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Question : Directions: Select the option that represents the correct order of the given words as they would appear in an English dictionary. 1. Profess 2. Product 3. Prosecute 4. Precaution 5. Proctor
Option 1: 2, 5, 4, 1, 3
Option 2: 3, 5, 2, 1, 4
Option 3: 4, 5, 2, 3, 1
Option 4: 4, 5, 2, 1, 3
Correct Answer: 4, 5, 2, 1, 3
Solution : Given: 1. Profess 2. Product 3. Prosecute 4. Precaution 5. Proctor
Step 1: Compare the first and second letters of each word. Since all the words start with the same letter P, and are followed by r then move on
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Yes, you can change your college after 2nd year. In the BA-LLB course, a law student can change colleges after completing two semesters of the first year. This applies specifically to students who have been admitted through the Centralised Admission Process (CAP). So, if you want to explore other
Question : Sports Authority of India, the apex body for sports promotion, was set up in the year_______.
Option 1: 1990
Option 2: 1961
Option 3: 1984
Option 4: 1982
Correct Answer: 1984
Solution : The correct option is 1984.
The Sports Authority of India (SAI) was founded by the Ministry of Youth Affairs and Sports of the Government of India. It was established as a registered society on January 25, 1984, through the Department of Sports. SAI is
Yes, arts students with a background in mathematics are eligible to apply for the CMI entrance exam. The CMI entrance exam is open to students from various backgrounds and that includes arts with maths. The eligibility requirement is that the student must have completed 10+2 or equivalent examination with
Question : If in a $\triangle$ABC, D and E are on the sides AB and AC, such that, DE is parallel to BC and $\frac{AD}{BD}$ = $\frac{3}{5}$. If AC = 4 cm, then AE is:
Option 1: 1.5 cm
Option 2: 2.0 cm
Option 3: 1.8 cm
Option 4: 2.4 cm
Correct Answer: 1.5 cm
Solution : Given: $\frac{AD}{BD}$ = $\frac{3}{5}$ In $\triangle$ABC and $\triangle$DBE, $\angle$BAC = $\angle$DAE (same angle) $\angle$ADE = $\angle$ABC (corresponding angles) $\angle$AED = $\angle$ACB (corresponding angles) By AAA similarity, $\triangle$ABC ~ $\triangle$ADE ⇒ $\frac{AD}{AB}$ = $\frac{AD}{AD+BD}$ = $\frac{3}{3+5}$ = $\frac{3}{8}$ Now, $\frac{AD}{AB}$ = $\frac{AE}{AC}$ ⇒ $\frac{3}{8}$ =
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