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Staff Selection Commission Sub Inspector Exam

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Question : Directions: From the given answer figures, select the one in which the question figure is hidden/embedded.

Option 1:

Option 2:

Option 3:

Option 4:

Team Careers360 17th Jan, 2024

Correct Answer:


Solution : Because there is no restriction on the rotation of the figure, we will check all the possible angles where the question figure can fit itself in the given option figures.
By comparison of all the option figures, the given question figure is embedded only in the

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Question : The number 150328 is divisible by 23. If the digits are rearranged in descending order and five times of 13 is subtracted from the new number thus formed, then the resultant number will be divisible by:

Option 1: 3

Option 2: 5

Option 3: 11

Option 4: 2

Team Careers360 20th Jan, 2024

Correct Answer: 5


Solution : Here, the number 150328 is divisible by 23.
When rearranged in descending order we get = 853210
When 5 times 13 i.e., 65 is subtracted from the new number, we get = 853210 – 65 = 853145
$\therefore$ The resultant number is divisible by 5

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Question : Directions: Two dimensions of the same dice are given. What letter will be on the face opposite to the face having the letter F?

Option 1: B

Option 2: D

Option 3: C

Option 4: A

Team Careers360 23rd Jan, 2024

Correct Answer: B


Solution : Taking dice positions 1 and 2 with B as the common face.

Moving clockwise from the common face with B –

So, the opposite pairs are –

So, the opposite face to the face containing F is B. Hence, the first option is correct.

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Question : The preferred IUPAC name of Allyl bromide is:

Option 1: 3-Bromopropene

Option 2: 3-Bromobutene

Option 3: 2-Bromopropene

Option 4: 1-Bromopentane

Team Careers360 20th Jan, 2024

Correct Answer: 3-Bromopropene


Solution : The correct option is 3-Bromopropene.

The preferred IUPAC name for allyl bromide is 3-Bromopropene. 

  • Molecular Formula: C₃H₅Br
  • Structural Formula: CH₂=CH-CH₂Br
  • It consists of a three-carbon chain with a double bond between the second and third carbon atoms and a bromine atom attached to the third
34 Views

Question : If $\cos ^2 \theta-\sin ^2 \theta=\tan ^2 \phi$, then which of the following is true?

Option 1: $\cos \theta \cos \phi=1$

Option 2: $\cos ^2 \phi-\sin ^2 \phi=\tan ^2 \theta$

Option 3: $\cos ^2 \phi-\sin ^2 \phi=\cot ^2 \theta$

Option 4: $\cos \theta \cos \phi=\sqrt{2}$

Team Careers360 17th Jan, 2024

Correct Answer: $\cos ^2 \phi-\sin ^2 \phi=\tan ^2 \theta$


Solution : Given,
$\cos^2\theta – \sin^2 \theta = \tan^2 \phi$
⇒ $\frac{\cos^2 \theta – \sin^2\theta}{1} = \frac{\sin^2\phi}{\cos^2 \phi}$
⇒ $\frac{\cos^2 \theta – \sin^2 \theta}{\cos^2\theta + \sin^2 \theta} = \frac{\sin^2\phi}{\cos^2 \phi}$
By Componendo and Dividendo,
⇒ $\frac{\cos^2 \theta}{–\sin^2 \theta} = \frac{\sin^2 \phi

8 Views

Question : Directions: In the following question, find the odd number pair from the given alternatives.

Option 1: 14 – 48 

Option 2: 12 – 72 

Option 3: 11 – 88 

Option 4: 8 – 24 

Team Careers360 11th Jan, 2024

Correct Answer: 14 – 48 


Solution : Let's check the options –
First option: 14 – 48; 48 is not divisible by 14. 
Second option: 12 – 72; 72 ÷ 12 = 6
Third option: 11 – 88; 88 ÷ 11 = 8
Fourth option: 8 – 24; 24 ÷

14 Views

Question : What is the value of $\frac{0.74 \times 1.23 \times 0.13}{(0.37)^3+(0.41)^3-8(0.39)^3}$?

Option 1: $1$

Option 2: $-\frac{1}{3}$

Option 3: $\frac{1}{3}$

Option 4: $-1$

Team Careers360 13th Jan, 2024

Correct Answer: $-\frac{1}{3}$


Solution : $\frac{0.74 \times 1.23 \times 0.13}{(0.37)^3+(0.41)^3-8(0.39)^3}$
$=\frac{0.74 \times 1.23 \times 0.13}{(0.37)^3+(0.41)^3-(0.78)^3}$
We know the identity,
If $a+b+c=0$ then $a^3+b^3+c^3=3abc$
Here, $(0.37 + 0.41 - 0.78) = 0 ⇒ (0.37)^3+(0.41)^3-(0.78)^3=-3\times 0.37\times 0.41\times 0.78$
So, $\frac{0.74 \times 1.23 \times 0.13}{(0.37)^3+(0.41)^3-(0.78)^3}$
$=\frac{0.74 \times 1.23 \times 0.13}{-3\times 0.37\times 0.41\times 0.78}$

16 Views

Question : How many schedules are there in the Indian Constitution?

Option 1: 8

Option 2: 10

Option 3: 11

Option 4: 12

Team Careers360 17th Jan, 2024

Correct Answer: 12


Solution : The correct option is 12.

The 12 schedules in the Indian Constitution cover a wide range of topics, including delegation of authority, representation, official languages, and more. There were eight schedules in the original Indian Constitution. It was amended and now the number of

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