Dear

According to the information with a JEE Mains rank of 408,120, getting admission to the College of Delhi for BTech in Computer Science and Engineering (CSE) might be challenging as the cutoffs for this course are generally higher. However, there are still several private colleges in Delhi that accept JEE Mains scores and have lower cutoffs. Here are some options you can consider:

1. Jamia Millia Islamia (JMI)

2. Netaji Subhas University of Technology (NSUT)

3. Guru Gobind Singh Indraprastha University (GGSIPU)

4. Bharati Vidyapeeth's College of Engineering (BVCOE)

5. HMR Institute of Technology and Management (HMRITM)

These colleges have varying cutoffs, and your rank might be competitive for admission to some of them. For finding the best college you deserve use College predictor tool.

Thanks.

Hey,

First of all congratulations for scoring such rank.

Apart from the IITs, the top colleges accepting UCEED 2024 score are listed below:

• Tezpur University, Assam
• Dr D Y Patil School of Design, Pune
• Manav Rachna International Institute of Research and Studies
• Footwear Design & Development Institute (FDDI)
• Shri Mata Vaishno Devi University, Katra
• Dr Vishwanath Karad MIT World Peace University, Pune
• Department of Design, Netaji Subhas University of Technology (NSUT), New Delhi
• RV University, Bengaluru
• Somaiya School of Design, Somaiya Vidyavihar University, Mumbai
• JK Lakshmipat University, Jaipur
• CMR University, Bengaluru
• ITM Skills University, Navi Mumbai
• World University of Design, Sonipat
• Indraprastha Institute of Information Technology Delhi
• Department of Design, Shiv Nadar IoE, Delhi NCR
• Navrachana University, Gujarat
• MIT ID Indore - Avantika University
• CEPT University, Ahmedabad
• Institute of Design, Nirma University, Ahmedabad
• MODY University of Science and Technology, Rajasthan

Predict your UCEED college at : https://design.careers360.com/uceed-college-predictor?utm_medium=c360

Hope this helps you.

Hello

IIT Bombay released the UCEED cutoff 2024 on February 8 in the form of mean and standard deviation. The mean and standard deviation for UCEED 2024 cutoff for Part A are 43.91 and 23.03 respectively.

You can check the cutoffs, eligibility and more for UCEED 2024, using the below link.

https://design.careers360.com/articles/uceed-cutoff

Correct Answer: 130

Solution : Given numbers = 260 and 390
LCM = 780
We know,
Multiplication of two numbers = HCF × LCM
⇒ 260 × 390 = 780 × HCF
⇒ HCF = 130
Hence, the correct answer is 130.