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Staff Selection Commission Sub Inspector Exam

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Question : Hydro Thermal Carbonisation technology(HTC) developed at IIT Kharagpur is a process of generation of energy from which of the following sources?

Option 1: Water current in rivers

Option 2: Hydropower in barrages and dams

Option 3: Solid waste with high moisture content

Option 4: Naturally available Hydrocarbons

Team Careers360 14th Jan, 2024

Correct Answer: Solid waste with high moisture content


Solution : The correct option is solid waste with high moisture content.

The Hydro-Thermal Carbonisation (HTC) technology developed at IIT Kharagpur isn't directly for generating energy but rather for transforming organic waste, solid waste with high moisture content, into valuable resources.

13 Views

Question : Select the option that can be used as a one-word substitute for the given group of words.

A place where coins are made

Option 1: Trough

Option 2: Post Office

Option 3: Grove

Option 4: Mint

Team Careers360 14th Jan, 2024

Correct Answer: Mint


Solution : The fourth option is correct.

The one-word substitute for the given group of words "a place where coins are made" is mint.

A mint can refer to a facility where coins are manufactured.

Therefore, the correct answer is mint.

10 Views

Question : Under which Article of the Constitution of India is the National Commission for Scheduled Castes established?

Option 1: Article 336

Option 2: Article 338

Option 3: Article 333

Option 4: Article 335

Team Careers360 7th Jan, 2024

Correct Answer: Article 338


Solution : The correct answer is Article 338.

The National Commission for the Scheduled Castes and Scheduled Tribes was established under Article 338 of the Constitution to oversee all the protections afforded to the Scheduled Castes and Scheduled Tribes by the Constitution or other laws. The

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Question : Select the option that can be used as a one-word substitute for the given group of words.

A letter, poem etc. whose author is unknown.

Option 1: Autonomous

Option 2: Anomalous

Option 3: Anonymous

Option 4: Autocrat

Team Careers360 16th Jan, 2024

Correct Answer: Anonymous


Solution : The third option is correct.

Explanation: The word anonymous is an adjective that describes something for which the author's identity is not known or disclosed. In this context, it is used to refer to a letter, poem, etc., where the author remains unidentified.

Therefore, the

14 Views

Question : Who among the following gave "The Theory of Natural Selection"?

Option 1: Richard High Ebright

Option 2: Lamarck

Option 3: Charles Darwin

Option 4: Francesco Redi

Team Careers360 25th Jan, 2024

Correct Answer: Charles Darwin


Solution : The correct option is Charles Darwin.

Natural selection theory, introduced by Charles Darwin and Alfred Russel Wallace, is a key idea in evolutionary biology. It is a major mechanism that drives the evolution and adaptive processes in living organisms explaining how they adapt to

71 Views

Question : The given pie charts represent the popularity of ice-cream flavours in the years 2005 and 2015.


If a percentage point shift results in annual additional sales of INR 10,000, how much (in INR), did the combined annual strawberry and butterscotch sales increase from 2005 to 2015?

Option 1: INR 74,000

Option 2: INR 37,000

Option 3: INR 65,000

Option 4: INR 10,000

Team Careers360 7th Jan, 2024

Correct Answer: INR 74,000


Solution : 1% = INR 10000
Combined annual strawberry and butterscotch sales in 2005
= 18.90 + 10.80
= 29.70%
Combined annual strawberry and butterscotch sales in 2015
= 20.50 + 16.60
= 37.10%
Percentage increase
= 37.10 – 29.70
= 7.4%
Required sales increase
=

19 Views

Question : In $\triangle{ABC}, \angle A=90^{\circ}, {AB}=16\ cm $ and $AC =12 \ cm$. $D$ is the midpoint of $AC$ and $DE \perp CB$ at $E$. What is the area (in ${cm}^2$ ) of $\triangle{CDE}$?

Option 1: 8.64

Option 2: 7.68

Option 3: 5.76

Option 4: 6.25

Team Careers360 15th Jan, 2024

Correct Answer: 8.64


Solution :
Given: In $\triangle {ABC}, \angle A=90^{\circ}, {AB}=16\ cm $ and $AC =12 \ cm$.
$D$ is the midpoint of $AC$ and $DE \perp CB$ at $E$.
The area of the triangle = $\frac{1}{2}\times \text{Base} \times \text{Height}$
Use the Pythagoras's theorem in $\triangle ABC$, $(BC)^2=(AB)^2+(AC)^2$

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