Hello Dear Student,
With a 95.9 percentile in TANCET MBA 2026, securing a regular MBA seat at the University of Madras during the general counselling process is highly challenging, but possible depending on your community category and the specific TANCET cutoff list for the year.

You can check, find and

Hi,

With 97.3 percentile in TANCET under BC category, you actually have a very strong profile for top MBA colleges in Tamil Nadu.

You should definitely fill as many good options as possible, not just 5 colleges. More choices increase your chances during allotment.

Top colleges you should prioritize include:

To apply or download the TANCET MBA 2025 scorecard, you need to visit the official TANCET website, which is managed by Anna University. Once the results are announced, the scorecard will be available online for download.

Here’s what you should do:

1. Go to the official TANCET website.

2. Click

Hello,

TANCET is a popular entrance exam in Tamil Nadu for MBA aspirants. The exam evaluates candidate's aptitude in areas like quantitative ability, logical reasoning, verbal ability, and data interpretation.

TANCET scores are accepted by various colleges and universities in Tamil Nadu for their MBA programs.

You can get TANCET

Hello aspirant,

The TANCET MBA question paper provides candidates with information on the test's format, probable themes, degree of difficulty, and other features. Using the TANCET MBA questions paper is one of the best ways for applicants to master the entrance exam and get a higher grade.

To obtain the

Hello aspirant,

Through the use of the TANCET MBA question paper, candidates can learn about the format, likely themes, difficulty level, and other aspects of the test. One of the finest approaches for applicants to ace the entrance exam and score higher is to use the TANCET MBA questions paper.

Correct Answer: $0$

Solution : Given: $\frac{x}{(b–c)(b+c–2a)}=\frac{y}{(c–a)(c+a–2b)}=\frac{z}{(a–b)(a+b–2c)}$
Let $\frac{x}{(b–c)(b+c–2a)}=\frac{y}{(c–a)(c+a–2b)}=\frac{z}{(a–b)(a+b–2c)}=k$.
${x}=k{(b–c)(b+c–2a)}$ (equation 1)
${y}=k{(c–a)(c+a–2b)}$ (equation 2)
${z}=k{(a–b)(a+b–2c)}$ (equation 3)
Adding equations 1, 2, and 3 respectively, we get,
$x+y+z=k{(b–c)(b+c–2a)}+k{(c–a)(c+a–2b)}+k{(a–b)(a+b–2c)}$
$x+y+z=k[(b–c)(b+c–2a)+(c–a)(c+a–2b)+(a–b)(a+b–2c)]$
$x+y+z= k[b^2+bc–2ab–bc–c^2+2ac+c^2+ac–2bc–ac–a^2+2ab+a^2+ab–2ac–ab–b^2+2bc)$
$x+y+z$ = 0
Hence, the correct answer is 0.

Correct Answer: All of the above.
 

Solution : No licence was needed to-

1. Set up new units
2. Expand the existing line of manufacturing
3. Diversify the existing line of manufacturing

Hence Option D is correct.

Correct Answer: Sonu Nigam

Solution : The correct answer is Sonu Nigam.

Sonu Nigam, the accomplished Indian singer, composer, and actor, was honoured with the Padma Shri in 2022 for his noteworthy contributions to the arts. Recognized as the "Modern Rafi," a tribute to his musical inspiration, Muhammad Rafi, Sonu