It's a Question of your Career!

hi,

you may get the full syallabus of neet ug in information brochure according to 11th and 12th syllabus.

number questions- subject is given below,

physics-45 question- 180 marks

chemistry-45 questions-180 marks

biology- 90 questions-360 marks.

for each correct answer you will get 4 marks, for each of wrong input

You must have Mathematics and Physics as subjects in 10+2.

You can give NDA(National Defence Academy) through the CDS exam conducted twice a year by UPSC. The candidates who qualify the examination will have to undergo a three years training .

Admission through NCC special entry scheme is also a

Hey Joshi

You can give NDA(National Defence Academy) through the CDS exam conducted twice a year by UPSC. You must have Mathematics and Physics as subjects in 10+2.The candidates who qualify the examination will have to undergo a three years training .

Admission through NCC special entry scheme is also

Hello,

No, Sathaye College, Mumbai doesn't offer any law program for 12th students. It offers programmes in various disciplines such as BMM,BMS,BCom, BSc, BA and Master's Degree in Arts and Science.

You can check out the following link for more details regarding the same-

https://www.careers360.com/colleges/sathaye-college-mumbai

Hello,

Yes you can give the exam and if you qualify and get selected you can take your admission back from the current course you are pursuing. But you'll have to essentially present the documents required during the counselling which you'll have to take from your current university in case

NEET exam cutoff to get admission in Kolkata college is based on different ranks for different categories. According to last cutoff result, one can get admission in Kolkata college if he/she have scored the following ranks and score i.e,

1. For general category the student's rank must be around 18370

Hello ,

The answer will be 47 .

As x+1/x= 3

Squaring both sides ;

x²+1/x² + 2.x.(1/x)= 9

x²+1/x²=9-2=7

Now again squaring it we get;

x+1/x+2.x².(1/x²)=49

x+1/x= 49-2 = 47.

So the required answer is 47 .

Hello. Did you contact the help desk? My friend made the same mistake. Even he wants to know the same.

Hi aspirant,

You have got a very good score.Congratulations on that but it is very difficult to say about the results clearly.

lets hope for the best.

you may calculate your expected rank by this formula

100 - your total percentile score is the percentage  of people ahead of you.

Hello bhavani

The exam centres are

• Anantapur
• Chittoor
• Godavari
• Guntur
• Krishna
• Gooty
• Hindpur
• Puttur
• Kakinada
• Nandayal
• Kavali
• Eluru
• Rajampat

I hope it helps