series? MKPN, LMOP, ?, JQMT, ISLV
Option 1: KOLT
Option 2: KNNQ
Option 3: KNMR
Option 4: KONR
Correct Answer: KONR
Solution : Given: MKPN, LMOP, ?, JQMT, ISLV
Subtract 1 from the place value of the first and the third letters and add 2 to the place value of the second and fourth letters of the previous term to obtain the next term in the series –
Question : Simplify: $(x+y)^3-(x-y)^3-6y(x^2-y^2)$
Option 1: $8y^3$
Option 2: $x^3$
Option 3: $8x^2$
Option 4: $y^3$
Correct Answer: $8y^3$
Solution : $(x+y)^3-(x-y)^3-6y(x^2-y^2)$ $=(x^3+3x^2y+3xy^2+y^3)-(x^3-3x^2y+3xy^2-y^3)-6x^2y+6y^3$ $=x^3+3x^2y+3xy^2+y^3-x^3+3x^2y-3xy^2+y^3-6x^2y+6y^3$ $=y^3+y^3+6y^3$ $=8y^3$ Hence, the correct answer is $8y^3$.
Question : Directions: Given here is a graph showing the number of workers with their daily payment by a workshop. Study the graph and answer questions based on this graph. The total daily payment made to the group, which contains 9 workers, is (in Rs.):
Option 1: 400
Option 2: 315
Option 3: 480
Option 4: 135
Correct Answer: 315
Solution : According to given bar graph in question, The daily payment made to each worker which contains 9 workers = Rs. 35 $\therefore$ Required total daily payment = 35 × 9 = Rs. 315 Hence, the correct answer is 315.
Question : Study the graph and answer the question. In how many years were the exports of type B cars more than the average exports of type A cars from 2012 to 2016?
Option 1: 2
Option 2: 3
Option 3: 1
Option 4: 4
Correct Answer: 4
Solution : Average exports of type A cars from 2012 to 2016 = $\frac{275+250+225+260+340}{5}$ = $\frac{1350}{5}$ = 270 Required number of years = 4 Hence, the correct answer is 4.
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