It's a Question of your Career!

You can calculate your rank in JEE Main Paper 1 using the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 1 (Jan) are around 869000, your rank will be around 70000. However as the no. of students in April changes,

For more details related to gate exam you can contact to Deepanshu jain sir-8787241374

They are very helpful for me

Dear student ,

if you want to pursue BMS from St Xavier college mumbai then you have to qualify in the entrance test which held every year in the third week of june . a student must fulfill the eligibility criteria as per demanded at the time of filling the

Hello!

Check the following link for information about colleges in Hyderabad: https://engineering.careers360.com/colleges/list-of-engineering-colleges-in-hyderabad

Congratulations on your score. You've surely worked hard which is why you were ahead of 4 lakh other students. You should focus on the April session. It is a good opportunity to do better and improve your rank.

For SC cartagery how many cut off marks

Following are the opening and closing ranks for different categories for CSE branch at IIT Jodhpur:

Open                      2209                    3110

Open (PwD)           75                      126

OBC-NCL               949                    1279

OBC-NCL (PwD)     64P                      64P

SC                            568                     825

ST                            316                        461

For more information regarding cutoffs, kindly visit the follwing links:

https://josaa.nic.in/webinfocms/Public/View.aspx?page=71

https://josaa.nic.in/Result/Result/OpeningClosingRankArchieve.aspx

Hello!!

To calculate your JEE main rank,you can use this formula ((100-your total percentile)*869010/100).This formula will give your general category rank(Common list rank).And your rank is approximately 187966.To know about all the possibilities of your admission into various colleges,visit the below given website.You will have to enter the details asked