Hello Utkarsh Pandey,

The capus of Vishwakarma institute of technology is fine. The academic facilities are adequate. The faculty is not that good but still not an issue.

The job work placements of ECE are next best to CSE. The average package of the mentioned branch is 5-6 lpa. The

Hello Aspirant, 

Most or you can say about all of the colleges have a variety of hostel residing students and do not allow the mess department to cook non vegetarian meals for the students. So wherever you find a mess, you will only get pure vegetarian food and this routine

Hi Piyush,

I can provide you 2017 and 2018 MHT CET cutoff of VIT, Pune, and VJTI, Mumbai for CS and IT branch.

These cutoffs were for NT-2 category i.e. NT-C, so you can get a clear idea.

• VIT, Pune-

In 2017, after the last round-

Closing Rank- 4,744 (CS)

Hello Aditya,

As you secured 88 percentile it is good in the jee main .

The VIT,Pune . According to the information there is admission through the jee main contact the college management

If you have contacted the college management they will give you information about the B category seats

Hello Prajwal,

I will mention the closing rank of all branches in VIT,Pune.

• Chemical engg( CR 4099)
• Computer science( CR 950)
• Electronics and telecommunication( CR 2267)
•  Electonics engg( CR 3600)
• Nformation tech(CR 1018)
• Industrial engg(CR 11406)
• Mechanical(CR 2300)

For more info

https://www.careers360.com/colleges/vishwakarma-institute-of-technology-pune

Sorry but unfortunately you are not eligible for the JEE Advanced 2019 exam as a candidate is treated based on the information they have provided in registration form which are verified. As you have not mentioned general EWS in the form you will be treated as a student of general

Hey!

Sorry but your query is bit unclear so please make it clear first  and provide all the necessary details then only we will be able to provide you with an answer.

Thanks.

Hii Nishant. 90.88 %ile means 90.88% of students who appeared for this exam have scored less than or equal to you. That means 9.12% are ahead of you. And this year approximately 3.93 lakh students have appeared for the exam. So, your rank can be calculated as 9.12% of 393000