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Hi Sukanya,
I am sorry, but a minimum of 60% marks is required in the undergraduate degree from a recognized University or Institution to get admission in VIT Vellore MBA. You got only 52% in graduation.
Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 206129. Now this is your overall rank and we do not have Category based ranks yet. Let's say the number of candidates for April exam increased to 12,00,000 then your
Hi Deep,
The cut off for M.Sc. Statistics in Delhi University is 63 marks for an SC candidate.
According to 2019 merit list, a SC student got M.Sc. Statistics in Ramjas College scoring 66 marks and 98 combined rank in fifth round.
To be in safe zone you should try
Hi Aruna,
The qualifying cutoff will be released after JEE mains April result will be declared. For further details please refer the below link.
https://engineering.careers360.com/articles/jee-main-cutoff
NEET and JEE Mains are 2 different exams and you need 2 different approaches altogether for it. You can rub off one's outcome on another preparation. If you are a NEET aspirat, move on from your January session result and focus on NEET preparation. What you cannot afford right now
To be honest, its difficult to predict the actual rank or JEE advanced qualifying marks. Neverthless, you may calculate your expected rank by this formula.A percentile is the no.of Candidates who scored better than you in the exam. Going by that, to calculate your JEE percentille, we should use the
Your rank can be predicted by using the formula, (100-your total percentile)*869010/100. In your case, your approximate rank would be 99327. Let's say the number of candidates for April exam increased to 12,00,000 then your final rank shall be (100 - your total score) X 12,00,000/100. This will be your
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