Staff Selection Commission Sub Inspector Exam
Question : If $a+b+c=0$, then the value of $\frac{a^2}{b c}+\frac{b^2}{c a}+\frac{c^2}{a b}$ is:
Option 1: 1
Option 2: 3
Option 3: - 1
Option 4: 0
Correct Answer: 3
Solution : $a+b+c=0$ $a^3+b^3+c^3 - 3abc = (a+b+c)(a^2+b^2+c^2-ab-bc-ca)$ ⇒ $a^3+b^3+c^3 - 3abc = 0$ ⇒ $a^3+b^3+c^3 = 3abc$ ⇒ $\frac{a^3+b^3+c^3}{abc} = 3$ ⇒ $\frac{a^2}{bc} + \frac{b^2}{ac} + \frac{c^2}{ab} = 3$ Hence, the correct answer is 3.
Question : If a nine-digit number 785$x$3678$y$ is divisible by 72, then the value of ($x$ + $y$) is:
Option 1: 20
Option 2: 12
Option 3: 10
Option 4: 5
Correct Answer: 10
Solution : Given number = 785$x$3678$y$ is divisible by 72, then the number must be divisible by 8 and 9. 785$x$3678$y$ is divisible by 8 if the last digit three-digit 78y is divisible by 8. 78$y$ is divisible by 8 if $y$ = 4 785$x$36784 is divisible
Question : Directions: In the following question, a sentence is given with a blank that is to be filled in with an appropriate word. Four alternatives are suggested; choose the correct alternative out of them as your answer.
The demonstration passed off without any _______.
Option 1: coincidence
Option 2: accident
Option 3: incident
Option 4: incidence
Correct Answer: incident
Solution : The correct choice is the third option.
Incident means an event or occurrence. This is the correct answer, as it fits the context of the sentence, describing that the demonstration occurred without any noteworthy events or occurrences.
The meanings of the other options are as
Question : Directions: In the following question, find the odd number from the given alternatives.
Option 1: 25
Option 2: 15
Option 3: 18
Option 4: 21
Correct Answer: 25
Solution : Let's check the given options – First option: 25 is not divisible by 3. Second option: 15; 15 ÷ 3 = 5 (It is divisible by 3) Third option: 18; 18 ÷ 3 = 6 (It is divisible by 3) Fourth option: 21; 21 ÷
Question : Directions: Two positions of a cube are shown below. What will come opposite to face containing 1?
Option 1: 4 or 5
Option 2: 5
Option 3: 4
Option 4: 3
Correct Answer: 5
Solution : Taking dice positions 1 and 2 with 3 as a common face,
Moving clockwise from the common face with 3,
Pairs of opposite numbers –
So, the face opposite to the face containing 1 is 5. Hence, the second option is correct.
Question : In which state of India was a non-Congress government formed for the first time?
Option 1: West Bengal
Option 2: Tamil Nadu
Option 3: Puducherry
Option 4: Kerala
Correct Answer: Kerala
Solution : The correct option is Kerala.
The first non-Congress government in India was formed in the state of Kerala. The 1957 Kerala Legislative Assembly election resulted in the formation of the first democratically elected communist government in the world, led by the Communist Party of
Question : Directions: If a mirror is placed on line AB, then which of the answer figures is the right image of the given figure?
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : As per the mirror image properties, closer things appear close to the mirror in the reflection. So, according to the above property and the information provided, the mirror is placed on the right side of the figure (on line AB). So, the left side of the
Question : Which of the following is colourless?
Option 1: Chlorine
Option 2: Oxygen
Option 3: Phosphorus
Option 4: Sulphur
Correct Answer: Oxygen
Solution : The correct option is Oxygen.
Oxygen is said to be colourless in its elemental state. Composed of two linked oxygen atoms, oxygen gas (O2) is typically colourless and transparent. We inhale oxygen when we breathe, and the air we breathe looks colourless to
Question : Directions: Select the option related to the third letter cluster in the same way as the second letter cluster is related to the first letter cluster. SLOW : MPTX :: CAUGHT : ?
Option 1: BDHIUV
Option 2: BDIUVH
Option 3: WVHIUV
Option 4: DBVHIU
Correct Answer: BDHIUV
Solution : Given: SLOW : MPTX :: CAUGHT : ?
Arrange letters in alphabetical order and then add 1 in the positional value of SLOW, to obtain the required code – SLOW→LOSW L + 1 = M, O + 1 = P, S + 1 = T,
Question : If $x^4+\frac{1}{x^4}=1154$, where $x>0$, then what is the value of $x^3+\frac{1}{x^3}?$
Option 1: 205
Option 2: 214
Option 3: 185
Option 4: 198
Correct Answer: 198
Solution : Given, $x^4+\frac{1}{x^4}=1154$ Adding 2 on both sides, $x^4+\frac1{x^4}+2=1154+2$ ⇒ $(x^2)^2+(\frac1{x^2})^2+2\times x^2\times\frac1{x^2}=1156$ We know, $a^2+b^2+2ab=(a+b)^2$ ⇒ $(x^2+\frac{1}{x^2})^2=1156$ ⇒ $x^2+\frac{1}{x^2}=\sqrt{1156}$ ⇒ $x^2+\frac{1}{x^2}=34$ Again, adding 2 on both sides, ⇒ $x^2+\frac{1}{x^2}+2=34+2$ ⇒ $(x+\frac{1}{x})^2=36$ ⇒ $x+\frac{1}{x}=6$ We know, $a^3+b^3=(a+b)(a^2-ab+b^2)$ ⇒ $x^3+\frac{1}{x^3}=(x+\frac1x)(x^2-x\times\frac1x+\frac1{x^2})$ $= (x+\frac1x)(x^2+\frac1{x^2}-1)$ $= 6 × (34 – 1)
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