It's a Question of your Career!

Hello,

With is percentile you can not be able to get any nit or any government college. So you should wait for the state counselling.

For more details you please visit the following link

https://engineering.careers360.com/jee-main-college-predictor

Hope for the best.

Thank you.

Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 177451. Let's say the number of candidates for April exam increased to 12,00,000 then your final rank shall be (100 - your total score) X 12,00,000/100. Now to predict colleges,

Hello dear student,

as you have asked for the fee structure of jawaharlal Nehru engineering College mahatma Gandhi mission ideas to this college do not provide BTech rather it provides bachelor in in engineering which is BE. Fee structure of BE in mechanical engineering is 4.80 lakhs for 4 years

Following are the last year's cutoff of JEE Main for the eligibility of JEE Advanced:

CRL              89.7548849+

Gen-EWS    78.2174869

OBC-NCL    74.3166557

SC                54.0128155

ST                44.3345172

PwD            0.11371730

As you can see there are less chances of being you qualified for JEE Advanced but if the cutoff percentile changes, you may

hi,

see open university student who have completed their graduation in any discipline may appear in cds exam.

you have not mention your graduation course or stream. if you dont belongs to bachelor in electrical engineering or bachelor courses in physics or mathematics you may apply for below mention post,

Hello,

With this percentile you can not get any government college  but you have the chances to get many private colleges.

Just to search the colleges in your hometown you can use the following link.

https://engineering.careers360.com/jee-main-college-predictor

Hope for the best.

Thank you.

To find the impedance of the circuit, we first calculate X L and X C .

X L = 2 π ν L

= 2 × 3.14 × 50 × 25.48 × 10 –3 W = 8 W

X C = (1/2 π ν C)

= (1/ 2 × 3.14

Hi Sowjanya!

for IIIT Allahabad:

• Admission in full-time B. Tech course, JEE Mains score is considered.
• Admission in full-time M. Tech course, GATE score is considered.
• Admission in the full-time coordinated course, JEE Mains score is considered.
• PhD confirmation 2020, the up-and-comer needs a fair scholastic score and needs to