Staff Selection Commission Sub Inspector Exam
Question : Directions: The following table gives details about the percentage change in the population in a particular town for given years. Go through the chart given and answer the questions that follow:
Which year out of these 8 years has the highest population?
Option 1: 2008
Option 2: 2005
Option 3: 2010
Option 4: 2011
Correct Answer: 2011
Solution : The population will be highest in the year 2011. Because it is the last year of the bar graph and all the increased population will be counted in that year. Hence, the correct answer is 2011.
Question : Study the pie chart and answer the question.
Distribution (degree-wise) of the number of employees of a company working in 5 departments A, B, C, D, and E. Total number of employees = 3200 If the total number of employees working in departments A and B exceeds the number of employees in department C by $x$, then $x$ lies between:
Option 1: 120 and 140
Option 2: 80 and 100
Option 3: 100 and 120
Option 4: 140 and 160
Correct Answer: 120 and 140
Solution : The central angle formed by the number of employees in departments A and B = 79.2$^\circ$ + 57.6$^\circ$ = 136.8$^\circ$ The central angle formed by the number of employees in department C = 122.4$^\circ$ The number of employees in A and B is
Question : The simple interest on a sum of money at 10% per annum for 2 years is 8,100. Compounded annually, what would be the compound interest (in ) on the same sum for the same period at the same rate of interest?
Option 1: 8,100
Option 2: 8,505
Option 3: 8,715
Option 4: 9,000
Correct Answer: 8,505
Solution : Simple interest = $\frac{\text{Principal × Rate × Time}}{100}$ According to the question $⇒ 8100 = \frac{\text{Principal}×10×2}{100}$ $\therefore$ Principal $= 40500$ Now, $\text{Total Amount}$ $=\text{Principal}×(1+\frac{\text{Rate}}{100})^{\text{Time}}$ $ = 40500({1+ \frac{10}{100})^2}$ $ = 40500({ \frac{11}{10})^2}$ $ = 40500×{ \frac{121}{100}}$ $=49005$ $\therefore$ Compound Interest = Amount – Principal =
Question : Directions: The sequence of folding a piece of paper and how the folded paper has been cut is shown below. Choose the figure that would most closely resemble the unfolded form of the paper.
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : When the given folded paper is unfolded, it will look like –
Hence, the third option is correct.
Question : Geeta runs $\frac{5}{2}$ times as fast as Babita. In a race, if Geeta gives a lead of 40 m to Babita, find the distance from the starting point where both of them will meet (correct up to two decimal places).
Option 1: 66.67 m
Option 2: 65 m
Option 3: 65.33 m
Option 4: 66 m
Correct Answer: 66.67 m
Solution : Let the speed of Babita be $2x$. Speed of Geeta = $\frac{5}{2} \times 2x = 5x$ Let the distance covered by Geeta be $y$ metres. Distance covered by Babita = $(y - 40)$ metres As time is constant, distance is directly proportional to speed.
Question : An article is sold for Rs. 6552 after a discount of 22%. What is the marked price (in Rs.) of the article?
Option 1: 8450
Option 2: 8425
Option 3: 8400
Option 4: 8750
Correct Answer: 8400
Solution : Given: An article is sold for Rs. 6552 after a discount of 22%. Let the marked price be 100 units. So, the selling price is (100 – 22) = 78 units When the selling price is Rs. 6552, The marked price will be $\frac{100}{78}$ ×
Question : Directions: In a certain code language, LUCKNOW is written as 6, and PATANA is written as 5. How will RAJASTHAN be written in that language?
Option 1: 8
Option 2: 7
Option 3: 9
Option 4: 6
Correct Answer: 8
Solution : Given: LUCKNOW is written as 6, and PATANA is written as 5.
Subtract 1 from the total number of letters in LUCKNOW, to obtain the required code – The total number of letters in the word LUCKNOW is 7→7 – 1 = 6 Thus, LUCKNOW
Question : A can do work in 12 days and B in 20 days. If they together work on it for 5 days and the remaining work is completed by C in 3 days, then in how many days can C do the same work alone?
Option 1: 10 days
Option 2: 9 days
Option 3: 12 days
Option 4: 15 days
Correct Answer: 9 days
Solution : Given: A can do a piece of work in 12 days and B in 15 days. Time taken by A = 12 days So, part of work done by A in 1 day = $\frac{1}{12}$ Time taken by B = 20 days So, part
Question : Directions: In each of the following questions select the related words/letters/numbers/ figure from the given alternatives.
Solution : According to the given figures – 1. From Box 1 to Box 2, box 1 is rotated by 90° in an anticlockwise direction. 2. The oval shape figure moves to the right corner, also the triangle with a dot is now inside the rhombus. By following
Question : Directions: From the given options, which answer figure can be formed by folding the figure given in the question?
Solution : In the 3D view of dice, 1. Each face out of the three faces in the 3D view should be from all the pairs. 2. Two opposite faces cannot appear adjacently in the 3D view of a folded cube figure. So, the opposite pairs of faces
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