University
Hi Himanshu,
The Delhi Technological University offers Undergraduate and Postgraduate courses but as you mentioned 12th standard, I am going to give you information regarding UG programs. For B.Tech, you need to pass 12th with Physics, Chemistry, Mathematics and English as their main subjects. B.Des. and BBA require a candidate
Hello Satyam,
Aryabhatta Knowledge University at Patna provides a M.Sc course in Food technology. The duration of this course is 2 years.
To apply for admission, you need to fulfill the eligibility criteria which says that the candidate must have passed class 10+2 from a recognized board and has a
Dear candidate,
The result of the degree 1st semester examinations that are held in the month of May 2019 by Adikavi Nannaya University(AKNU) will be declared on the month of January 2019. The results will be available on the official website @nannaya.info .
Hope this information is helpful.
Hello saurav
You can get the question frome outside or you can buy a guide for that entrance exam, here we only solve your queries about colleges ,courses and your doubts about pursuing any field.
I hope it helps.
Hello Bharadwaj,
Minimum of 80 marks in the AP eamcet to get the rank below 10000, then you can get the free seat in any college in AP.For a particular college to get free seat you wants to get below cut-off rank for that particular college if the cut-off rank
Hello there. Hope you are doing good. I would like to tell you that as per the official website, only the 3rd semesters are results. First semester results will be out soon but there is no official announcement for the same till date. You can check official website regularly for
Hello,
Sorry to disappoint you, it is quite difficult to get into the top IIMs. Students generally get the call when there score is above 96 in particular for IIM-ABC. 96 might be less as well.
But don't get disappointed, with 84 percentile you can still apply for the other
Hello.
If you are searching for Private colleges In India . Then I would recommend you to try the College Predictor tool ( Click here ).
To get your rank :
100 - your total percentile score .
869010 are the number of candidates appeared for Jan exam.
(100-68)*869010/100= 278083.
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