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Hello pavansaidasari,
There are several universities that are quite good for MCA, some of them that accept lateral entry are mentioned below:
hello aspirant
Orbital angular momentum is given by the formula given below:
for a ‘p’ electron, l = 1, hence you can now find out the answer by putting the values.
To calculate the angular momentum of an electron, use the Bohr’s formula which is given by mvr.
Where,
m
Hi Tech,
On securing 160 marks in JEE Main, you rank would be approximately in between 17000 to 19000. Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score. The percentile corresponding to this rank
Greetings aspirant,
As per your percentile score, you're not likely to get a seat in any of the NITs through general category quota. Also, if you're general category candidate, it is not quite possible that you might clear JEE Mains 2020. But if you belong to SC or ST category,
Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 65697. Let's say the number of candidates for April exam increased to 12,00,000 then your final rank shall be (100 - your total score) X 12,00,000/100. Now you haven't mentioned
Hi Suhas,
Dayananda Sagar College of Engineering, Bangalore accepts COMEDK UGET, KGET B.Tech, NATA, GATE entrance exams and takes admission through all these only.
MHT - CET is not accepted by Dayananda Sagar College of Engineering, Bangalore.
This college admits the students B.E/B.Tech degree through COMEDK UGET only.
You may
Hello Rahul
The cutoff for CSE in Thapar is 40985 for home state students and around 19k for students from outside punjab.
According to your cutoff you rank will be more than 50k, do it's really difficult that you will get cse but you can get any other stream very
you can follow these steps to prepare for NEET:
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