It's a Question of your Career!

Dear Sethu,

IISER i.e,  Indian Institution Of Science and Research, admits student by three channels and these are:

1. Kishore vaigyanik prosthan yojana (KVPY)

2. IIT-JEE (advance) and

3. Date and central board (SCB).

So, yes you can apply for IISER through SCB and JEE.

Good luck.

Thank you!

Hello Vikash,

VIMS- Vydehi Institute of Medical Sciences and Research Centre, Bangalore is a private college established in 2000. Most of the courses are related to medical field only.

The admission is through NEET and NEET PG.

Please follow the below official link for eligibility information:

http://www.vims.ac.in/education/medical-college-admission.html

Please follow the

Hello ,

The Attendance matter depends on the college you are in . The college decides the attendance theory and applies.

But I guess,in every college and every stream  there is a Criteria of 75% attendance. 75%  attendance is mandatory for every student to attend the respective College Examinations.

But

No Shaheer. An NRI can only apply under NRI Category and not under General Cateogry. The Categories like General Category, EWS, OBC,SC,ST are confined to Indian Nationals appearing for NEET based on the constitutional rights. Reservations are not applicable for NRI Candidates. So if you are a NRI, you should

Hi,

Indian Statistical Institute conducts entrance test to admission for various ug and pg courses.

For the year 2020 it is conducted by indian statistical institute of science Calcutta. The registration will open for the year likely in the Month of February 2020 and exam will be conducted in the

Hello,  Abdullah

It’s difficult to predict actual rank or JEE advanced qualify marks. you may calculate your expected rank by this formula.

To calculate the rank for B.Arch:

So rank formula is (100 - your total score) X 112679 /100.

At this Score or Rank your Chances To get nit

• The sum of the original n number is 32n
• If 3/4th of the numbers are each increased by 4 their sum and therefore the sum of n increases by 3/4n X 4=3n
• If 1/4th each decreased by 6 their sum

First of all you need to pursue computer science engineering course of course from a top university of you want better future opportunities. Then you will have a chance to either do masters in operating system from foreign universitites or else you can do MTech from Indian top universities like

Hi Aruna.

The cutoff ranks for Engineering physics vary for different IITs.  For example-

• IIT Delhi- Engineering Physics closing rank for general category last year was  2097 AIR.
• IIT Bombay- The closing rank was 1041 in 2018.
• IIT Kanpur- It has a Physics branch, whose cutoff closing rank last year