Staff Selection Commission Sub Inspector Exam
Question : The angle of elevation of an aeroplane from a point on the ground is 60°. After 15 seconds of flight, the elevation changes to 30°. If the aeroplane is flying at a height of $1500\sqrt{3}$ metre, find the speed of the plane:
Option 1: 300 m/sec
Option 2: 200 m/sec
Option 3: 100 m/sec
Option 4: 150 m/sec
Correct Answer: 200 m/sec
Solution : Height of the aeroplane = BD = CE = $1500\sqrt{3}$ m and $\angle$ BAE = 60°, $\angle$ CAE = 30° In $\Delta$ ADB, $\tan 60°=\frac{1500\sqrt{3}}{AD}$ ⇒ $\sqrt{3}=\frac{1500\sqrt{3}}{AD}$ ⇒ AD = $\frac{1500\sqrt{3}}{\sqrt{3}}$ ⇒ AD = 1500 m In $\Delta$ CAE, $\tan 30°=\frac{1500\sqrt{3}}{AE}$ ⇒ $\frac{1}{\sqrt{3}}=\frac{1500\sqrt{3}}{AE}$ ⇒
Question : The principles of Liberty, Equality, and Fraternity were adopted from the Constitution of:
Option 1: United Kingdom
Option 2: France
Option 3: Canada
Option 4: Ireland
Correct Answer: France
Solution : The correct option is France.
The principles of Liberty, equality, and Fraternity were adopted from the French Constitution. These ideals, integral to democratic values, were enshrined in the Preamble of the Indian Constitution, reflecting a commitment to justice, liberty, equality, and fraternity for all
Question : An item is offered for sale at Rs. 250, less by successive discounts of 20% and 15%. The sale price of the item is:
Option 1: 82% of Rs. 250
Option 2: 77% of Rs. 250
Option 3: 68% of Rs. 250
Option 4: 65% of Rs. 250
Correct Answer: 68% of Rs. 250
Solution : Single equivalent discount = $(x+y-\frac{xy}{100}$)% where $x$ and $y$ are two successive discounts. Total Discount = $(20+15-\frac{20×15}{100}$)% = 35 – 3 = 32% So, the required Selling Price = (100 – 32)% of Rs. 250 = 68% of Rs. 250 Hence, the
Question : Cellulose is a polymer of____.
Option 1: Fructose
Option 2: Galactose
Option 3: Glucose
Option 4: sucrose
Correct Answer: Glucose
Solution : The correct option is Glucose.
Cellulose is a polymer made up of repeated glucose units joined by 1, 4 glycosidic linkages. These glucose molecules are positioned in a way that allows them to create long, linear chains. Cellulose is essential for plant growth and structural
Question : Comprehension: Read the given passage and answer the questions that follow. Climate policy must now put health at the centre and promote climate change mitigation policies that bring health benefits simultaneously. Health-focused climate policy would help bring about a planet that has cleaner air, more abundant and safer fresh water and food, more effective and fairer health and social protection systems and, as a result, healthier people. Investments in clean energy will yield health gains that repay those investments twice over. There are proven interventions able to reduce emissions of short-lived climate pollutants, for instance, applying higher standards for vehicle emissions, which have been calculated to save approximately 2.4 million lives per year, through improved air quality and reduce global warming by about 0.5°C by 2050. The cost of renewable sources of energy has decreased significantly in the last few years, and solar energy is now cheaper than coal or gas in most major economies. Question: Which is the best description of the tone of the passage?
Option 1: Biased
Option 2: Cynical
Option 3: Technical
Option 4: Humanistic
Correct Answer: Humanistic
Solution : The correct answer is the fourth option
Explanation: The term "humanistic" is often associated with an approach that prioritises the well-being and dignity of humans. In the context of the passage, the focus on integrating health into climate policy suggests a concern for the health
Question : If the numerator of a fraction is increased by 60% and the denominator is increased by 40%, then the resultant fraction is $\frac{16}{63}$. The original fraction is:
Option 1: $\frac{5}{9}$
Option 2: $\frac{2}{9}$
Option 3: $\frac{2}{11}$
Option 4: $\frac{4}{9}$
Correct Answer: $\frac{2}{9}$
Solution : If the numerator of a fraction is increased by 60% and the denominator is increased by 40%, then the resultant fraction is $\frac{16}{63}$. The original fraction is: The numerator increased by 60% The denominator increased by 40% Resultant fraction = $\frac{16}{63}$ Calculation: Let the original
Question : The value of $6 \frac{8}{15}÷\frac{7}{9}$ of $\left(1 \frac{1}{10}+5 \frac{1}{5}\right)+\frac{2}{5}÷7 \frac{1}{5}$ is:
Option 1: $\frac{25}{16}$
Option 2: $\frac{5}{14}$
Option 3: $\frac{25}{18}$
Option 4: $\frac{5}{18}$
Correct Answer: $\frac{25}{18}$
Solution : $6 \frac{8}{15}÷\frac{7}{9}$ of $\left(1 \frac{1}{10}+5 \frac{1}{5}\right)+\frac{2}{5}÷7 \frac{1}{5}$ = $\frac{98}{15}÷\frac{7}{9}$ of $\left( \frac{11}{10}+ \frac{26}{5}\right)+\frac{2}{5}÷\frac{36}{5}$ = $\frac{98}{15}÷(\frac{7}{9}\times\frac{63}{10})+\frac{2}{5}÷\frac{36}{5}$ = $\frac{98}{15}×\frac{10}{49}+\frac{2}{5}×\frac{5}{36}$ = $\frac{4}{3}+\frac{1}{18}$ = $\frac{25}{18}$ Hence, the correct answer is $\frac{25}{18}$.
Question : Directions: Stayen starts walking towards North. After walking 70m he turns to left and walks 35m straight. He then turns to the left and walks 30m, again he turns to the left and walks a distance of 35m. How far is he from the starting point and in which direction?
Option 1: 35m, South
Option 2: 35m, North
Option 3: 40m, North
Option 4: 40m, South
Correct Answer: 40m, North
Solution : Firstly, we will draw the diagram as per the given instructions –
Now, we have to determine the distance between the starting and end points and in which direction with respect to the starting point.
The distance between the starting (A) and end point
Question : Directions: Select the option related to the third term in the same way as the second term is related to the first term. CANOPY : BCKSKE :: WARDROBE : ?
Option 1: VCOHMUVN
Option 2: VCOHMUUM
Option 3: XCOHMUUM
Option 4: XCOHMUUN
Correct Answer: VCOHMUUM
Solution : Given: CANOPY : BCKSKE :: WARDROBE : ?
Subtract and add consecutive numbers in the positional value of the alphabet alternately starting from 1. Like, CANOPY : BCKSKE→C – 1 = B; A + 2 = C; N – 3 = K; O + 4=
Question : The Battle of Haldighati was fought between which two armies?
Option 1: Babur and Lodi Empire
Option 2: Babur and Rana Sanga
Option 3: Akbar and Hemu
Option 4: Akbar and Maharana Pratap
Correct Answer: Akbar and Maharana Pratap
Solution : The correct answer is Akbar and Maharana Pratap.
Rajput monarch Maharana Pratap of Mewar and Mughal emperor Akbar engaged in combat in Haldighati. On June 18, 1576, a battle took place in the Haldighati Pass, which is now in the state
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